a=1/1+3+1/1+3+5+1/1+3+5+7+......+1/1+3+5+7+...+2017
chung minh a<3/4
a)chung minh A= 2^1+2^2+2^3+2^4+...2^2010chia het cho 3
b)chung minh B= 3^1+3^2+3^3+3^4+...3^2010chia het cho 4
c)chung minh C= 5^1+5^2+5^3+5^4+...5^2010chia het cho 6
d)chung minh D= 7^1+7^2+7^3+7^4+...7^2010chia het cho 8
a) A=21+22+23+...+22010
A=(21+22)+(23+24)+.....+(22009+22010)
A=(21x3)+(23x3)+.....+(22009x3)
A=3x(21+23+.......+22009)
Vậy A chia hết cho 3.
NHỮNG CÂU CÒN LẠI BẠN LÀM TƯƠNG TỰ !
A=1/1+3+ 1/1+3+5+............+ 1/1+3+5+7+.........+2017
chung minh A<3/4
Cho A = 1/1+3 + 1/1+3+5 + 1/1+3+5+7 + 1/1+3+.....+2013
Chứng minh A < 3/4
Ta có :
\(A=\dfrac{1}{1+3}+\dfrac{1}{1+3+5}+...........+\dfrac{1}{1+3+.....+2013}\)
\(A=\dfrac{1}{\dfrac{\left(1+3\right).2}{2}}+\dfrac{1}{\dfrac{\left(1+5\right).3}{2}}+.........+\dfrac{1}{\dfrac{\left(1+2013\right).1007}{2}}\)
\(A=\dfrac{2}{2.4}+\dfrac{2}{3.6}+\dfrac{2}{4.8}+...........+\dfrac{2}{1007.2014}\)
\(A=\dfrac{1}{2.2}+\dfrac{1}{3.3}+\dfrac{1}{4.4}+..........+\dfrac{1}{1007.1007}\)
\(\Rightarrow A< \dfrac{1}{2.2}+\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+......+\dfrac{1}{1006.1008}\right)\)
\(\Rightarrow A< \dfrac{1}{4}+\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...........+\dfrac{1}{1006}-\dfrac{1}{1007}\right)\)
\(\Rightarrow A< \dfrac{1}{4}+\left(\dfrac{1}{2}-\dfrac{1}{1007}\right)\)
\(\Rightarrow A< \dfrac{1}{4}+\dfrac{1}{2}=\dfrac{3}{4}\) \(\rightarrowđpcm\)
~ Chúc bn học tốt ~
Cho A= \(\frac{1}{1+3}+\frac{1}{1+3+5}+\frac{1}{1+3+5+7}+...+\frac{1}{1+3+5+7+...+2017}\)
Chứng minh A<\(\frac{3}{4}\)
A=1/(1+3)+1/(1+3+5)+1/(1+3+5+7)+...+1/(1+3+5+7+...+2017)
A=1/2^2+1/3^2+1/4^2+...+1/1009^2
2A=2/2^2+2/3^2+2/4^2+...+2/1009^2
Ta co :(x-1)(x+1)=(x-1)x+x-1=x^2-x+x-1=x^2-1<x^2
suy ra 2A<2/(1*3)+2/(3*5)+2/(5*7)+...+2/(1008*1010)
suy ra 2A <1-1/3+1/3-1/5+1/5-1/7+...+1/1008-1/1010
suy ra 2A<1-1/1010
suy ra 2A<2009/2010<1<3/2
suy ra 2A <3/2
suy ra A <3/4 (dpcm)
nho k cho minh voi nha
A=1/(1+3)+1(1+3+5)+1/(1+3+5+7)+....+1/(1+3+5+7+...+2017)
A=1/4+1/9+1/16+....+1/1018081
A=1/2^2+1/3^2+1/4^2+...+1/1009^2
Ta có : 1/3^2=1/3x3<1/2x3
1/4^2=1/4x4<1/3x4
......
1/1009^2<1/1008x1009
Suy ra 1/2^2+1/3^2+1/4^2+.....+1/1009^2<1/2^2+1/2x3+1/3x4+.....+1/1008x1009
Suy ra A< 1/2^2+1/2-1/3+1/3-1/4+.....+1/1008-1/1009
=> A<1/2^2+1/2+1/3-1/3+......+1/1008-1/1008-1/1009
=> A<1/2^2+( 1/2-1/1009)
=> A< 3023/4036
Mà +) 3023<3/4
+) A<3023/4026
Suy ra A<3/4
=> A<1008/1009
Ta có 1008/1009+
A= 1/1+3+5 + 1/1+3+5 + 1/1+3+5+7 +...+ 1/1+3+5+7+...2021
mà A=3/4
GIÚP MÌNH VỚI
A = \(\dfrac{1}{1+3}\) + \(\dfrac{1}{1+3+5}\) + \(\dfrac{1}{1+3+5+7}\) + ... + \(\dfrac{1}{1+3+5+7+...+2021}\)
\(\Leftrightarrow\) A = \(\dfrac{1}{\dfrac{\left(1+3\right).2}{2}}\) + \(\dfrac{1}{\dfrac{\left(1+5\right).3}{2}}\) + \(\dfrac{1}{\dfrac{\left(1+7\right).4}{2}}\) + ... + \(\dfrac{1}{\dfrac{\left(1+2021\right).1011}{2}}\)
= \(\dfrac{2}{2.4}\) + \(\dfrac{2}{3.6}\) + \(\dfrac{2}{4.8}\) + ... + \(\dfrac{2}{1011.2021}\)
= \(\dfrac{1}{2.2}\) + \(\dfrac{1}{3.3}\) + \(\dfrac{1}{4.4}\) + ... + \(\dfrac{1}{2021.2021}\)
A < \(\dfrac{1}{4}\) + ( \(\dfrac{1}{2.3}\) + \(\dfrac{1}{3.4}\) + ... + \(\dfrac{1}{2020.2021}\) )
< \(\dfrac{1}{4}\) + ( \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\) + \(\dfrac{1}{3}\) - \(\dfrac{1}{4}\) + ... + \(\dfrac{1}{2020}\) - \(\dfrac{1}{2021}\) )
< \(\dfrac{1}{4}\) + ( \(\dfrac{1}{2}\) - \(\dfrac{1}{2021}\) ) < \(\dfrac{1}{4}\) + \(\dfrac{1}{2}\) = \(\dfrac{3}{4}\)
Kiểu như vậy hả ?
Giúp mình bài này với
a) Tìm các số tự nhiên a và b thỏa mãn : ( 100a + 3b +1 )( 2^a + 10a + b ) = 225
b) Cho A = 1/1+3 + 1/1+3+5 + 1/1+3+5+7 + ... + 1/1+3+5+7+...+2017
Chứng minh A < 3/4
a, tính 5/1*3+5/3*7+...+5/19*21
b,chứng minh rằng A=1/1*3+1/3*5+...+1/(2n-1)(2n+1)<1/2
A) Chứng minh: A=2^1+2^2+2^3+2^4+.........+2^2010 chia hết cho 3 và 7
B)Chứng minh:B=3^1+3^2+3^3+3^4+..........+2^2010 chia hết cho 4 và 13
C) Chứng minh C=5^1+5^2+5^3+5^4+.......+5^2010 chia hết cho 6 và 31
D) Chứng minh D=7^1+7^2+7^3+7^4+........+7^2010 chia hết cho 8 và 57
a)-1/24-[1/4-(1/2-7/8)]
b)(5/7-7/5)-[-1/2-(-2/7-1/10)
c)(-1/2)-(-3/5)+(-1/9)+1/71-(-2/7)+4/35-7/18
d) (3-1/4+2/3) -(5-1/3-6/5)-(6-7/4+3/2)
a) -1/24 - [ 1/4 - ( 1/2 - 7/8 )]
= -1/24 - [ 1/4 +3/8 ]
= -1/24 - 5/8
= -2/3.
a) -1/24 - [ 1/4 - ( 1/2 - 7/8 )]
= -1/24 - [ 1/4 +3/8 ]
= -1/24 - 5/8
= -2/3.
Xin lỗi nha chỉ có thời gian làm câu a) thôi