a, \(x^2-4-3\left(x-2\right)=\left(x-2\right)\left(x+2\right)-3\left(x-2\right)=\left(x-1\right)\left(x-2\right)\)

b, \(x^2-xy+5y-25=\left(x-5\right)\left(x+5\right)-y\left(x-5\right)=\left(x+5-y\right)\left(x-5\right)\)

c, \(x^3+x^2-2x-8=\left(x-2\right)\left(x^2+2x+4\right)+x\left(x-2\right)=\left(x-2\right)\left(x^2+3x+4\right)\)

d, \(x^3-4x^2-8x+8=\left(x+2\right)\left(x^2-2x+4\right)-4x\left(x+2\right)=\left(x^2-6x+4\right)\left(x+2\right)\)

Trả lời:

1, x² - 4 - 3 ( x - 2 )

= ( x² - 4 ) - 3 ( x - 2 )

= ( x - 2 ) ( x + 2 ) - 3 ( x - 2 )

= ( x - 2 ) ( x + 2 - 3 )

= ( x - 2 ) ( x - 1 )

2, x² - xy + 5y - 25

= ( x² - 25 ) - ( xy - 5y )

= ( x - 5 ) ( x + 5 ) - y ( x - 5 )

= ( x - 5 ) ( x + 5 - y )

3, x³ + x² - 2x - 8

= ( x³ - 8 ) + ( x² - 2x )

= ( x - 2 ) ( x² + 2x + 4 ) + x ( x - 2 )

= ( x - 2 ) ( x² + 2x + 4 + x )

= ( x - 2 ) ( x² + 3x + 4 )

4, x³ - 4x² - 8x + 8 

= ( x³ + 8 ) - ( 4x² + 8x )

= ( x + 2 ) ( x² - 2x + 4 ) - 4x ( x + 2 )

= ( x + 2 ) ( x² - 2x + 4 - 4x )

= ( x + 2 ) ( x² - 6x + 4 )

xin lỗi em lớp 3 :>>>>

𝑥2−3𝑥+2

(x-5)^2

k nhé tó k lại

.....me chịu.

KHông thì. bạn tải qanda nhé.

chụp bài rồi gửi ,người ta giải cho .

nhưng nó ko quét bài viết bài tay đâu nhé,chỉ quét chữ in thôi.

Trả lời:

a, x⁴ + 3x³ + x² + 3x

= ( x⁴ + 3x³ ) + ( x² + 3x )

= x³ ( x + 3 ) + x ( x + 3 )

= ( x³ + x ) ( x + 3 )

= x ( x² + 1 ) ( x + 3 )

b, Sửa đề: x⁴ - x² + 8x - 8

= ( x⁴ - x² ) + ( 8x - 8 )

= x² ( x² - 1 ) + 8 ( x - 1 ) 

= x² ( x - 1 ) ( x + 1 ) + 8 ( x - 1 )

= ( x - 1 ) [ x² ( x + 1 ) + 8 ]

= ( x - 1 ) ( x³ + x² + 8 )

x⁴ + 3x³ + x² + 3x = x³(x + 3) + x(x + 3)
= (x + 3)(x² + 1)x

\(1,\)

\(\left(x^2-9y^2\right)\left(4x+12y\right)\)

\(=\left(x-3y\right)\left(x+3y\right)-4\left(x+3y\right)\)

\(=\left(x+3y\right)\left(x-3y-4\right)\)

\(3,\)

\(-x^2+2xy-y^2+25\)

\(=-\left(x^2-2xy+y^2\right)+25\)

\(=25-\left(x-y\right)^2\)

\(=5^2-\left(x-y\right)^2\)

\(=\left(5-x+y\right)\left(5+x-y\right)\)

\(5,\)

\(x^3-6x^2+9\)

\(=x\left(x^2-6x+9\right)\)

\(=x\left(x-3\right)^2\)

6, x mũ 4 - 4x mũ 3 - 8x mũ 2 + 8x =x (x+2) (x^2-6x+4)

8, x mũ 4 + 2x mũ 3 + x mũ 2 - y mũ 2  = -(y-x^2-x) (y+x^2+x)

10, 4x mũ 2 ( x + y ) -x - y  = (2x-1) (2x+1) (y+x)

6, \(x^2y+xy^2-4x-4y=xy\left(x+y\right)-4\left(x+y\right)=\left(xy-4\right)\left(x+y\right)\)

7, \(10ax-5ay-2x+y=5a\left(2x-y\right)-\left(2x-y\right)=\left(5a-1\right)\left(2x-y\right)\)

8, xem lại đề bạn nhé

9, \(4x^2-y^2+8y-16=4x^2-\left(y^2-8y+16\right)=4x^2-\left(y-4\right)^2\)

\(=\left(2x-y+4\right)\left(2x+y-4\right)\)

Trả lời:

6, x²y + xy² - 4x - 4y = ( x²y + xy² ) - ( 4x + 4y ) = xy ( x + y ) - 4 ( x + y ) = ( x + y )( xy - 4 )

7, 10ax - 5ay - 2x + y = ( 10ax - 5ay ) - ( 2x - y ) = 5a ( 2x - y ) - ( 2x - y ) = ( 2x - y )( 5a - 1 ) 

8, Sửa đề: x³ - 2x² + 2x - 4 = ( x³ - 2x² ) + ( 2x - 4 ) = x² ( x - 2 ) + 2 ( x - 2 ) = ( x - 2 )( x² + 2 )

9, 4x² - y² + 8y - 16 = 4x² - ( y² - 8y + 16 ) = 4x² - ( y - 4 )² = ( 2x - y + 4 )( 2x + y - 4 )

a)x²−2x−4y²−4ya)x²-2x-4y²-4y

=x²−2x−4y²−4y+2xy−2xy=x²-2x-4y²-4y+2xy-2xy

=(x²−2xy−2x)+(2xy−4y²−4y)=(x²-2xy-2x)+(2xy-4y²-4y)

=x(x−2y−2)+2y(x−2y−2)=x(x-2y-2)+2y(x-2y-2)

=(x+2y)(x−2y−2)=(x+2y)(x-2y-2)

b)x4+2x³−4x−4b)x4+2x³-4x-4

=x4+2x³+2x²−2x²−4x−4=x4+2x³+2x²-2x²-4x-4

=(x4+2x³+2x²)−(2x²+4x+4)=(x4+2x³+2x²)-(2x²+4x+4)

=x²(x²+2x+2)−2(x²+2x+2)=x²(x²+2x+2)-2(x²+2x+2)

=(x²−2)(x²+2x+2)=(x²-2)(x²+2x+2)

c)x³+2x²y−x−2yc)x³+2x²y-x-2y

=x²(x+2y)−(x+2y)=x²(x+2y)-(x+2y)

=(x²−1)(x+2y)=(x²-1)(x+2y)

=(x+1)(x−1)(x+2y)=(x+1)(x-1)(x+2y)

d)3x²−3y²−2(x−y)²d)3x²-3y²-2(x-y)²

=3(x²−y²)−2(x−y)²=3(x²-y²)-2(x-y)²

=3(x+y)(x−y)−2(x−y)²=3(x+y)(x-y)-2(x-y)²

=(x−y)[3(x+y)−2(x−y)]=(x-y)[3(x+y)-2(x-y)]

=(x−y)(3x+3y−2x+2y)=(x-y)(3x+3y-2x+2y)

=(x−y)(x+5y)=(x-y)(x+5y)

e)x³−4x²−9x+36e)x³-4x²-9x+36

=(x³−4x²)−(9x−36)=(x³-4x²)-(9x-36)

=x²(x−4)−9(x−4)=x²(x-4)-9(x-4)

=(x−4)(x²−9)=(x-4)(x²-9)

=(x−4)(x²−3²)=(x-4)(x²-3²)

=(x−4)(x+3)(x−3)=(x-4)(x+3)(x-3)

f)x²−y²−2x−2yf)x²-y²-2x-2y

=(x²−y²)−(2x+2y)=(x²-y²)-(2x+2y)

=(x+y)(x−y)−2(x+y)=(x+y)(x-y)-2(x+y)

=(x+y)(x−y−2)

hok tốt nhé

k đi