d)\(\frac{2.3+4.6+14.21}{3.5+6.10+21.35}=\frac{2.3+2.2.6+2.7.21}{3.5+3.2.10+3.7.35}=\frac{2.3+2.12+2.147}{3.5+3.20+3.245}=\frac{2\left(3+12+147\right)}{3\left(5+20+245\right)}\)

\(=\frac{2.162}{3.270}=\frac{54}{135}=\frac{2}{5}\)

\(a.\frac{-2019.2018+1}{\left(-2017\right).\left(-2019\right)+2018}\)

\(=\frac{2019.\left(-2018\right)+1}{2019.2017+2018}\)

\(=\frac{2019.\left(-2018\right)+1}{2019.2018-1}\)

\(=-\frac{2018}{2018}\)

\(=-1\)

c)\(\frac{2929-101}{2.1919+404}=\frac{29.101-101}{29.101+101.4}=\frac{101\left(29-1\right)}{101\left(29+4\right)}=\frac{28}{33}\)

\(\frac{2929-101}{2.1919+404}\)

\(=\frac{101.\left(29-1\right)}{101\left(2.19+4\right)}\)

\(=\frac{28}{38+4}\)

\(=\frac{28}{42}\)

\(=\frac{2}{3}\)

Ta có : 

\(\frac{2929-101}{2.1919+404}\)

\(=\frac{29.101-101}{2.19.101+4.101}=\frac{101\left(29-1\right)}{101\left(2.19+4\right)}=\frac{28}{38+4}=\frac{28}{42}=\frac{2}{3}\)

Ủng hộ mk nha !!! ^_^

dễ ma bạn

\(\frac{101.29-101.1}{2.101.19+101.4}\)

\(=\frac{101.\left(29-1\right)}{101.\left(2.19+4\right)}\)

\(=\frac{28}{38+4}\)

\(=\frac{28}{42}=\frac{2}{3}\)

\(\frac{2929-101}{2.1919+404}=\frac{29.101-101}{2.19.101+101.4}=\frac{101.\left(29-1\right)}{101.\left(2.19+4\right)}=\frac{28}{42}=\frac{2}{3}\)

\(\frac{2}{3}\)

2929-101

___________

2.1919+404

   2929-101*1

=_____________

   2.1919+101*4

  2929-1*1

=____________ 

   2.1919+1*4

  2929-1

=__________

  2.1919+4

  2928

=_____

  6.1919

\(\frac{2929-101}{2.1919+404}=\frac{29.101-101}{2.19.101+4.101}=\frac{28.101}{42.101}=\frac{2}{3}\)

đáp án = 2/3 đấy bn !!!

2/3 nha bạn

\(\frac{13.\left(2929-101\right)}{2.1919+404}=\frac{13\left(101.29-101\right)}{2.101.19+101.4}=\frac{13.101\left(29-1\right)}{2.101\left(19+2\right)}=\frac{13.28}{2.21}=\frac{13.2}{3}=\frac{26}{3}\)

\(\frac{26}{3}\)

\(B=\frac{2929-101}{2.1919+404}\)

\(B=\frac{29.101-101}{38.101+4.101}\)

\(B=\frac{101.\left(29-1\right)}{101.\left(38+4\right)}\)

\(B=\frac{2}{3}\)

bài này dễ mà bạn

bạn tách ra