a) \(A=-\frac{13}{4}=-3-\frac{1}{4}< -3,B=\frac{17}{-6}>\frac{18}{-6}=-3\)

suy ra \(A< B\).

b) \(\frac{20^{10}+1}{20^{10}-1}=1+\frac{2}{20^{10}-1},\frac{20^{10}-1}{20^{10}-3}=1+\frac{2}{20^{10}-3}\)

Có \(20^{10}-1>20^{10}-3>0\Leftrightarrow\frac{2}{20^{10}-1}< \frac{2}{20^{10}-3}\)

Suy ra \(A< B\).

ông đi qua bà đi lại có ai biết làm không thì GIÚP MK VỚI

ko biêt làm

bài 1 :

a)\(2,5.16,27.4+7,3=\left(2,5.4\right).16,27+7,3=10.16,27+7,3\)

\(=162,7+7,3=170\)

b) \(\frac{2}{3}+\frac{3}{4}-\frac{5}{6}=\left(\frac{2}{3}-\frac{5}{6}\right)+\frac{3}{4}=\frac{-1}{6}+\frac{3}{4}=\frac{7}{12}\)

c) \(17,6-5,3+16,8-7,6+15,3-6,8\)

\(=\left(17,6-7,6\right)+\left(-5,3+15,3\right)+\left(16,8-6,8\right)\)

\(=10+10+10=30\)

d)\(\frac{38}{11}+\left(13,16+\frac{6}{11}\right)=\frac{38}{11}+13,16+\frac{6}{11}\)

\(=\left(\frac{38}{11}+\frac{6}{11}\right)+13,16=4+13,16=17,16\)

\(2,45.46+8.0,75+54.2,45+0,5.8\\ =\left[2,45.46+54.2,45\right]\)

\(+\left[8.0,75+0,5.8\right]=\left[2,45.\left(46+54\right)\right]+\left[8.\left(0,75+0,5\right)\right]\)

\(=\left(2,45.100\right)+\left(8.1,25\right)=245+10=255\)

 bài 2 :

a) .....

b) \(1-\left(12,5+x-4,25\right):21,75=0\)

\(\Rightarrow1-\left(12,5+x-4,25\right)=21,75\)

\(\Rightarrow12,5+x-4,25=-20,75\\ \Rightarrow12,5+x=-16,5\)

\(\Rightarrow x=-29\)

cậu có thể tham khảo bài làm trên đây ạ, mn ai thấy đúng thì cho mk xin 1 t.i.c.k đúng ạ ,thank nhiều

a/b=17

nên a=17b

Ta có: a+b=-496

=>17b+b=-496

=>18b=-496

hay b=-248/9

=>a=-4216/9

Ta có : \(A=\frac{10^{17}+5}{10^{17}-8}=\frac{10^{17}-8+13}{10^{17}-8}=1+\frac{13}{10^{17}-8}\)

Lại có B = \(\frac{10^{17}-13+13}{10^{17}-13}=1+\frac{13}{10^{17}-13}\)

Nhận thấy 10¹⁷ - 8 > 10¹⁷ - 13

=> \(\frac{13}{10^{17}-8}< \frac{13}{10^{17}-13}\)

=> \(1+\frac{13}{10^{17}-8}< 1+\frac{13}{10^{17}-13}\)

=> A < B

Câu 1 : Tìm x

\(\frac{7}{12}-\left[2x-\frac{4}{9}\right]=1\)

\(\Rightarrow\frac{7}{12}-1=\left[2x-\frac{4}{9}\right]\)

\(\Rightarrow\frac{7}{12}-\frac{12}{12}=\left[2x-\frac{4}{9}\right]\)

\(\Rightarrow\frac{-5}{12}=2x-\frac{4}{9}\)

\(\Rightarrow2x-\frac{4}{9}=\frac{-5}{12}\)

\(\Rightarrow2x=-\frac{5}{12}+\frac{4}{9}\)

Đến đây dễ tìm rồi :v

Câu 2: a, Ta có : \(MSC=BCNN(21,15)=105\)

Quy đồng : \(\frac{17}{21}=\frac{17\cdot5}{21\cdot5}=\frac{85}{105}\)

\(\frac{13}{15}=\frac{13\cdot7}{15\cdot7}=\frac{91}{105}\)

Mà 85 < 91 => \(\frac{85}{105}< \frac{91}{105}\). Vậy : \(\frac{17}{21}< \frac{13}{15}\)

Vậy còn ý b đâu bạn

Ý b tương tự như ý a nhé bạn đào quỳnh anh :v

Study well >_<

\(ta có A=\dfrac{13^{15}+1}{13^{16}+1}=\dfrac{13^{15}}{13^{16}}+1\)=\(\dfrac{1}{13}+1\)

B=\(\dfrac{13^{16}+1}{13^{17}+1}=\dfrac{13^{16}}{13^{17}}+1\)=\(\dfrac{1}{13}+1\)

vậy A=B

\(A=\dfrac{13^{15}+1}{13^{16}+1}vàB=\dfrac{13^{16}+1}{13^{17}+1}\)

ta có

\(\dfrac{13^{16}+1}{13^{17}+1}< 1\Rightarrow\dfrac{13^{16}+1+12}{13^{17}+1+12}=\dfrac{13\left(13^{15}+1\right)}{13\left(13^{16}+1\right)}=\dfrac{13^{15}+1}{13^{16}+1}=A\)

vậy B<A

\(A=\dfrac{13^{15}+1}{13^{16}+1}vàB=\dfrac{13^{16}+1}{13^{17}+1}\)

ta có B<1 nên

\(\dfrac{13^{16}+1}{13^{17}+1}< \dfrac{13^{16}+1+12}{13^{17}+1+12}=\dfrac{13\left(13^{15}+1\right)}{13\left(13^{16}+1\right)}=\dfrac{13^{15}+1}{13^{16}+1}=A\)

Vậy B<A