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chanjipark
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trần công phúc
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Nguyễn Linh
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(.I_CAN_FLY.)
14 tháng 12 2022 lúc 22:38

1B

2C

3A

4D

5C

6A

violet
14 tháng 12 2022 lúc 22:51

Chào em, em tham khảo nhé:

1. B

2. C

3. A

4. D

5. C

6. A

Chúc em học tốt.

hoài tạ
20 tháng 3 2023 lúc 19:36

1B

2C

3A

4D

5C

6A

Bùi Thị Kim Ngân
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giao nè
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Gia Linh
1 tháng 8 2023 lúc 17:54

1. shouldn't

2. should

3. should

4. should

5. should

6. Should

7. should

8. shouldn't

9. should

10. should

11. shouldn't

12. Should

13. should

14. shouldn't

15. shouldn't

-----------

II

1. was -> were

2. Was -> Were

3. was -> did

4. went -> go

5. weren't -> didn't

6. have -> had

7. broke -> break

8. go -> went

9. am -> was

10. turn -> turned

--------------

III

1. taught/ to ride/ was

2. does your father go/ drives

3. are going

4. used/ lived 

5. spent/ repairing 

-------------

IV

1. Lang Lieu couldn't buy any special food because he was very pool

2. During Tet, Vietnamese people buy all kinds of sweets, so they make Chung cakes as well

3. The Hung King Temple Festival was a local festival. However, it has become a public holiday in Viet Nam

4. At the Mid-Autumn festival, kids can sing, dance and enjoy moon cakes; therefore, every child like it very much.

5. Because the water is highly polluted, we can't swim in this part of the river

6. Mr. Minh is admired since he dedicates all his life to protecting the environment

-------------

V

1. A

2. B

3. A

4. D

5. C 

Quỳnh Thư
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Quỳnh Thư
18 tháng 4 2020 lúc 23:18
https://i.imgur.com/ygdl9jF.jpg
Quỳnh Thư
18 tháng 4 2020 lúc 23:18

Pleaseeeeeee!

Tasia
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Smile
22 tháng 6 2021 lúc 19:39

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Bài 1:

a) \(\dfrac{4}{5}-\dfrac{7}{6}+\dfrac{-6}{15}=\dfrac{24}{30}-\dfrac{35}{30}+\dfrac{-12}{30}=\dfrac{24-35+-12}{30}=\dfrac{-23}{30}\) 

b) \(\dfrac{-5}{9}.\dfrac{7}{13}+\dfrac{6}{13}.\dfrac{-5}{9}+3\dfrac{7}{9}\) 

\(=\dfrac{-5}{9}.\left(\dfrac{7}{13}+\dfrac{6}{13}\right)+\dfrac{34}{9}\) 

\(=\dfrac{-5}{9}.1+\dfrac{34}{9}\) 

\(=\dfrac{-5}{9}+\dfrac{34}{9}\) 

\(=\dfrac{29}{9}\) 

c) \(6\dfrac{3}{8}-\left(4\dfrac{3}{8}-\dfrac{1}{2}\right)=\dfrac{51}{8}-\dfrac{35}{8}+\dfrac{1}{2}=\left(\dfrac{51}{8}-\dfrac{35}{8}\right)+\dfrac{1}{2}=2+\dfrac{1}{2}=\dfrac{5}{2}\) 

d) \(2\dfrac{1}{3}.1,5-\left(\dfrac{11}{10}+50\%\right):\dfrac{4}{15}\) 

\(=\dfrac{7}{3}.1,5-\dfrac{8}{5}:\dfrac{4}{15}\) 

\(=\dfrac{7}{2}-6\) 

\(=\dfrac{-5}{2}=-2,5\) 

Bài 2:

a) \(\dfrac{3}{2}+x=\dfrac{-5}{3}\) 

           \(x=\dfrac{-5}{3}-\dfrac{3}{2}\) 

           \(x=\dfrac{-19}{6}\) 

b) \(5\dfrac{2}{3}-\left(\dfrac{3}{2}+x\right)=4\dfrac{1}{3}\) 

                   \(\dfrac{3}{2}+x=\dfrac{17}{3}-\dfrac{13}{3}\) 

                   \(\dfrac{3}{2}+x=\dfrac{4}{3}\) 

                          \(x=\dfrac{4}{3}-\dfrac{3}{2}\) 

                          \(x=\dfrac{-1}{6}\) 

b) \(\left|x-\dfrac{1}{2}\right|+75\%=\dfrac{9}{10}\) 

               \(\left|x-\dfrac{1}{2}\right|=\dfrac{9}{10}-75\%\) 

               \(\left|x-\dfrac{1}{2}\right|=\dfrac{3}{20}\) 

\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=\dfrac{3}{20}\\x-\dfrac{1}{2}=\dfrac{-3}{20}\end{matrix}\right.\) 

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{13}{20}\\x=\dfrac{7}{20}\end{matrix}\right.\)

lê mai
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Nguyễn Hoàng Minh
13 tháng 12 2021 lúc 14:41

\(B=\dfrac{10\cdot9}{\sqrt{10}}-2\cdot5+1+2021=9\sqrt{10}-10+2022=9\sqrt{10}+2012\)

danny danh
20 tháng 1 2022 lúc 9:02

=10⋅9/√10−2⋅5+1+2021=9√10−10+2022=9√10+2012

lê mai
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Akai Haruma
13 tháng 12 2021 lúc 19:38

Lời giải:

Nếu $x+y+z+t=0$ thì $M=\frac{-t}{t}=\frac{-x}{x}=\frac{-z}{z}=-1$

$\Rightarrow (M-1)^{2025}=(-1-1)^{2025}=(-2)^{2025}$

Nếu $x+y+z+t\neq 0$. Áp dụng TCDTSBN:

$M=\frac{x+y+z}{t}=\frac{y+z+t}{x}=\frac{z+t+x}{y}=\frac{t+x+y}{z}=\frac{x+y+z+y+z+t+z+t+x+t+x+y}{t+x+y+z}=\frac{3(x+y+z+t)}{x+y+z+t}=3$

$\Rightarrow (M-1)^{2025}=2^{2025}$