\(\dfrac{22}{5}\times\dfrac{6}{121}\times\dfrac{11}{4}\times\dfrac{3}{5}\times\dfrac{1}{3}\times\dfrac{5}{4}\)

\(=\left(\dfrac{22}{5}\times\dfrac{5}{4}\right)\times\left(\dfrac{6}{121}\times\dfrac{11}{4}\right)\times\left(\dfrac{3}{5}\times\dfrac{1}{3}\right)\)

\(=\dfrac{11}{2}\times\dfrac{3}{22}\times\dfrac{1}{5}\)

\(=\dfrac{3}{20}\)

\(=\dfrac{22\times6\times11\times3\times1\times5}{5\times121\times4\times5\times3\times4}=\dfrac{11\times2\times6\times11\times1}{11\times11\times4\times5\times4}=\dfrac{2\times6\times1}{4\times5\times4}=\dfrac{18}{100}=\dfrac{9}{50}\)

a) \(\frac{22}{7}:\left(11-x\right)+\frac{2}{3}=\frac{7}{5}\)
                \(\frac{22}{7}:\left(11-x\right)=\frac{7}{5}-\frac{2}{3}\)
                \(\frac{22}{7}:\left(11-x\right)=\frac{11}{15}\)
                                \(11-x=\frac{22}{7}:\frac{11}{15}\)
                                \(11-x=\frac{30}{7}\)
                                            \(x=11-\frac{30}{7}\)
                                            \(x=\frac{47}{7}\)
b) \(22.\left(x+1\right)-12,5=53,5\)
                     \(22.\left(x+1\right)=53,5+12,5\)
                     \(22.\left(x+1\right)=66\)
                                  \(x+1=66:22\)
                                  \(x+1=3\)
                                           \(x=3-1\)
                                           \(x=2\)
c) \(\left(x-\frac{1}{2}\right).\frac{5}{2}+\frac{1}{2}=\frac{7}{4}\)
                \(\left(x-\frac{1}{2}\right).\frac{5}{2}=\frac{7}{4}-\frac{1}{2}\)
                \(\left(x-\frac{1}{2}\right).\frac{5}{2}=\frac{5}{4}\)
                             \(x-\frac{1}{2}=\frac{5}{4}:\frac{5}{2}\)
                             \(x-\frac{1}{2}=\frac{1}{2}\)
                                         \(x=\frac{1}{2}+\frac{1}{2}\)
                                         \(x=1\)
                 
            
       
                              
                                       
                                      
                                     
                                         

a)22/7:(11-x)=7/5-2/3

            22/7:(11-x)=11/15

           11-x=22/7:11/15

11-x=30/7

     x=11-30/7

      x=47/7 

vậy x=47/7

b)22.(x+1)=53,5+12,5

22.(x+1)=66

x+1=66:2

x+1=3

x=3-1

x=2

vậy x=2

c)(x-1/2).5/2=7/4-1/2

(x-1/2).5/2=5/4

x-1/2=5/4:5/2

x-1/2=1/2

x=1/2+1/2

x=1

vậy x=1 

bạn hãy tích đúng cho mình nhé

12/5-x=1

1.

a. (x - 12,5) : 3/4 = 8/5

x - 12,5 = 8/5 x 3/4

x = 6/5 + 12,5

x = 137/10 = 13.7

1.

b, (x -2/5) x 5/11 = 75/22

x - 2/5 = 75/22 : 5/11

x = 15/2 + 2/5

x = 79/10 = 7.9

Mon ben ak,con 2bai bai nx thui a~ ban neo giup mk nx thi 1 hom mk k cho 3 k trong 1 thang ngay nao mk cx k choa lun!

2:

a: x=2,4-0,4=2

b: =>2x=-1,5+0,8=-0,7

=>x=-0,35

c: =>x-16=-15

=>x=1

A)  7/38 x 9/11 +7/38 x 4/11 -7/38 x 2/11

=7/38.(9/11+4/11-2/11)

=7/38

B) 5/31 x 21/25 + 5/31 x -7/10 - 5/31 x 9/20

=5/31.(21/25-7/10-9/20)

=5/31.(-31/100)

=-1/20

6927/440

cách làm cụ thể nhé

1: \(\dfrac{4}{23}+\dfrac{5}{21}+\dfrac{1}{2}-\dfrac{4}{23}+\dfrac{16}{21}\)

\(=1+\dfrac{1}{2}\)

\(=\dfrac{3}{2}\)

2: \(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)

\(=\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}-\dfrac{79}{67}+\dfrac{28}{41}\)

\(=\dfrac{1}{3}\)

\(\dfrac{37\cdot5^4}{25^2}=\dfrac{37\cdot5^4}{5^4}=37\\ \dfrac{2^4\cdot2^6\cdot3^8\cdot9^2}{4^4\cdot3^{11}}=\dfrac{2^{10}\cdot3^8\cdot3^4}{2^8\cdot3^{11}}=2^2\cdot3=12\\ \dfrac{3\cdot9^4\cdot9^3}{3^2\cdot9}=\dfrac{3\cdot3^8\cdot3^6}{3^2\cdot3^2}=3^{11}\\ \dfrac{125\cdot5\cdot64-25^3\cdot10\cdot4}{5^7\cdot8}=\dfrac{5^3\cdot5\cdot2^6-5^6\cdot2\cdot5\cdot2^2}{5^7\cdot2^3}=\dfrac{5^4\cdot2^3\left(2^3-5^3\right)}{5^7\cdot2^3}=\dfrac{8-125}{5^3}=\dfrac{-117}{125}\)

a, (x+2)+(x+5)+(x+8)+(x+11)+(x+14)=75

 5x + (2 + 5 + 8 + 11 + 14) = 75

5x + 40 = 75

5x = 35

x = 7

Các câu dưới tương tự.

a)(x+2)+(x+5)+(x+8)+(x+11)+(x+14)=75

x+x+x+x+x+2+5+8+11+14=75

5xx+40=75

5xx=75-40

5xx=35

x=35:5

x=7

b)(x+1)+(x+3)+(x+5)+....+(x+101)=5400

Nhận thấy dãy trên có (101-1):2+1=51(số) nên có 51 x

Tách như câu a

51xx+(1+3+5+...+101)=5400

51xx+[(101+1)x51:2]=5400

51xx+2601=5400

51xx=5400-2601

51xx=2799

x=2799:51

x=933/17

c)(x+1)+(x+4)+(x+7)+....+(x+94)=1840

Phần c này cũng giống phần b,em dựa vào mà làm nhé,giống,khác mỗi số thôi

Chúc em họ tốt^^