x=79

nên x+1=80

\(P\left(x\right)=-80x^6+80x^5-80x^4+...+80x+15\)

\(=-x^6\left(x+1\right)+x^5\left(x+1\right)-x^4\left(x+1\right)+...+x\left(x+1\right)+15\)

\(=-x^7-x^6+x^6+x^5-x^5-x^4+...+x^2+x+15\)

\(=-x^7+x+15\)

\(=-79^7+79+15\)

\(=-79^7+94\)

\(x=79\Leftrightarrow x+1=80\\ \Leftrightarrow P\left(x\right)=-\left(x+1\right)x^6+\left(x+1\right)x^5-\left(x+1\right)x^4+...+\left(x+1\right)x+15\\ P\left(x\right)=-x^7-x^6+x^6+x^5-x^5-x^4+...+x^2+x+15\\ P\left(x\right)=-x^7+x+15=-79^7+94\)

Ta có: x=79

nên x+1=80

\(P\left(x\right)=-x^6\left(x+1\right)+x^5\left(x+1\right)-x^4\left(x+1\right)+...+x\left(x+1\right)+15\)

\(=-x^7+x+15\)

\(=-79^7+94\)

Lời giải:

\(P=-80(x^6-x^5+x^4-x^3+x^2-x+1)+95\)

\(=-(x+1)(x^6-x^5+x^4-x^3+x^2-x+1)+95=-(x^7+1)+95\)

\(=-79^7+94\)

Có : x = 79

=> x + 1 = 80

Xét P(x) , có :

\(P\left(x\right)=x^7-80x^6+80x^5-80x^4+....+80x+15\)

\(P\left(x\right)=x^7-\left(x+1\right)x^6+\left(x+1\right)x^5-\left(x+1\right)x^4+....+\left(x+1\right)x+15\)

\(P\left(x\right)=x^7-x^7-x^6+x^6+x^5-x^5-x^4+....+x^2+x+15\)

\(P\left(x\right)=x+15\)

\(P\left(79\right)=79+15=94\)

\(C=x^7-80x^6+80x^5-80x^4+80x^3-80x^2+80x+15\)

Ta có x=79 => 80=79+1=x+1

\(C=x^7-\left(x+1\right)x^6+\left(x+1\right)x^5-\left(x+1\right)x^4+\left(x+1\right)x^3-\left(x+1\right)x^2+\left(x+1\right)x+15\)

\(C=x^7-x^7-x^6+x^6+x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2+x+15\)

\(C=x+15=79+15=94\)

b) Để \(\dfrac{n+3}{n-1}\) là số nguyên thì \(n+3⋮n-1\)

\(\Leftrightarrow4⋮n-1\)

\(\Leftrightarrow n-1\in\left\{1;-1;2;-2;4;-4\right\}\)

hay \(n\in\left\{2;0;3;-1;5;-3\right\}\)

Thay x+1=80 ta đc:

\(P\left(x\right)=x^7-\left(x+1\right)x^6+\left(x+1\right)x^5-\left(x+1\right)x^4+...+\left(x+1\right)x+15\)

\(=x^7-x^7-x^6+x^6+x^5+...+x^2+x+15\)

\(79+15=94\)

\(Ta \)  \(có \) \(:\)

\(x = 79 \)\(\Rightarrow\)\(x + 1 = 80\)

\(Thay \)  \(x + 1 = 80 \) \(vào \)  \(P(x)\) \(ta\) \(được :\)

\(P ( x ) = x ^7 - ( x + 1 )x ^6 + ( x + 1 )x^5\)\(- ( x + 1 )x ^4\)\(+ ...+ ( x + 1 )x + 15\)

\(P ( x ) = x ^7 - x ^7- x^6 + x^6 + x^5 - x^ 5\)\(- x ^4 + x ^4 + ... - x^ 2 + x ^2 + x + 15\)

\(P ( x ) = x + 15\)

\(Thay x = 79 vào P ( x ) ta được :\)

\(P ( x ) = 79 + 15 = 94\)

a) Ta có: x²\(\ge0,\forall x\) 

=> x² +3/4 \(\ge\dfrac{3}{4}\) , mọi x

Vậy min A = 3/4

Dấu "=" xảy ra <=> x =0

b) ( x- 3/2)² -0,4

Ta có ( x-3/2)² lớn hơn hoặc bằng 0, mọi x

=> ( x-3/2)² - 0,4 lớn hơn hoặc bằng 0 - 0;4 = -0,4

Vậy min B =-0,4

Dấu "=" xảy ra <=> x = 3/2

Chúc bạn học tốt !

bạn cho mik hỏi là min A nghĩa là sao vậy

Min-max tưởng bạn học từ lớp 7 rồi.

Min : Gía trị nhỏ nhất

Max: Gía trị lớn nhất