26-x/995+22-x/197+18-x/199=12-x/334
tìm x
26-x/995 + 22-x/997 + 18-x/999 = 12-x/334
tìm x biết
\(\frac{26-x}{995}+\frac{22-x}{997}+\frac{18-x}{999}=\)\(\frac{12-x}{334}\)
nhanh nha mấy chế !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
\(\frac{26-x}{995}\)+2+\(\frac{22-x}{997}\)+\(\frac{18-x}{999}\)+2=\(\frac{12-x}{334}\)+6
\(\frac{2016-x}{995.2}\)+\(\frac{2016-x}{997.2}\)+\(\frac{2016-x}{999.2}\)-\(\frac{2016-x}{334.6}\)=0
(2016-x)(\(\frac{1}{995.2}\)+\(\frac{1}{997.2}\)\(\frac{1}{999.2}\)-\(\frac{1}{334.6}\))=0
Dễ thấy giá trị biểu thức trong ngoặc thứ 2 khác 0
Nên 2016-x=0=>x=2016
Vậy giá trị của x là 2016
Các bạn giúp mình bài này với nhé:
Câu 1. Tính:
a) A = 1+2-3-4+5+6-7-8+...-2012+2013+2014-2015-2016
b) B = ( 1-1/4 ) x ( 1-1/9) x ... x ( 1-1/196 )
Câu 2:Tìm x biết:
a) I(x - 2)3I = 69 + (-4).5/4
b) 26 - x/995 + 22-x/997 + 18-x/999 = 12-x/334
Cảm ơn các bạn nha!!!
Câu 1:
a: =(1+2-3-4)+(5+6-7-8)+...+(2013+2014-2015-2016)
=(-4)+(-4)+...+(-4)
=-4x504=-2016
b: \(B=\dfrac{3}{4}\cdot\dfrac{8}{9}\cdot...\cdot\dfrac{195}{196}=\dfrac{1\cdot3\cdot2\cdot4\cdot...\cdot13\cdot15}{2\cdot3\cdot...\cdot14\cdot2\cdot3\cdot...\cdot14}=\dfrac{15}{14\cdot2}=\dfrac{15}{28}\)
31-x/995 + 27-x/997 + 23-x/995= 17-x/334 ai giúp mk mk sẽ cho tích
25-x / 995 + 21-x /997 +17-x / 999 = 11-x / 334. Tìm x
tìm x
25-x/995+21-x/999+17-x/999=11-x/334
(25-x) / 995 + (21-x) /997 +(17-x) / 999 = (11-x) / 334. Tìm x.
So sánh hai phân số: A = 20\39 + 22\27 + 18\43 và B = 14\39 + 22\39 + 18\41.
Rút gọn phân số : 199 .......9 \ 999....... 9.
Tìm x 1) : x-1\10 + x-1\11 = x-1\12 + x-1\13.
2): x-2000\10 + x-1999\9 = x-1998\8 + x-1997\7.
Bài 3:
\(a,\dfrac{x-1}{10}+\dfrac{x-1}{11}=\dfrac{x-1}{12}+\dfrac{x-1}{13}\)
\(\Rightarrow\dfrac{x-1}{10}+\dfrac{x-1}{11}-\dfrac{x-1}{12}-\dfrac{x-1}{13}=0\)
\(\Rightarrow\left(x-1\right)\left(\dfrac{1}{10}+\dfrac{1}{11}-\dfrac{1}{12}-\dfrac{1}{13}\right)=0\)
Mà \(\dfrac{1}{10}+\dfrac{1}{11}-\dfrac{1}{12}-\dfrac{1}{13}\ne0\)
\(\Rightarrow x-1=0\Rightarrow x=1\)
Vậy x = 1
b, \(\dfrac{x-2000}{10}+\dfrac{x-1999}{9}=\dfrac{x-1998}{8}+\dfrac{x-1997}{7}\)
\(\Rightarrow\dfrac{x-2000}{10}+1+\dfrac{x-1999}{9}+1=\dfrac{x-1998}{8}+\dfrac{x-1997}{7}+1\)
\(\Rightarrow\dfrac{x-1990}{10}+\dfrac{x-1990}{9}-\dfrac{x-1990}{8}-\dfrac{x-1990}{7}=0\)
\(\Rightarrow\left(x-1990\right)\left(\dfrac{1}{10}+\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{7}\right)=0\)
Mà \(\dfrac{1}{10}+\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{7}\ne0\)
\(\Rightarrow x-1990=0\Rightarrow x=1990\)
Tìm x , biết : \(\frac{25-x}{995}+\frac{21-x}{997}+\frac{17-x}{999}=\frac{11-x}{334}\)
\(\frac{25-x}{995}+\frac{21-x}{997}+\frac{17-x}{999}=\frac{11-x}{334}\)
\(\Rightarrow\frac{25-x}{995}+2+\frac{21-x}{997}+\frac{17-x}{999}+2=\frac{11-x}{334}+6\)
\(\Rightarrow\frac{25-x}{995}+\frac{1990}{995}+\frac{21-x}{997}+\frac{1994}{997}+\frac{17-x}{999}+\frac{1998}{999}=\frac{11-x}{334}+\frac{2004}{334}\)
\(\Rightarrow\frac{2015-x}{995}+\frac{2015-x}{997}+\frac{2015-x}{999}=\frac{2015-x}{334}\)
\(\Rightarrow\frac{2015-x}{995}+\frac{2015-x}{997}+\frac{2015-x}{999}-\frac{2015-x}{334}=0\)
\(\Rightarrow\left(2015-x\right)\left(\frac{1}{995}+\frac{1}{997}+\frac{1}{999}+\frac{1}{334}\right)=0\)
\(\Rightarrow2015-x=0\left(\text{vì }\frac{1}{995}+\frac{1}{997}+\frac{1}{999}+\frac{1}{334}\ne0\right)\)
\(\Rightarrow x=2015\)