tính A = \(\sqrt{1+2018^2+\left(\frac{2018}{2019}\right)^2}+\frac{2018}{2019}\)
tính A=\(\sqrt{1+2018^2+\left(\frac{2018}{2019}\right)^2+\frac{2018}{2019}}\)
Tính
\(\left(\frac{19}{2018}-2019\right)\cdot\frac{1}{2019}-\left(\frac{1}{2018}-2019\right)\cdot\frac{19}{2019}\)
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Chúc mày học ngu
\(\left(\frac{19}{2018}-2019\right).\frac{1}{2019}-\left(\frac{1}{2018}-2019\right).\frac{19}{2019}\)
\(=\frac{19}{2018}-2019.\frac{1}{2019}-\frac{-1}{2018}+2019.\frac{19}{2019}\)
\(=\left(\frac{19}{2018}-\frac{-1}{2018}\right)-\left(2019+2019\right).\left(\frac{1}{2019}.\frac{19}{2019}\right)\)
\(=\frac{18}{2018}-2038.\frac{19}{2019}\)
còn đâu tự tính nha
Giải phương trình:\(\frac{\left(2018-x\right)^2+\left(2018-x\right)\left(x-2019\right)+\left(x-2019\right)^2}{\left(2018-x\right)^2-\left(2018-x\right)\left(x-2019\right)+\left(x-2019\right)^2}=\frac{19}{49}\)
Đặt \(\left\{{}\begin{matrix}2018-x=a\\x-2019=b\end{matrix}\right.\) \(\Rightarrow a+b=-1\Rightarrow b=-1-a\)
\(\frac{a^2+ab+b^2}{a^2-ab+b^2}=\frac{19}{49}\Leftrightarrow49\left(a^2+ab+b^2\right)=19\left(a^2-ab+b^2\right)\)
\(\Leftrightarrow15a^2+34ab+15b^2=0\)
\(\Leftrightarrow\left(5a+3b\right)\left(3a+5b\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}5a=-3b\\3a=-5b\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}5a=-3\left(-1-a\right)\\3a=-5\left(-1-a\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2a=3\\2a=-5\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}a=\frac{3}{2}\\a=-\frac{5}{2}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2018-x=\frac{3}{2}\\2018-x=-\frac{5}{2}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=\frac{4033}{2}\\x=\frac{4041}{2}\end{matrix}\right.\)
Tính \(\sqrt{1+2018^2+\frac{2018^2}{2019^2}}+\frac{2018}{2019}\)
tính \(\sqrt{1+2018^2+\frac{2018}{2019}^2}+\frac{2018}{2019}\)
Đặt \(2018=a\)
\(\Rightarrow\sqrt{1+2018^2+\frac{2018^2}{2019^2}}+\frac{2018}{2019}=\sqrt{1+a^2+\frac{a^2}{\left(a+1\right)^2}}+\frac{a}{a+1}\)
\(=\sqrt{\frac{\left(a^2+a+1\right)^2}{\left(a+1\right)^2}}+\frac{a}{a+1}=\frac{a^2+a+1}{a+1}+\frac{a}{a+1}=\frac{\left(a+1\right)^2}{a+1}=a+1=2019\)
Tính:
\(\sqrt{1+2018^2+\frac{2018^2}{2019^2}}+\frac{2018}{2019}\)
Tìm MinS= \(\frac{1}{\left(x-2018\right)^2}+\frac{1}{\left(x-2019\right)^2}+\frac{1}{\left(x-2018\right)\left(x-2019\right)}\)
Thực hiện phép tính
a,\(2018.\left(\frac{1}{2017}-\frac{2019}{1009}\right)-2019.\left(\frac{1}{2017}-2\right)\)
\(2018\cdot\left(\frac{1}{2017}-\frac{2019}{1009}\right)-2019\cdot\left(\frac{1}{2017}-2\right)=\frac{2018}{2017}-4038-\frac{2019}{2017}+4038\)
\(=\frac{2018}{2017}-\frac{2019}{2017}=-\frac{1}{2017}\)
a) Cho các số dương a,b,c,d; c khác d và \(\frac{a}{b}\)=\(\frac{c}{d}\). Chứng minh rằng : \(\frac{\left(a^{2018}+b^{2018}\right)^{2019}}{\left(c^{2018}+d^{2018}\right)^{2019}}\)=\(\frac{\left(a^{2019}-b^{2019}\right)^{2018}}{\left(c^{2019}-d^{2019}\right)^{2018}}\)
b) Cho biết |3x + 2y| + |5z - 7x| + \(\left(xy+yz+xz-500\right)^{2022}\)= 0 . Tính giá trị : \(A=\left(3x-y-z\right)^{2021}\)
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