(X-3/2)^3=1/64
(X+3/2)^2=9/49
(2x-3)^2=36
Những câu hỏi liên quan
tìm x biết
a) ( 3x - 1/5)3= 64/125
b) (2x+ 3/7)2 = 100/49
c) ( x+2/9) 5 = ( x+2/9)3
Tìm x, biết:a) left(5x+1right)^2dfrac{36}{49}b) left[left(-0,5right)^3right]^xdfrac{1}{64}c) 2020^{left(x-2right).left(2x+3right)}1d) left(x+1right)^{x+10}left(x+1right)^{x+4} với xin Ze) dfrac{3}{4}sqrt{x}-dfrac{1}{2}dfrac{1}{3}
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Tìm x, biết:
a) \(\left(5x+1\right)^2=\dfrac{36}{49}\)
b) \(\left[\left(-0,5\right)^3\right]^x=\dfrac{1}{64}\)
c) \(2020^{\left(x-2\right).\left(2x+3\right)}=1\)
d) \(\left(x+1\right)^{x+10}=\left(x+1\right)^{x+4}\) với \(x\in Z\)
e) \(\dfrac{3}{4}\sqrt{x}-\dfrac{1}{2}=\dfrac{1}{3}\)
\(a,\Rightarrow\left[{}\begin{matrix}5x+1=\dfrac{6}{7}\\5x+1=-\dfrac{6}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}5x=\dfrac{1}{7}\\5x=-\dfrac{13}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{35}\\x=-\dfrac{13}{35}\end{matrix}\right.\\ b,\Rightarrow\left(-\dfrac{1}{8}\right)^x=\dfrac{1}{64}=\left(-\dfrac{1}{8}\right)^2\Rightarrow x=2\\ c,\Rightarrow\left(x-2\right)\left(2x+3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=2\\x=-\dfrac{3}{2}\end{matrix}\right.\\ d,\Rightarrow\left(x+1\right)^{x+10}-\left(x+1\right)^{x+4}=0\\ \Rightarrow\left(x+1\right)^{x+4}\left[\left(x+1\right)^6-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}x+1=0\\\left(x+1\right)^6=1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x+1=0\\x+1=1\\x+1=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=0\\x=-2\end{matrix}\right.\\ e,\Rightarrow\dfrac{3}{4}\sqrt{x}=\dfrac{5}{6}\left(x\ge0\right)\\ \Rightarrow\sqrt{x}=\dfrac{10}{9}\Rightarrow x=\dfrac{100}{81}\)
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21 tháng 7 2023 lúc 7:14
bài 1 :tìm x,y biết
a) (5x+1)=\(\dfrac{36}{49}\) b) (x-2/9) = (2/3) c)(8x-1) 2x+1= 5^2 x+1
d) (x-3,5)^x+(y - 1/10)^4=0
`(5x+1)=36/49`
`<=> 5x = 36/49-1`
`<=> 5x = -13/49`.
`<=> x = -13/245.`
Vậy `x = -13/245`.
`b, x-2/9 = 2/3`.
`<=> x = 2/3 + 2/9`
`<=> x = 8/9`.
Vậy `x = 8/9`.
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c: (8x-1)^(2x+1)=5^(2x+1)
=>8x-1=5
=>8x=6
=>x=3/4
d: Sửa đề: (x-3,5)^2+(y-1/10)^4=0
=>x-3,5=0 và y-0,1=0
=>x=3,5 và y=0,1
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Giải PT:a) dfrac{1}{2}sqrt{x-1}-dfrac{3}{2}sqrt{9x-9}+24sqrt{dfrac{x-1}{64}}-17b) sqrt{18x-9}-0,5sqrt{2x-1}+dfrac{1}{2}sqrt{25left(2x-1right)}+sqrt{49left(2x-1right)}24c) sqrt{36x-72}-15sqrt{dfrac{x-2}{25}}4left(5+sqrt{x-2}right)d) sqrt{dfrac{1}{3x+2}}-dfrac{1}{2}sqrt{dfrac{9}{3x+2}}+sqrt{dfrac{16}{3x+2}}-5sqrt{dfrac{1}{12x+8}}1e) dfrac{1}{2}sqrt{dfrac{49x}{x+2}}-3sqrt{dfrac{x}{4x+8}}-sqrt{dfrac{x}{x+2}}-sqrt{5}0
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Giải PT:
a) \(\dfrac{1}{2}\sqrt{x-1}-\dfrac{3}{2}\sqrt{9x-9}+24\sqrt{\dfrac{x-1}{64}}=-17\)
b) \(\sqrt{18x-9}-0,5\sqrt{2x-1}+\dfrac{1}{2}\sqrt{25\left(2x-1\right)}+\sqrt{49\left(2x-1\right)}=24\)
c) \(\sqrt{36x-72}-15\sqrt{\dfrac{x-2}{25}}=4\left(5+\sqrt{x-2}\right)\)
d) \(\sqrt{\dfrac{1}{3x+2}}-\dfrac{1}{2}\sqrt{\dfrac{9}{3x+2}}+\sqrt{\dfrac{16}{3x+2}}-5\sqrt{\dfrac{1}{12x+8}}=1\)
e) \(\dfrac{1}{2}\sqrt{\dfrac{49x}{x+2}}-3\sqrt{\dfrac{x}{4x+8}}-\sqrt{\dfrac{x}{x+2}}-\sqrt{5}=0\)
a. ĐKXĐ: $x\geq 1$
PT $\Leftrightarrow \frac{1}{2}\sqrt{x-1}-\frac{3}{2}.\sqrt{9}.\sqrt{x-1}+24.\sqrt{\frac{1}{64}}.\sqrt{x-1}=-17$
$\Leftrightarrow \frac{1}{2}\sqrt{x-1}-\frac{9}{2}\sqrt{x-1}+3\sqrt{x-1}=-17$
$\Leftrightarrow -\sqrt{x-1}=-17$
$\Leftrightarrow \sqrt{x-1}=17$
$\Leftrightarrow x-1=289$
$\Leftrightarrow x=290$
b. ĐKXĐ: $x\geq \frac{1}{2}$
PT $\Leftrightarrow \sqrt{9}.\sqrt{2x-1}-0,5\sqrt{2x-1}+\frac{1}{2}.\sqrt{25}.\sqrt{2x-1}+\sqrt{49}.\sqrt{2x-1}=24$
$\Leftrightarrow 3\sqrt{2x-1}-0,5\sqrt{2x-1}+2,5\sqrt{2x-1}+7\sqrt{2x-1}=24$
$\Leftrightarrow 12\sqrt{2x-1}=24$
$\Leftrihgtarrow \sqrt{2x-1}=2$
$\Leftrightarrow x=2,5$ (tm)
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c. ĐKXĐ: $x\geq 2$
PT $\Leftrightarrow \sqrt{36}.\sqrt{x-2}-15\sqrt{\frac{1}{25}}\sqrt{x-2}=4(5+\sqrt{x-2})$
$\Leftrightarrow 6\sqrt{x-2}-3\sqrt{x-2}=20+4\sqrt{x-2}$
$\Leftrightarrow \sqrt{x-2}=-20< 0$ (vô lý)
Vậy pt vô nghiệm
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d. ĐKXĐ: $x>\frac{-2}{3}$
PT $\Leftrightarrow \sqrt{\frac{1}{3x+2}}-\frac{1}{2}\sqrt{9}.\sqrt{\frac{1}{3x+2}}+\sqrt{16}.\sqrt{\frac{1}{3x+2}}-5\sqrt{\frac{1}{4}}\sqrt{\frac{1}{3x+2}}=1$
$\Leftrightarrow \sqrt{\frac{1}{3x+2}}-\frac{3}{2}\sqrt{\frac{1}{3x+2}}+4\sqrt{\frac{1}{3x+2}}-\frac{5}{2}\sqrt{\frac{1}{3x+2}}=1$
$\Leftrightarrow \sqrt{\frac{1}{3x+2}}=1$
$\Leftrightarrow \frac{1}{3x+2}=1$
$\Leftrightarrow 3x+2=1$
$\Leftrightarrow x=-\frac{1}{3}$
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(Bài 14; Tìm x biết
1) x ^ 2 - 9 = 0
4) 4x ^ 2 - 4 = 0
7) (3x + I) ^ 2 - 16 = 0
10) (x + 3) ^ 2 - x ^ 2 = 45
2) 25 - x ^ 2 = 0
5) 4x ^ 2 - 36 = 0
8) (2x - 3) ^ 2 - 49 = 0
11) (5x - 4) ^ 2 - 49x ^ 2 = 0
3) - x ^ 2 + 36 = 0
6) 4x ^ 2 - 36 = 0
9) (2x - 5) ^ 2 - x ^ 2 = 0
12) 16 * (x - 1) ^ 2 - 25 = 0
1, \(x^2\) - 9 = 0
(\(x\) - 3)(\(x\) + 3) = 0
\(\left[{}\begin{matrix}x-3=0\\x+3=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
vậy \(x\) \(\in\) {-3; 3}
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7, (3\(x\) + 1)2 - 16 = 0
(3\(x\) + 1 - 4)(3\(x\) + 1 + 4) = 0
(3\(x\) - 3).(3\(x\) + 5) = 0
\(\left[{}\begin{matrix}3x-3=0\\3x+5=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}3x=3\\3x=-5\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=1\\x=\dfrac{-5}{3}\end{matrix}\right.\)
Vậy \(x\) \(\in\) {1; - \(\dfrac{5}{3}\)}
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10, (\(x\) + 3)2 - \(x^2\) = 45
[(\(x\) + 3) - \(x\)].[(\(x\) + 3) + \(x\)] = 45
3.(2\(x\) + 3) = 45
2\(x\) + 3 = 15
2\(x\) = 12
\(x\) = 6
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In the figure below, x Câu 2 Find the measure of angle J if widehat{K}29^o K 29 o and angle J and K are supplementary. Answer: widehat{J} J ^o o . Câu 3 In the figure below, x Câu 4 In the figure below, x Câu 5 Solve: |2x-3|-43∣2x−3∣−43, where xx is a negative number. Answer: xx Câu 6 Calculate: 9+|-6|:1^2 9+∣−6∣:1 2 Câu 7 Compare: dfrac{36}{27} 27 36 dfrac{4}{3} 3 4 Câu 8 Find the negative number yy such that |y+dfrac{7}{2}|-dfrac{1}{2}4∣y+ 2 7 ∣− 2 1 4. Answer: yy Câu 9 Find xx su...
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In the figure below, x = Câu 2 Find the measure of angle J if \widehat{K}=29^o K =29 o and angle J and K are supplementary. Answer: \widehat{J}= J = ^o o . Câu 3 In the figure below, x = Câu 4 In the figure below, x = Câu 5 Solve: |2x-3|-4=3∣2x−3∣−4=3, where xx is a negative number. Answer: x=x= Câu 6 Calculate: 9+|-6|:1^2 =9+∣−6∣:1 2 = Câu 7 Compare: \dfrac{36}{27} 27 36 \dfrac{4}{3} 3 4 Câu 8 Find the negative number yy such that |y+\dfrac{7}{2}|-\dfrac{1}{2}=4∣y+ 2 7 ∣− 2 1 =4. Answer: y=y= Câu 9 Find xx such that \dfrac{32}{2^x}=2 2 x 32 =2. Answer: x=x= Câu 10 Find nn such that \dfrac{(-4)^n}{64}=-16 64 (−4) n =−16. Answer: n=n= Cần gấp nhé
Hinh câu 1
(2x +3).(1/2.x - 3/2) = 0
(1/2 - x)2= 64/49
1/2.(x- 4/5 )=3/4.x = 5/12
ai nhanh mik tik cho
help me..........
a) \(\left(2x+3\right).\left(\frac{1}{2}.x-\frac{3}{2}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x+3=0\\\frac{1}{2}.x-\frac{3}{2}=0\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}2x=-3\\\frac{1}{2}.x=\frac{3}{2}\end{cases}}\Rightarrow\orbr{\begin{cases}x=-\frac{3}{2}\\x=\frac{3}{2}:\frac{1}{2}\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=-\frac{3}{2}\\x=3\end{cases}}\)
Vậy x = \(-\frac{3}{2}\) hoặc x = 3
b)\(\left(\frac{1}{2}-x\right)^2=\frac{64}{49}\)
\(\Rightarrow\left(\frac{1}{2}-x\right)^2=\left(\frac{8}{7}\right)^2\) hoặc \(\left(\frac{1}{2}-x\right)^2=\left(-\frac{8}{7}\right)^2\)
\(\Rightarrow\orbr{\begin{cases}\frac{1}{2}-x=\frac{8}{7}\\\frac{1}{2}-x=-\frac{8}{7}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}-\frac{8}{7}\\x=\frac{1}{2}+\frac{8}{7}\end{cases}}\Rightarrow\orbr{\begin{cases}x=-\frac{9}{14}\\x=\frac{23}{14}\end{cases}}\)
Vậy x = \(-\frac{9}{14}\) hoặc x = \(\frac{23}{14}\)
c) \(\frac{1}{2}.\left(x-4,5\right)=\frac{3}{4}.x=\frac{5}{12}\) ( câu này mik ko hiểu cho lắm)
k mik nha mn!
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1) Tìm x
a) (1/4 x X - 1/8) x 3/4 = 1/4
b) 12/5 : X = 14/3 x 4/7
c) x + 2/3 = 8 : 4 - 1
2) Thực hiện phép tính:
a) (1/5 + 3/4) x 1/2
b) 13/20 - (1/4 - 5/20)
c) 1/10 + 4/20 + 9/30 + 25/50 + 36/60 + 49/70 + 64/80 + 81/90
d) 2/3.5 + 2/5.7 + 2/7.9 + ... + 2/41.43
Bài 1:
a; (\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\)) x \(\dfrac{3}{4}\) = \(\dfrac{1}{4}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) : \(\dfrac{3}{4}\)
\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) x \(\dfrac{4}{3}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{3}\)
\(\dfrac{1}{4}x\) = \(\dfrac{1}{3}\) + \(\dfrac{1}{8}\)
\(\dfrac{1}{4}\) \(x\)= \(\dfrac{8}{24}\) + \(\dfrac{11}{24}\)
\(\dfrac{1}{4}x=\dfrac{11}{24}\)
\(x=\dfrac{11}{24}:\dfrac{1}{4}\)
\(x=\dfrac{11}{24}\times4\)
\(x=\dfrac{11}{6}\)
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b; \(\dfrac{12}{5}:x\) = \(\dfrac{14}{3}\) x \(\dfrac{4}{7}\)
\(\dfrac{12}{5}\) : \(x\) = \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) : \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) x \(\dfrac{3}{8}\)
\(x\) = \(\dfrac{9}{10}\)
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c; \(x+\dfrac{2}{3}\) = 8:4 - 1
\(x+\dfrac{2}{3}\) = 2 - 1
\(x+\dfrac{2}{3}\) = 1
\(x=1-\dfrac{2}{3}\)
\(x\) = \(\dfrac{1}{3}\)
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(2x-3)3 = -64
(2x-3)2 =25
(3x-4)2 =36
2x+1 = 64
a, (2x-3)3 = -64
=> (2x-3)3 = -43
=> 2x-3=-4
=> 2x = -1
=> x = -1 : 2
=> x = -1/2
b, (2x-3)2 =25
=> (2x-3)2 =5^2
=> 2x-3 = 5
=> 2x = 8
=> x = 4
c, (3x-4)2 =36
=> (3x-4)2 =62
=> 3x-4 = 6
=> 3x = 10
=> x = 3.(3)
d, 2x+1 = 64
=> 2x+1 = 26
=> x+1 = 6
=> x = 5
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a/ (2x - 3)3 = -64 => (2x - 3)3 = (-4)3 => 2x - 3 = -4 => 2x = -1 => x = -1/2
b/ (2x - 3)2 = 25 => (2x - 3)2 = 52 => 2x - 3 = 5 => 2x = 8 => x = 4
c/ (3x - 4)2 = 36 => (3x - 4)2 = 62 => 3x - 4 = 6 => 3x = 10 => x = 10/3
d/ 2x+1 = 64 => 2x+1 = 26 => x + 1 = 6 => x = 5
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