\(B=\frac{\frac{1}{39}-\frac{1}{6}-\frac{1}{51}}{\frac{1}{8}-\frac{1}{52}+\frac{1}{68}}:\frac{31}{6}\)

\(=\frac{\frac{1}{3}\left(\frac{1}{13}-\frac{1}{2}-\frac{1}{17}\right)}{\frac{1}{4}\left(\frac{1}{2}-\frac{1}{13}+\frac{1}{17}\right)}.\frac{6}{31}\)

\(=\frac{\frac{-1}{3}\left(\frac{-1}{13}+\frac{1}{2}+\frac{1}{17}\right)}{\frac{1}{4}\left(\frac{1}{2}-\frac{1}{13}+\frac{1}{17}\right)}.\frac{6}{31}\)

\(=\frac{-1}{3}:\frac{1}{4}.\frac{6}{31}\)

\(=\frac{-1}{3}.4.\frac{6}{31}\)

Tiếp theo dễ r tự làm tiếp :)

SỐ LẺ NHA BẠN - \(\frac{1704}{4991}\)

Cách giải bạn có thể hướng dẫn mk ko cảm ơn bạn nhiều!

\(A=\left[6.\left(\frac{1}{3}\right)^3-3\left(\frac{-1}{3}\right)+1\right]:\left(\frac{-1}{3}-1\right)\)

\(A=\left[6.\frac{1}{27}-3.\left(\frac{-1}{3}\right)+1\right]:\left(\frac{-1}{3}-1\right)\)

\(A=\left[\frac{2}{9}-\frac{-3}{3}+\frac{9}{9}\right]:\left(\frac{-1}{3}+\frac{-3}{3}\right)\)

\(A=\frac{2}{9}.\frac{-3}{4}=\frac{1}{3}.\frac{-1}{2}=\frac{-1}{6}\)

?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????/??bố thằng nào mà biết được

\(\dfrac{\dfrac{1}{6}-\dfrac{1}{39}+\dfrac{1}{51}}{\dfrac{1}{8}-\dfrac{1}{52}+\dfrac{1}{68}}\)

\(\dfrac{11}{\dfrac{78}{\dfrac{11}{104}+\dfrac{1}{68}}}+\dfrac{1}{51}\)

\(\dfrac{71}{\dfrac{442}{\dfrac{213}{1768}}}\)\(\Rightarrow\dfrac{4}{3}\)

= \(\dfrac{4}{3}\)

Ta có : \(B=\frac{\frac{1}{39}-\frac{1}{6}-\frac{1}{51}}{\frac{1}{8}-\frac{1}{52}+\frac{1}{68}}:5\frac{1}{6}\)

=> \(B=\frac{\frac{\frac{1}{13}-\frac{1}{2}-\frac{1}{17}}{3}}{\frac{\frac{1}{2}-\frac{1}{13}+\frac{1}{17}}{4}}:5\frac{1}{6}\)

=> \(B=\frac{\frac{\frac{1}{13}-\frac{1}{2}-\frac{1}{17}}{3}}{\frac{\frac{1}{13}-\frac{1}{2}-\frac{1}{17}}{-4}}:5\frac{1}{6}\)

=> \(B=\frac{-4}{3}:5\frac{1}{6}\)

=> \(B=\frac{-8}{6}:\frac{31}{6}=-\frac{8}{6}.\frac{6}{31}=-\frac{8}{31}\)

Nguyễn Ngọc Lộc No choice teenPhạm Thị Diệu HuyềnTrên con đường thành công không có dấu chân của kẻ lười biếngVũ Minh Tuấn

Ta có: \(\frac{\frac{1}{6}-\frac{1}{39}+\frac{1}{51}}{\frac{1}{8}-\frac{1}{52}+\frac{1}{68}}=\frac{\left(\frac{1}{6}-\frac{1}{39}+\frac{1}{51}\right).5304}{\left(\frac{1}{8}-\frac{1}{52}+\frac{1}{68}\right).5304}\)\(=\frac{136-884+104}{663-102+78}=-\frac{664}{639}\)

Ta có : \(\frac{\frac{1}{39}-\frac{1}{6}-\frac{1}{51}}{\frac{1}{8}-\frac{1}{52}+\frac{1}{68}}=\frac{\left(\frac{1}{39}-\frac{1}{6}-\frac{1}{51}\right)\times5304}{\left(\frac{1}{8}-\frac{1}{52}+\frac{1}{68}\right)\times5304}=\frac{136-884-104}{663-102+78}=\frac{-852}{639}=-\frac{4}{3}\)

\(\frac{-4}{3}\)