\(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}\)

\(=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}\)

\(=\frac{1}{2}-\frac{1}{11}+0+0\)

\(=\frac{9}{22}\)

Thanh lý nick này, ai cần xin liên hệ

\(B=\frac{3}{2\cdot5}+\frac{3}{5\cdot8}+\frac{3}{8\cdot11}\)

\(B=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}\)

\(B=\frac{1}{2}-\frac{1}{11}\)

\(B=\frac{9}{11}\)

thanks bn nhiều nha

\(A=\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+\frac{3}{14.17}+\frac{3}{17.20}.\)

\(A=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}+\frac{1}{17}-\frac{1}{20}\)

\(A=\frac{1}{2}-\frac{1}{20}\)

\(A=\frac{10}{20}-\frac{1}{20}\)

\(A=\frac{9}{20}\)

Mình ra kết quả thứ nhất là 17/60 thứ 2 là 9/20 các bạn thấy cái nào đúng 

Ta có : A=3/2x5+3/5x8+3/8x11+3/11x14+3/14x17+3/17x20

     => A=1/2-1/5+1/5-1/8+1/8-1/11+1/11-1/14+1/14-1/17+1/17-1/20

     => A=1/2-1/20

     => A=9/20

Vậy A=9/20

Hãy ủng hộ mik nha bạn .

A=1/5-1/8+1/8-1/11+...+1/602-1/605

=1/5-1/605

=24/121

`@` `\text {Ans}`

`\downarrow`

`A =`\(\dfrac{3}{2\times5}+\dfrac{3}{5\times8}+\dfrac{3}{8\times11}+...+\dfrac{3}{20\times23}+\dfrac{3}{23\times26}\)

`A=`\(\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+...+\dfrac{1}{23}-\dfrac{1}{26}\)

`A=`\(\dfrac{1}{2}-\dfrac{1}{26}\)

`A=`\(\dfrac{6}{13}\)

Vậy, `A=`\(\dfrac{6}{13}\).

mình ko hiểu tại sao lại lấy 1/2 - 1/26 ?

9/20=0,45

k cho minh nha

uqeafyumnjdfjjj

\(\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+...+\frac{3}{2006.2009}\)

\(=\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{2006}-\frac{1}{2009}\)

\(=\frac{1}{5}-\frac{1}{2009}\)

\(=\frac{2004}{10045}\)

Đề: Tính

\(A=\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+...+\frac{3}{2006.2009}\)

\(=\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+...+\frac{1}{2006}-\frac{1}{2009}\)

\(=\frac{1}{5}-\frac{1}{2009}=\frac{2004}{10045}\)

Vậy \(A=\frac{2004}{10045}.\)

\(A=\frac{3}{5\times8}+\frac{3}{8\times11}+\frac{3}{11\times14}+....+\frac{3}{2006\times2009}\)

\(=\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+.......+\frac{1}{2006}-\frac{1}{2009}\)

\(=\frac{1}{5}-\frac{1}{2009}\)

\(=\frac{2009}{10045}-\frac{5}{10045}\)

\(=\frac{2004}{10045}\)

Chúc bạn học tốt

\(A=\dfrac{3}{5\times8}+\dfrac{3}{8\times11}+...+\dfrac{3}{2009\times2012}\)

\(A=\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{11}+...+\dfrac{1}{2009}-\dfrac{1}{2012}\)

\(=\dfrac{1}{5}-\dfrac{1}{2012}=\dfrac{2007}{10060}\)

Ta có : 

\(A=\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{17.20}\)

\(A=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{17}-\frac{1}{20}\)

\(A=\frac{1}{2}-\frac{1}{20}\)

\(A=\frac{9}{20}\)

Vậy \(A=\frac{9}{20}\)

Chúc bạn học tốt ~