bài 1 ko cho = hả bạn

a) 31 . { 330 : [178 – 4 . ( 35 – 21 : 3 )]} = 31 . { 330 : [178 – 4 . ( 35 – 7)]}

= 31 . { 330 : [178 – 4 . 28]} = 31 . { 330 : [178 – 112]}

= 31 . { 330 : 66 } = 31 . 5 = 155

b) ( 5 19  .  5 14 ) :  5 32  =  5 33 :  5 32 = 5

hơi lệch

\(1,A=\dfrac{2}{3\cdot7}+\dfrac{2}{7\cdot11}+\dfrac{2}{11\cdot15}+...+\dfrac{2}{99\cdot103}\\ 2A=\dfrac{4}{3\cdot7}+\dfrac{4}{7\cdot11}+\dfrac{4}{11\cdot15}+...+\dfrac{4}{99\cdot103}\\ 2A=\dfrac{1}{3}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{11}+...+\dfrac{1}{99}-\dfrac{1}{103}\\ 2A=\dfrac{1}{3}-\dfrac{1}{103}=\dfrac{100}{309}\\ A=\dfrac{100}{309}\cdot\dfrac{1}{2}=\dfrac{50}{309}\)

\(2,A=\dfrac{7}{2}+\dfrac{7}{6}+\dfrac{7}{12}+\dfrac{7}{20}+\dfrac{7}{30}+\dfrac{7}{42}+\dfrac{7}{56}+\dfrac{7}{72}+\dfrac{7}{90}\\ A=7\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{9\cdot10}\right)\\ A=7\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)\\ A=7\left(1-\dfrac{1}{10}\right)=7\cdot\dfrac{9}{10}=\dfrac{63}{10}\)

Bài 1: 

Ta có: \(A=\dfrac{2}{3\cdot7}+\dfrac{2}{7\cdot11}+\dfrac{2}{11\cdot15}+...+\dfrac{2}{99\cdot103}\)

\(=\dfrac{1}{2}\left(\dfrac{4}{3\cdot7}+\dfrac{4}{7\cdot11}+\dfrac{4}{11\cdot15}+...+\dfrac{4}{99\cdot103}\right)\)

\(=\dfrac{1}{2}\left(\dfrac{1}{3}-\dfrac{1}{103}\right)\)

\(=\dfrac{1}{2}\cdot\dfrac{100}{309}=\dfrac{50}{309}\)

Bài 2: 

Ta có: \(A=\dfrac{7}{2}+\dfrac{7}{6}+\dfrac{7}{12}+\dfrac{7}{20}+\dfrac{7}{30}+\dfrac{7}{42}+\dfrac{7}{56}+\dfrac{7}{72}+\dfrac{7}{90}\)

\(=7\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+\dfrac{1}{6\cdot7}+\dfrac{1}{7\cdot8}+\dfrac{1}{8\cdot9}+\dfrac{1}{9\cdot10}\right)\)

\(=7\left(1-\dfrac{1}{10}\right)\)

\(=\dfrac{63}{10}\)

a) 87 x (-78) + 78 x 31 - 78 x (-156)

= (-87 + 31 + 156) x 78

=  100 x 78

= 7800

b) -178 x (-35 - 78) - 78 x (178 + 35)

= -178 x (-113) - 78 x 213

= 20114 - 16614

= 3500

2 x 175 x 5 

= ( 2 x 5 ) x 175

=    10      x 175

=            1750

263 x 15 x 4 

= 263 x ( 15 x 4 )

= 263  x    60

       15780

20 x 198 x 4 

= ( 20 x 4 ) x 198

=      80      x 198

=           15840

505 x 35 x 2 

=  505 x ( 35 x 2 )

=  505 x      70

=        35350

tk nha

2 x 175 x 5 

= ( 2 x 5 ) x 175

= 10 x 175

= 1750

20 x 198 x 4

= ( 20 x 4 ) x 198

= 80 x 198

= 15840

còn lại tự làm nha

Phương pháp giải:

a) Phân tích số có ba chữ số thành tổng các trăm, chục, đơn vị.

b) Viết số có ba chữ số từ tổng trăm, chục, đơn vị đã cho. 

Lời giải chi tiết:

a) Mẫu : 482 = 400 + 80 + 2

687 = 600 + 80 + 7

141 = 100 + 40 + 1

735 = 700 + 30 + 5

460 = 400 + 60

505 = 500 + 5

986 = 900 + 80 + 6

b) Mẫu : 200 + 50 + 9 = 259

600 + 70 + 2 = 672

300 + 90 + 9 = 399

400 + 40 + 4 = 444

900 + 50 + 1 = 951

500 + 20 = 520

700 + 3 = 703

a) 31 . { 330 : [178 – 4 . ( 35 – 21 : 3 )]} = 31 . { 330 : [178 – 4 . ( 35 – 7)]}

= 31 . { 330 : [178 – 4 . 28]} = 31 . { 330 : [178 – 112]}

= 31 . { 330 : 66 } = 31 . 5 = 155

( 5 19 .  5 14 ) :  5 32 =  5 33 :  5 32  = 5

\(3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot\left(7^8-7^6+7^0\right)\right]\right\}\)

\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot5647153\right]\right\}\)

\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-45177224\right]\right\}\)

\(=3^3\cdot5^3-20\cdot\left\{300--45176678\right\}\)

\(=3^3\cdot5^3-20\cdot45176978\)

\(=3375-903539560\)

\(=-903536185\)

\(626500:\left\{50^2:\left[178-4\cdot\left(35-21:3\right)\right]\right\}\)

\(=626500:\left\{50^2:\left[178-4\cdot\left(35-7\right)\right]\right\}\)

\(=626500:\left\{50^2:\left[178-4\cdot28\right]\right\}\)

\(=626500:\left\{50^2:\left[178-112\right]\right\}\)

\(=626500:\left\{50^2:66\right\}\)

\(=626500:\frac{1250}{33}\)

\(=\frac{82698}{5}\)

CHUC BAN HOC TOT >.<