2.3^x+2+4.3^x+1=10.3⁶

=>2.3.3^x+1+4.3^x+1=10.3⁶

=>(6+4).3^x+1=10.3⁶

=>10.3^x+1=10.3⁶

=>3^x+1=3⁶

=>x+1=6

=>x=5

A) \(2.3^{x+2}+4.3^{x+1}=10.3^6\)

=> \(2.3.3^{x+1}+4.3^{x+1}=10.3^6\)

=> \(6.3^{x+1}+4.3^{x+1}=10.3^6\)

=> \(\left(6+4\right).3^{x+1}=10.3^6\)

=> \(10.3^{x+1}=10.3^6\)

=> \(3^{x+1}=3^6\)

=> \(x+1=6\)

=> \(x=6-1\)

=> \(x=5\)

Vậy \(x=5.\)

B) \(6.8^{x-1}+8^{x+1}=6.8^{19}+8^{21}\)

=> \(6.8^{x-1}+8^{x-1}.8^2=6.8^{19}+8^{19}.8^2\)

=> \(8^{x-1}.\left(6+8^2\right)=8^{19}.\left(6+8^2\right)\)

=> \(8^{x-1}=8^{19}\)

=> \(x-1=19\)

=> \(x=19+1\)

=> \(x=20\)

Vậy \(x=20.\)

Còn câu c) thì mình đang nghĩ nhé.

Chúc bạn học tốt!

\(2.3^{x+2}+4.3^{x+1}=10.3\)

\(\Leftrightarrow2.3^{x+1}\left(3+2\right)=10.3\)

\(\Leftrightarrow3^{x+1}=3\)

\(\Leftrightarrow x+1=1\)

\(\Leftrightarrow x=0\)

   2.3^x+2+4.3^x+1=10.3⁶

2.3.3^x+1+4.3^x+1=10.3⁶

   6.3^x+1+4.3^x+1=10.3⁶

            10.3^x+1=10.3⁶

=>3^x+1=3⁶

=>x+1=6 =>x=5

Ai thấy đúng cho mình nha!

\(2.3^{x+2}+4.3^{x+1}=10.3^6\)

\(2.3^{x+2}+2^2.3^{x+1}=2.5.3^6\)

\(2.3^{x+1}\left(3+2\right)=2.5.3^6\)

\(2.3^{x+1}.5=2.5.3^6\)

\(\Rightarrow x+1=6\Rightarrow x=5\)

Cho mình hỏi bạn Sahra Elizabel, tại sao lại là 3+2 ạ?

1;Ta có\(5.3^x=5.3^4\)

\(\Rightarrow3^x=3^4\)

\(\Rightarrow x=4\)

2.Ta có \(9.5^x=6.5^6+3.5^6\)

\(\Rightarrow9.5^x=5^6.\left(6+3\right)\)

\(\Rightarrow9.5^x=9.5^6\)

\(\Rightarrow5^x=5^6\)\

\(\Rightarrow x=6\)

3, Ta có \(2.3^{x+2}+4.3^{x+1}=10.3^6\)

\(\Rightarrow3^{x+1}.\left(2.3+4\right)=10.3^6\)

\(\Rightarrow3^{x+1}.10=10.3^6\)

\(\Rightarrow3^{x+1}=3^6\)

\(\Rightarrow x+1=6\)

\(\Rightarrow x=5\)

a) 5.3^x = 5.3⁴

=> 3^x=3⁴

=> x=4

b) 9.5^x=6.5⁶+3.5⁶

=> 9.5^x = (6+3)5⁶

=> 9.5^x=9.5⁶

=> 5^x=5⁶

=> x=6

c) 2.3^x+2 + 4.3^x+1 = 10.3⁶

=> 2.3^x+1.3 + 4.3^x+1 = 10.3⁶ 

=> 6.3^x+1+4.3^x+1=10.3⁶

=> (6+4).3^x+1=10.3⁶

=> 10.3^x+1=10.3⁶

=> 3^x+1=3⁶

=> x+1=6

=> x=5

a) \(2^{2x}.2^4=1024\)

\(2^{2x}=1024:2^4\)

\(2^{2x}=1024:16\)

\(2^{2x}=64\)

\(2^{2x}=2^6\)

\(\Rightarrow2x=6\)

\(\Rightarrow x=3\)

vay \(x=3\)

b) \(2.3^x=10.3^{12}+8.27^4\)

\(2.3^x=2.5.3^{12}+2^3.\left(3^3\right)^4\)

\(2.3^x=2.5.3^{12}+2^3.3^{12}\)

\(2.3^x=2.3^{12}.\left(5+2^2\right)\)

\(2.3^x=2.3^{12}.9\)

\(2.3^x=2.3^{12}.3^2\)

\(2.3^x=2.3^{14}\)

\(\Rightarrow x=14\)

vay \(x=14\)

c) \(5^8.25^x+1=5^{17}\)

\(5^8.\left(5^2\right)^x+1=5^{17}\)

\(5^8.5^{2x}+1=5^{17}\)

\(5^{8+2x}=5^{17}-1\)

e) \(\left(2x-4\right)^5=\left(2x-4\right)^3\)

\(\left(2x-4\right)^5-\left(2x-4\right)^3=0\)

\(\left(2x-4\right)\left[\left(2x-4\right)^2-1\right]=0\)

\(\left(2x-4\right)\left(2x-4-1\right)\left(2x-4+1\right)=0\)

\(\left(2x-4\right)\left(2x-5\right)\left(2x-3\right)=0\)

\(\Rightarrow2x-4=0\)hoac  \(\orbr{\begin{cases}2x-5=0\\2x-3=0\end{cases}}\)

\(\Rightarrow2x=4\)hoac \(\orbr{\begin{cases}2x=5\\2x=3\end{cases}}\)

 \(\Rightarrow x=2\)hoac \(\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)

              vay \(x=2\)hoac \(\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)

2\(^x\)- 15 = 17

\(\Rightarrow\)2\(^x\) =  32

\(\Rightarrow\)x  = 5

2^x-15=17

=>2^x=17+15

=2^x=32

=>2^x=2^5

=>x=5

1:

\(\Leftrightarrow4\cdot3^x\cdot\dfrac{1}{9}+2\cdot3^x\cdot3=4\cdot3^4+2\cdot3^7\)

\(\Leftrightarrow3^x\cdot\left(\dfrac{4}{9}+6\right)=3^4\cdot\left(4+2\cdot3^3\right)\)

\(\Leftrightarrow3^x=729\)

hay x=6

2: \(\Leftrightarrow3^x\cdot4\cdot\dfrac{1}{3}+3^x\cdot2\cdot9=4\cdot3^6+2\cdot3^9\)

\(\Leftrightarrow3^x\cdot\dfrac{58}{3}=42282\)

=>3^x=2187

hay x=7