\(\left(\frac{9}{15}-2,18\right):\left(3\frac{4}{5}+0,2\right)=\left(0,6-2,18\right):\left(3,8+0,2\right)=-1,58:4=-0,395\)

= -8,91             

a) \(=-\frac{91}{50}:4\)

   \(=-\frac{91}{200}\)

b) \(=\frac{5}{18}-\frac{26}{5}+\frac{18}{5}\)

   \(=-\frac{119}{90}\)

\(\left(\frac{9}{25}-2,18\right):\left(3\frac{4}{5}+0,2\right)\)

\(=\left(-1,82\right):4\)

\(=-0,455\)

tự tính đc mà (╬▔皿▔)╯

\(\left(\frac{9}{25}-2.18\right):\left(3\frac{4}{5}+0,2\right)\)

\(=\left(\frac{9}{25}-36\right):\left(\frac{19}{5}+0,2\right)\)

\(=\left(-\frac{891}{25}\right):4\)

\(=-\frac{891}{100}.\)

Chúc bạn học tốt!

a, (\(\frac{9}{25}\) - 2.18) : (\(3\frac{4}{5}\) + 0,2)

 = (\(\frac{9}{25}\) - 36) : 4

 = \(\frac{-891}{25}\) :4

 = -8,91

                                        tạm thời làm tới đây

                                           Chúc bạn học tốt 

a) (925−2.18):(345+0,2)

 = (\(\frac{9}{25}\) - 36) : (\(\frac{19}{5}\) + 0,2)

= \(\frac{-891}{25}\) : 4

= \(\frac{-891}{100}\)

b) 518−1,456:725+4,5.45

 = \(\frac{5}{18}\) - (1,456 : \(\frac{7}{25}\)) + (4,5 . \(\frac{4}{5}\))

= \(\frac{5}{18}\) - \(\frac{26}{5}\) + \(\frac{18}{5}\)

= \(\frac{-443}{90}\) + \(\frac{18}{5}\)

= \(\frac{-119}{90}\).

a) \(\left(\frac{9}{25}-2.18\right):\left(3\frac{4}{5}+0,2\right)\)

\(=\left(\frac{9}{25}-36\right):\left(\frac{19}{5}+0,2\right)\)

\(=\left(-\frac{891}{25}\right):4\)

\(=-\frac{891}{100}\)

b)\(\frac{5}{18}-1,456:\frac{7}{25}+4,5.\frac{4}{5}\)

\(=\frac{5}{18}-\frac{26}{5}+\frac{18}{5}\)

\(=-\frac{119}{90}\)

^...^  ^_^

a) Ta có: \(\left(\dfrac{9}{25}-2\cdot18\right):\left(3\dfrac{4}{5}+0.2\right)\)

\(=\left(\dfrac{9}{25}-36\right):\left(\dfrac{19}{5}+\dfrac{1}{5}\right)\)

\(=\left(\dfrac{9}{25}-\dfrac{900}{25}\right):\dfrac{20}{5}\)

\(=\dfrac{-891}{25}\cdot\dfrac{1}{4}\)

\(=-\dfrac{891}{100}\)

b) Ta có: \(\dfrac{3}{8}\cdot19\dfrac{1}{3}+\dfrac{3}{8}\cdot33\dfrac{1}{3}\)

\(=\dfrac{3}{8}\cdot\dfrac{58}{3}+\dfrac{3}{8}\cdot\dfrac{100}{3}\)

\(=\dfrac{58}{8}+\dfrac{100}{8}\)

\(=\dfrac{158}{8}=\dfrac{79}{4}\)

c) Ta có: \(15\cdot\left(-\dfrac{2}{3}\right)^2-\dfrac{7}{3}\)

\(=15\cdot\dfrac{4}{9}-\dfrac{7}{3}\)

\(=\dfrac{20}{3}-\dfrac{7}{3}\)

\(=\dfrac{13}{3}\)

d) Ta có: \(\dfrac{1}{2}\sqrt{64}-\sqrt{\dfrac{4}{25}}+\left(-1\right)^{2007}\)

\(=\dfrac{1}{2}\cdot8-\dfrac{2}{5}-1\)

\(=4-1-\dfrac{2}{5}\)

\(=3-\dfrac{2}{5}\)

\(=\dfrac{15}{5}-\dfrac{2}{5}=\dfrac{13}{5}\)

e) Ta có: \(\left(-\dfrac{5}{2}\right)^2:\left(-15\right)-\left(0.45+\dfrac{3}{4}\right)\cdot\left(-1\dfrac{5}{9}\right)\)

\(=\dfrac{25}{4}\cdot\dfrac{-1}{15}-\left(\dfrac{9}{20}+\dfrac{15}{20}\right)\cdot\dfrac{-14}{9}\)

\(=\dfrac{-25}{60}-\dfrac{24}{20}\cdot\dfrac{-14}{9}\)

\(=\dfrac{-25}{60}+\dfrac{28}{15}\)

\(=\dfrac{-25}{60}+\dfrac{112}{60}\)

\(=\dfrac{87}{60}=\dfrac{29}{20}\)

f) Ta có: \(\left(-\dfrac{1}{3}\right)-\left(-\dfrac{3}{5}\right)^0+\left(1-\dfrac{1}{2}\right)^2:2\)

\(=-\dfrac{1}{3}-1+\left(\dfrac{1}{2}\right)^2\cdot\dfrac{1}{2}\)

\(=\dfrac{-4}{3}+\dfrac{1}{4}\cdot\dfrac{1}{2}\)

\(=\dfrac{-4}{3}+\dfrac{1}{8}\)

\(=\dfrac{-32}{24}+\dfrac{3}{24}=\dfrac{-29}{24}\)

g) Ta có: \(\left(\dfrac{1}{2}\right)^{15}\cdot\left(\dfrac{1}{4}\right)^{20}\)

\(=\left(\dfrac{1}{2}\right)^{15}\cdot\left(\dfrac{1}{2}\right)^{40}\)

\(=\left(\dfrac{1}{2}\right)^{55}\)

\(=\dfrac{1}{2^{55}}\)

h) Ta có: \(\dfrac{5^4\cdot20}{25^5\cdot4^5}\)

\(=\dfrac{5^4\cdot5\cdot2^2}{5^{10}\cdot2^{10}}\)

\(=\dfrac{5^5}{5^{10}}\cdot\dfrac{2^2}{2^{10}}\)

\(=\dfrac{1}{5^5}\cdot\dfrac{1}{2^8}\)

\(=\dfrac{1}{800000}\)

90. a) \(-\frac{91}{200}\)

b) \(-\frac{119}{90}\)

118. a) >

b) >

c) >

d) =

Bài 90:

Bài 118 SBT:

Chúc bạn học tốt!

a) (925−2.18):(345+0,2)(925−2.18):(345+0,2)

=(925−36):(195+15)=(925−36):(195+15)

=(925−90025):205=(925−90025):205

=−89125:4=−89125:4

=−891100=−8,91