(2n + 1)³ = 125

(2n + 1)³ = 5³

2n + 1 = 5

2n = 4

n = 2

(2.n+1)³=125

(2.n+1)³=5³

(2.n+1) =5

 2.n      =5-1

 2.n      =4

          n=4:2

           n=2

    (2.n+1)³=125

=>(2.n+1)³=5³

=>2.n+1=5

=>2.n=5-1

=>2.n=4

=>n=4:2

=>n=2

k mik nha

\(2x^2-6x-1=0\)

Theo Vi - ét, ta có :

\(\left\{{}\begin{matrix}x_1+x_2=-\dfrac{b}{a}=\dfrac{6}{2}=3\\x_1x_2=\dfrac{c}{a}=-\dfrac{1}{2}\end{matrix}\right.\)

Ta có :

\(A=\dfrac{x_1-2}{x_2-1}+\dfrac{x_2-2}{x_1-1}\)

\(=\dfrac{\left(x_1-2\right)\left(x_1-1\right)+\left(x_2-2\right)\left(x_2-1\right)}{\left(x_2-1\right)\left(x_1-1\right)}\)

\(=\dfrac{x_1^2-x_1-2x_1+2+x_2^2-x_2-2x_2+2}{x_1x_2-\left(x_1+x_2\right)+1}\)

\(=\dfrac{\left(x_1+x_2\right)^2-2x_1x_2-3\left(x_1+x_2\right)+4}{x_1x_2-\left(x_1+x_2\right)+1}\)

\(=\dfrac{3^2-2.\left(-\dfrac{1}{2}\right)-3.3+4}{-\dfrac{1}{2}-3+1}\)

\(=-2\)

3S= 1.2.(3-0)+ 2.3.(4-1)+...+ n.(n+1).[(n+2)-(n-1)] 
=[1.2.3+ 2.3.4+...+ (n-1)n(n+1)+ n(n+1)(n+2)]- [0.1.2+ 1.2.3+...+(n-1)n(n+1)] 
=n(n+1)(n+2) 
=>S 

Nguyễn Đình Phương giống cn gái tek?

Lần sau bạn viết latex giúp mình nha, ghi vậy mình không biết biểu thức A cái nào trước sau.

=\(\frac{9}{9}\)-\(\frac{5}{9}\)=\(\frac{4}{9}\)

1 - 5/9 = 4/9

1 - 5/9 = 9/9 - 5/9 = 4/9

Đ.số ; 4/9

Ta có: (a-1)²=(a-1)(a-1)

                  =a(a-1)-1(a-1)

                 =(a²-a)-(a-1²)

                =a²-2a+1 

thiếu đầu  xem lại đề mik giải cho

a^2 - a +1

\(S1=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)

\(S1=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}\)

\(S1=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)

\(S1=1-\frac{1}{10}\)

\(S1=\frac{9}{10}\)

CHÚC BN HC GIỎI !!!!!!!!!! TỨ DIỆP THẢO

S=\(\frac{1}{1.2}+\frac{1}{2.3}+...............+\frac{1}{9.10}\)

=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...............+\frac{1}{9}-\frac{1}{10}\)

=\(1-\frac{1}{10}\)

=\(\frac{9}{10}\)

1.My mother cooks very well.She is a famous cook

1 My mother cooks very well.She is a famous cook.

1.My mother cooks very well.She is a famous cook .

chúc bạn học tốt !!!!!!!!!!!!!!!!!!!!!!!!!!!!! ^^