Mình làm và sửa đề đúng luôn nhé !

1) \(36x^2-a^2+10a-25\)

\(=\left(6x\right)^2-\left(a^2-10a+25\right)\)

\(=\left(6x\right)^2-\left(a-5\right)^2\)

\(=\left(6x-a+5\right)\left(6x+a-5\right)\)

2) \(4x^2-4xy+y^2-25a^2+10a-1\)

\(=\left(2x-y\right)^2-\left(5a-1\right)^2\)

\(=\left(2x-y-5a+1\right)\left(2x-y+5a-1\right)\)

3) \(m^2-6m+9-x^2+4xy-4y^2\)

\(=\left(m-3\right)^2-\left(x-2y\right)^2\)

\(=\left(m-3-x+2y\right)\left(m+3-x+2y\right)\)

\(4x^2-4xy+y-25a^2+10a-136\)

\(\text{Phân tích thành nhân tử}\)

\(-\left(4xy-y-4x^2+25a^2-10a+136\right)\)

k nhé !

Sai đề

Sửa đề: \(4x^2-4xy+y^2-25a^2+10a-1\)

\(=\left(2x-y\right)^2-\left(5a-1\right)^2\)

\(=\left(2x-y-5a+1\right)\left(2x-y+5a-1\right)\)

Sửa đề: \(4x^2-4xy+y^2-25a^2+10a-1\)

\(=\left(2x-y\right)^2-\left(5a-1\right)^2\)

\(=\left(2x-y-5a+1\right)\left(2x-y+5a-1\right)\)

Sửa đề: \(4x^2-4xy+y^2-25a^2+10a-1\)

\(=\left(2x-y\right)^2-\left(5a-1\right)^2\)

\(=\left(2x-y-5a+1\right)\left(2x-y+5a-1\right)\)

đề như này thì phân tích kiểu gì bạn

a: 

Sửa đề: \(4x^2-4xy+y^2-25a^2+10a-1\)

\(=\left(2x-y\right)^2-\left(5a-1\right)^2\)

\(=\left(2x-y-5a+1\right)\left(2x-y+5a-1\right)\)

b: Sửa đề: \(ax^2+bx^2+2xy\left(a+b\right)+ay^2+by^2\) 

\(=ax^2+ay^2+2xya+bx^2+2xyb+by^2\)

\(=a\left(x+y\right)^2+b\left(x+y\right)^2\)

\(=\left(x+y\right)^2\left(a+b\right)\)

\(1.25a^2+10a+1\)

\(=\left(5a\right)^2+2.5a.1+1^2\)

\(=\left(5a+1\right)^2\)

\(2.2x^8-12x^4+18\)

\(=2\left(x^8-6x^4+9\right)\)

\(=2\left[\left(x^4\right)^2-2.x^4.3+3^2\right]\)

\(=2\left(x^4-3\right)^2\)

\(=2\left(x^2-\sqrt{3}\right)^2\left(x^2+\sqrt{3}\right)^2\)

\(3.4x+4xy^6+xy^{12}\)

\(=x\left(y^{12}+4y^6+4\right)\)

\(=x\left[\left(y^6\right)^2+2.y^6.2+2^2\right]\)

\(=x\left(y^6+2\right)^2\)

Câu 1

\(25a^2+10a+1\)

\(=\left(5a\right)^2+2\cdot5\cdot a+1\)

\(=\left(5a+1\right)^2\)

A) \(25a^2+10a+1\)

\(=\left(5a\right)^2+2.5a.1+1^2\)

\(=\left(5a+1\right)^2\)

B) \(2x^8-12x^4+18\)

\(=2.\left(x^8-6x^4+9\right)\)

\(=2.\left[\left(x^4\right)^2-2.x^4.3+3^2\right]\)

\(=2.\left(x^4+3\right)^2\)

C) \(4x+4xy^6+xy^{12}\)

\(=\left(2\sqrt{x}\right)^2+2.\left(2\sqrt{x}\right).y^6+\left(xy^6\right)^2\)

\(=\left[\left(2\sqrt{x}\right)+xy^6\right]^2\)

P/s : Câu cuối không chắc chắn :))

Câu 3 dễ nên mk chỉ làm được câu 3 thôi

3.\(x^2\left(a+b\right)-4xa-4xb+4a+4b\)

\(=x^2\left(a+b\right)-4x\left(a+b\right)+4\left(a+b\right)\)

\(=\left(a+b\right)\left(x^2-4x+4\right)\)

\(=\left(a+b\right)\left(a-b\right)^2\)

1: Sửa đề: \(4x^2-4xy+y^2-25a^2+10a-1\)

\(=\left(2x-y\right)^2-\left(5a-1\right)^2\)

\(=\left(2x-y-5a+1\right)\left(2x-y+5a-1\right)\)

2: Sửa đề: \(ax^2+bx^2+2axy+2bxy+ay^2+by^2\)

\(=a\left(x^2+2xy+y^2\right)+b\left(x^2+2xy+y^2\right)\)

\(=\left(x+y\right)^2\left(a+b\right)\)