Một mảnh đất HCN có chiều dài 90cm chiều rộng bằng 3/5 chiều dài. Tính chu vi mảnh vườn đó

4/6 + 7/13 + 17/9 + 19/13 + 1/9 + 14/6

= ( 4/6 + 14/6 ) + ( 7/13 + 19/13 ) + ( 17/9 + 1/9 )

= 18/6 + 26/13 + 18/9

= 3 + 2 + 2 = 7

ta co 4/6+14/6+7/13+19/13+17/9+1/9

=3+2+2

=7

nhé bạn ok bye

\(\frac{19}{13}+\frac{14}{16}+\frac{1}{9}+\frac{4}{6}+\frac{7}{13}+\frac{17}{9}\)

\(=\left(\frac{19}{13}+\frac{7}{13}\right)+\left(\frac{14}{6}+\frac{4}{6}\right)+\left(\frac{1}{9}+\frac{17}{9}\right)\)

\(=2+3+2\)

\(=7\)

chúc bạn học tootrs nha

19/13 + 14/16 + 1/9 + 4/6 + 7/13 + 17/9

= ( 19/13 + 7/13 ) + ( 14/16 + 4/6 ) + ( 1/9 + 17/9 )

= 26/13 + 37/24 + 18/9

= 2 + 37/24 + 2

=( 2 + 2 ) + 37/24

= 4 + 37/24

= 133/24.

14/6 + 1/9 + 19/13 + 17/9 + 7/13 + 4/6 = (14/6 + 4/6) + (1/9 + 17/9) + (19/13 + 7/13)

                                                            = 18/6 + 18/9 + 26/13

                                                             = 3 + 2 + 2

                                                               = 7 

a) \(\dfrac{4}{6}+\dfrac{7}{13}+\dfrac{17}{9}-\dfrac{8}{9}+\dfrac{14}{6}+\dfrac{19}{13}\)

\(=\dfrac{2}{3}+\dfrac{7}{13}+\dfrac{17}{9}-\dfrac{8}{9}+\dfrac{7}{3}+\dfrac{19}{13}\)

\(=\left(\dfrac{2}{3}+\dfrac{7}{3}\right)+\left(\dfrac{7}{13}+\dfrac{19}{13}\right)+\left(\dfrac{17}{9}-\dfrac{8}{9}\right)\)

\(=\dfrac{9}{3}+\dfrac{26}{13}+\dfrac{9}{9}\)

\(=3+2+1\)

\(=6\)

b) \(\dfrac{328}{435}\times\dfrac{468}{432}\times\dfrac{435}{164}\times\dfrac{432}{984}\times\dfrac{164}{468}\)

\(=\dfrac{328\times468\times435\times432\times164}{435\times432\times164\times984\times468}\)

\(=\dfrac{328}{984}\)

\(=\dfrac{1}{3}\)

A = \(\dfrac{4}{3}\) + \(\dfrac{17}{3}\) +  \(\dfrac{17}{9}\) + \(\dfrac{19}{13}\) + \(\dfrac{1}{9}\) + \(\dfrac{14}{6}\)

A = (\(\dfrac{4}{3}\) + \(\dfrac{17}{3}\)) + (\(\dfrac{17}{9}\) + \(\dfrac{1}{9}\)) + (\(\dfrac{19}{13}\) + \(\dfrac{14}{6}\))

A = \(\dfrac{21}{3}\) + \(\dfrac{18}{9}\) + \(\dfrac{148}{39}\)

A = 7 + 2 + \(\dfrac{148}{39}\)

A = 9 + \(\dfrac{148}{39}\)

A = \(\dfrac{39\times9}{39}\) + \(\dfrac{148}{39}\)

A = \(\dfrac{499}{39}\)

4/3+17/3+17/9+19/13+1/9+14/6=499/39.

Ngu

`4/6+7/13+17/9+19/13+1/9+14/6`

`=(4/6+14/6)+(7/13+19/13)+(17/9+1/9)`

`=18/6+26/13+18/9`

`=3+2+2`

`=7`

a,  

\(\frac{14}{6}+\frac{1}{9}+\frac{19}{13}+\frac{17}{9}+\frac{7}{13}+\frac{4}{6}\)

\(=\left(\frac{14}{6}+\frac{4}{6}\right)+\left(\frac{1}{9}+\frac{17}{9}\right)+\left(\frac{19}{13}+\frac{7}{13}\right)\)

\(=\frac{18}{6}+\frac{18}{9}+\frac{26}{13}\)

  \(=3+2+2\)

\(=7\)

b,

\(\frac{995}{997}x\frac{990}{993}x\frac{997}{990}x\frac{993}{995}x\frac{97}{95}\)

\(=\frac{995x990x997x993x97}{997x993x990x995x95}\)
\(=\frac{97}{95}\)

(Cùng triệt tiêu 995 ; 990 ; 997 ; 993 )

a) \(\dfrac{3}{8}+\dfrac{7}{12}+\dfrac{10}{16}+\dfrac{10}{24}\)

\(=\dfrac{3}{8}+\dfrac{7}{12}+\dfrac{5}{8}+\dfrac{5}{12}\)

\(=\left(\dfrac{3}{8}+\dfrac{5}{8}\right)+\left(\dfrac{7}{12}+\dfrac{5}{12}\right)\)

\(=1+1\)

\(=2\)

b) \(\dfrac{4}{6}+\dfrac{7}{13}+\dfrac{17}{9}+\dfrac{19}{13}+\dfrac{1}{9}+\dfrac{14}{6}\)

\(=\dfrac{2}{3}+\dfrac{7}{13}+\dfrac{17}{9}+\dfrac{19}{13}+\dfrac{1}{9}+\dfrac{7}{3}\)

\(=\left(\dfrac{2}{3}+\dfrac{7}{3}\right)+\left(\dfrac{7}{13}+\dfrac{19}{13}\right)+\left(\dfrac{17}{9}+\dfrac{1}{9}\right)\)

\(=3+2+2\)

\(=7\)

c) \(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}\)

\(=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+\dfrac{1}{6\cdot7}\)

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}\)

\(=1-\dfrac{1}{7}\)

\(=\dfrac{6}{7}\)