0,3²⁰=(0,3²)¹⁰=0,09¹⁰

Do 0,09<0,1 =>0,09¹⁰<0,1¹⁰

=>0,1¹⁰>0,3²⁰

1,10²⁰và 90¹⁰

ta có:+,10²⁰=(10²)¹⁰=100¹⁰

        +,90¹⁰=90¹⁰

vì 100¹⁰>90¹⁰=>10²⁰>90¹⁰

2,(1/16)¹⁰ và (1/2)⁵⁰

ta có:+, (1/16)¹⁰=(1/16)¹⁰

         +,(1/2)⁵⁰=(1/2⁵)¹⁰=(1/32)¹⁰

vì (1/16)¹⁰>(1/32)¹⁰=>(1/16)¹⁰>(1/2)⁵⁰

k mik nhé

\(a,\)  \(10^{20}=10^{10+10}=10^{10}.10^{10}\)

        \(90^{10}=9^{10}.10^{10}\)

  Vì \(10^{10}.10^{10}>9^{10}.10^{10}\)

    \(\Rightarrow10^{20}>90^{10}\)

Vậy \(10^{20}>90^{10}\)

\(b,\)\(\left(\frac{1}{16}\right)^{10}=\frac{1^{10}}{16^{10}}=\frac{1}{\left(4^2\right)^{10}}=\frac{1}{4^{20}}\)

   \(\left(\frac{1}{2}\right)^{50}=\frac{1^{50}}{2^{50}}=\frac{1}{\left(2^2\right)^{25}}=\frac{1}{4^{25}}\)

Vì \(\frac{1}{4^{20}}>\frac{1}{4^{25}}\)

\(\Rightarrow\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)

Vậy \(\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)

                         ~~~~~~~~~~Hok tốt~~~~~~~~~~~

a/

(0.3)²⁰ = [(0.3)²]¹⁰ = (0.09)¹⁰

^b/ 

(\(\frac{1}{6}\))¹⁰  = [(\(\frac{1}{2}\))⁴]¹⁰ = (\(\frac{1}{2}\))⁴⁰ 

c/

2^400 ₌ (2²)²⁰⁰ = 4²⁰⁰

khó thế nhở ... ko làm được .....

a, Ta có: 5^30 = (5^3)^10= 125^ 10    >   (-10^2)^10= 100^10

b, ta có: 21^12= ( 21^3)^4 > 54^4

 c, Ta có: (1/16)^10 = 1/16^10

                 (1/2)^50= 1/2^50

   Lại có: 16^10=(2^4)^10= 2^40 < 2^50 nên (1/6)^10> (1/2)^50

\(\left(\frac{1}{16}\right)^{10}=\left[\left(\frac{1}{2}\right)^4\right]^{10}=\left(\frac{1}{2}\right)^{40}\)

vì 40<50 nên \(\left(\frac{1}{2}\right)^{40}

\(\left(\dfrac{7}{2}\right)^{50}=\left(\dfrac{16807}{32}\right)^{10}\)

mà 16807/32>1/16

nên \(\left(\dfrac{1}{16}\right)^{10}< \left(\dfrac{7}{2}\right)^{50}\)

a)0,3¹⁰=(0,3²)¹⁰=0,9¹⁰

0,9>0,1=>0,9¹⁰>0,1¹⁰hay0,3²⁰>0,1¹⁰

b)4³⁰+3²⁰=(4³)¹⁰+(3²)¹⁰=(4³+3²)¹⁰=73¹⁰

3.24=72

có 73>72 => 73¹⁰>72¹⁰ hay 4³⁰+3²⁰>3.24¹⁰ (câu này mình ko chắc đúng đâu)

a) 10²⁰ = 100¹⁰  => 10²⁰ > 90¹⁰

b) 0,3²⁰ = 0,9¹⁰  => 0,1¹⁰ < 0,9¹⁰