Bài 7. (2.5 điểm) Cho tam giác ABC cân tại A, có I là trung điểm của cạnh BC. Vẽ ID vuông góc với AB tại D, vẽ IE vuông góc với AC tại E. a Chứng minh :ADBI= AECI b/ Chứng minh : AIDE là tam giác cân. c/ Chứng minh :AB+AC> 2 BI
a: Xét ΔDIB vuông tại D và ΔEIC vuông tại E có
IB=IC
góc B=góc C
=>ΔDIB=ΔEIC
b: Xét ΔIDE có ID=IE
nên ΔIDE cân tại I
c: AB+AC>BC=2BI
cho tam giác ABC cân tại A gọi M là trung điểm của BC;
a)c/m:tam giác ABM=tam giác ACM và AM vuông góc với BC
b)kẻ ME vuông góc với AB tại E,ME vuông góc AC tại F.c/m tam giác EMF cân tại M
c)c/m EF song song BC
c)
Cho tam giác ABC cân tại A có góc BAC nhọn . Gọi M là trung điểm của cạnh BC , Vẽ ME Vuông góc với AB tại E; MF vuông góc với AC tại F . Tia FM cắt tia AB tại I , tia Em cắt tia AC tại K và N là trung điểm của IK
a) C/M tam giác AEM= tam giác AFM
b) C/m AM vuông góc với EF
c) C/M Tam giác MIK cân
d) C/M BM+CM< AB+AC
Cho tam giác ABC cân tai A. Gọi Ià trung điểm cạnh BC kẻ ID vuông góc AB tại D kẻ IE vuông góc AC tai E
A Chứng minh Tam giác ABI = Tam giác ACI
B Chứng minh Tam giác IDE cân
C Chứng minh DE song song với BC
giúp em với ạ mọi người thank moi người nhiều nha
a) Xét tam giác ABI và ACI ta có :
\(AB=AC\)
\(AI:chung\)
\(BI=CI\)
\(\Rightarrow\Delta ABI=\Delta ACI\)
b) + c) bị che
a. xét tam giác ABI và tam giác ACI có:
AB = AC ( ABC cân )
góc B = góc C ( ABC cân )
AI: cạnh chung
Vậy......
b. xét tam giác vuông BID và tam giác vuông CIE có:
góc B = góc C ( ABC cân )
IB = IC ( gt)
Vậy....
=>ID = IE ( 2 góc tương ứng )
=> tam giác IDE cân tại I
=> BD = CE
c. gọi N là giao điểm của DE và AI
ta có: AD=AE ( ABC cân, BD = CE )
=> ADE cân tại A
ta lại có AI là đường trung tuyến cũng là phân giác góc A
=> A cũng là phân giác trong tam giac ADE
mà trong tam giác cân ADE đường phân giác cũng là đường cao (1)
trong tam giác cân ABC đường trung tuyến cũng là đường cao ( 2 )
từ (1) và ( 2 ) => DE // BC ( 2 góc cùng vuông với 1 đường thẳng )
Bài 1:
Cho tam giác ABC cân có AB=AC=5cm, BC= 8cm.Kẻ AH vuông góc với BC ( H thuộc BC).
a, Chứng minh HB=HC
b, Tính độ dài AH.
c, Kẻ HD vuông góc với AB(D thuộc AB), kẻ HE vuông góc với AC ( E thuộc AC).Chứng minh tam giác HDE cân.
d, So sánh HD và HC.
Bài 2:
Cho tam giác ABC cân tại A có đường cao AH.
a, Chứng minh tam giác ABH = tam giác ACH và AH là tia phân giác của góc BAC.
b, Cho BH= 8cm, AB= 10cm.Tính AH.
c,, Gọi E là trung điểm của AC và G là giao điểm của BE và AH.Tính HG.
d, Vẽ Hx song song với AC, Hx cắt AB tại F. Chứng minh C, G, F thẳng hàng.
Bài 3
Cho tam giác ABC có CA= CB= 10cm, AB= 12cm.kẻ CI vuông góc với AB.Kẻ IH vuông góc với AC, IK vuông góc với BC.
a, Chứng minh IB= IC và tính độ dài CI
b, Chứng minh IH= IK.
c, HK// AC.
Bài 4:
Cho tam giác ABC cân tại A, vẽ AH vuông góc với BC tại H.Biết AB= 10cm, BH= 6cm.
a, Tính AH
b, tam giác ABH= tam giác ACH.
c, trên BA lấy D, CA lấy E sao cho BD= CE.Chứng minh tam giác HDE cân.
d, AH là trung trực của DE.
Bài 5:
Cho tam giác ABC cân tại AGọi D là trung điểm của BC.Từ D kẻ DE vuông góc với AB, DF vuông góc với AC. Chứng minh rằng:
a, tam giác ABD= tam giác ACD.
b, AD vuông góc với BC.
c, Cho AC= 10cm, BC= 12cm.Tính AD.
d, tam giác DEF cân.
Bài 6:
Cho tam giác ABC cân tại A có góc A < 900. kẻ BH vuông góc với AC ,CK vuông góc với AC.Gọi O là giao điểm của BH và CK.
a, Chứng minh tam giác ABH=Tam giác ACH.
b, Tam giác OBC cân.
c, Tam giác OBK = tam giác OCK.
d, trên nửa mặt phẳng bờ BC không chứa điểm A lấy I sao cho IB=IC.Chứng minh 3 điểm A, O, I thẳng hàng.
Bài 7
Cho tam giác ABC cân tại A. Kẻ BD vuông góc với AC, CE vuông góc với AB. BD và CE cắt nhau tại H.
a, Tam giác ABD=tam giác ACE.
b, Tam giác BHC cân.
c, ED//BC
d, AH cắt BC tại K, trên HK lấy M sao cho K là trung điểm của HM.Chứng minh tam giác ACM vuông.
Bài 8
Cho tam giác ABC cân tại A. Kẻ BD vuông góc với AC, CE vuông góc với AB. BD và CE cắt nhau tại H.
a, BD= CE.
b, Tam giác BHC cân.
c, AH là trung trực của BC
d, Trên tia BD lấy K sao cho D là trung điểm của BK.So sánh góc ECB và góc DKC.
Bài9
Cho tam giác ABC cân tại A.vẽ trung tuyến AM .từ M kẻ ME vuông góc với AB tại E.kẻ MF vuông góc với AC tại F.
a, chứng minh tam giác BEM= tam giác CFM.
b, AM là trung trực vủa EF.
c, từ B kẻ đường thẳng vuông góc với AB tại B, từ C kẻ đường thẳng vuông góc với AC tại C, hai đường này cắt nhau tại D.Chứng minh A,M,D thẳng hàng.
Bài 10
Cho tam giác ABC cân tại AGọi M là trung điểm của AC.Trên tia đối MB lấy D sao cho DM= BM.
a, Chứng minh Tam giác BMC= tam giác DMA.Suy ra AD//BC.
b, tam giác ACD cân.
c. trên tia đối CA lấy E sao cho CA= CE.Chuwngsminh DC đi qua trung điểm I của BE.
Bài 11: Cho tam giác ABC cân tại A (AB = AC ), M là trung điểm của BC. Gọi D là điểm là điểm nằm giữa A và M. Chứng minh rằng:
a) AM là tia phân giác của góc A?
b) (ABD = (ACD.
c) (BCD là tam giác cân ?
Bài 12: Cho tam giác ABC vuông tại A , đường phân giác BD. Kẻ DE vuông góc với BC (E BC). Gọi F là giao điểm của BA và ED.
Giúp mk với các bạn đẹp trai xinh gái ai làm đúng mk tik cho
Sắp hết Tết rùi giúp mk vs
ủa r viết ngần đó thì mất bn tg thek
Má ơi sao nó dài
Bài 1. Cho tam giác ABC cân tại A có Â = 80o
a) Tính số đo các góc B, C của tam giác ABC
b) Tia phân giác của góc B cắt AC tại D. Tính số đo góc ADB.
Bài 2. Cho tam giác ABC cân tại A. Kẻ BD vuông góc với AC (D ∈ AC), CE vuông góc với AB (E ∈ AB),
BD và CE cắt nhau tại I. M là trung điểm BC. Chứng minh:
a) ∆BDC = CEB.
b) Tam giác IBC là tam giác cân.
c) IE = ID.
d) Ba điểm A, I, M thẳng hàng.
Cho tam giác ABC cân tại A. Gọi I là trung điểm cạnh BC, kẻ ID vuông góc với AB tại D, kẻ IE vuông góc với AC tại E.
a) CM: tam giác ABI = tam giác ACI.
b) CM: tam giác BDI = tam giac CEI
c) CM: DE song song với BC
d) CM: AB^2 = AD^2 + BD^2 + 2DI^2
Mình làm phần d) thôi nhé!
Theo phần a) ta có được: \(\widehat{AIB}=\widehat{AIC}\)(2 góc tương ứng:
Tam giác ABI = Tam giác ACI)
mà \(\widehat{AIB}+\widehat{AIC}=180\)(2 góc kề bù)
=>\(\widehat{AIB}=\widehat{AIC}=90\)
Xét tam giác ABI vuông tại I, áp dụng định lí py-ta-go ta có:
\(AB^2=AI^2+BI^2\)(1)
Xét tam giác ADI vuông tại D, áp dụng định lí py-ta-go ta có:
\(AI^2=AD^2+DI^2\)(2)
Xét tam giác BDI vuông tại D, áp dụng định lí py-ta-go ta có:
\(BI^2=DI^2+BD^2\)(3)
Thay (2),(3) vào (1) ta có được:
\(AB^2=AD^2+DI^2+DI^2+BD^2\)
(hay) \(AB^2=AD^2+BD^2+2DI^2\)(ĐPCM)
1. Cho tam giác ABC vuông ở A có AB<AC. AH vuông góc với BC tại H, D là điểm trên cạnh BC sao cho AD=AB. Vẽ DE vuông góc với BC tại E. Chứng mih rằng AH=HE.
2. Cho tam giác ABC vuông cân tại A.. Qua A vẽ đường thẳng d ở ngoài tam giác ABC . Vẽ BD vuông góc với d taị D. CE vuông góc với d tại E. M là trung điểm CB. Chứng minh rằng:
a) BD + CE = DE
b) Tam giác MDE là tam giác vuông cân
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A I E B D C F K cho tam giác ABC cân tại A.vẽ đường cao AD của tam giác ABC .
a)chứng minh tam giác ABD = tam giác ACD và D là trung điểm BC
b)vẽ DE vuông góc với AB tại E,vẽ DF vuông góc với AC tại F.Chứng minh tam giác AEF cân
c) gọi I là trung điểm của AB, CI cắt AD tại K. Chứng minh CI + 2AD lớn hơn 3AI.
a: Xét ΔABD vuông tại D và ΔACD vuông tại D có
AB=AC
AD chung
=>ΔABD=ΔACD
=>BD=CD
=>D là trung điểm của BC
b: Xét ΔAED vuông tại E và ΔAFD vuông tại F có
AD chung
góc EAD=góc FAD
=>ΔAED=ΔAFD
=>AE=AF
=>ΔAEF cân tại A
c: CI+2AD
=3IK+2*3/2*AK
=3*(IK+AK)>3AI
