a,  \((\frac{3}{7}-\frac{2}{3})\)  .x  =\(\frac{10}{21}\)                                                                   

  \(\frac{-5}{21}\).x=\(\frac{10}{21}\)

x= -2

 Mk chỉ làm 1 phần  các phằn còn lại tương tự

Bài rút gọn biểu thức

a) M=|2x-3|+|x-1| với x > 1,5

b) N=|2-x|-3|x+1| với x < -1

c) P=|3x-5|+|x-2|

d) Q=|x-3|-2.|-5x|

a, \(\frac{3}{7}x-\frac{2}{3}x=\frac{10}{21}\Rightarrow\left(\frac{3}{7}-\frac{2}{3}\right)x=\frac{10}{21}\Rightarrow x=\frac{10}{21}.\left(\frac{-21}{5}\right)\Rightarrow x=-2\)

b, \(\frac{7}{35}:\left(x-\frac{1}{3}\right)=\frac{2}{25}\Rightarrow x-\frac{1}{3}=\frac{1}{5}:\frac{2}{25}\Rightarrow x=\frac{1}{10}-\frac{1}{3}=\frac{13}{30}\)

c, \(|2x-4|+1=5\)

\(\Rightarrow\orbr{\begin{cases}2x-4=4\\2x-4=-4\end{cases}}\Rightarrow\orbr{\begin{cases}x=4\\x=0\end{cases}}\)

d, \(3.|3-2x|-1=\frac{2}{5}\)

\(\Rightarrow3.|3-2x|=\frac{7}{5}\)

\(\Rightarrow\orbr{\begin{cases}3-2x=\frac{7}{15}\\3-2x=-\frac{7}{15}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{19}{15}\\x=\frac{26}{15}\end{cases}}\)

f, \(\left(2x-1\right).\left(x+\frac{2}{3}\right)=0\)

\(\Rightarrow\hept{\begin{cases}2x-1=0\\x+\frac{2}{3}=0\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{1}{2}\\x=-\frac{2}{3}\end{cases}}\)

a) x+2x+3x+4x+...+2011x = 2012.2013

\(\Rightarrow\) x(1+2+3+4+...+2011) = 4050156

\(\Rightarrow\) x.2023066 = 4050156

\(\Rightarrow\) x = 4026/2011

Câu a ko nhất thiết phải tính ra số lớn như thế đâu

a: |2x+3|=x+2

\(\Leftrightarrow\left\{{}\begin{matrix}x>=-2\\\left(2x+3+x+2\right)\left(2x+3-x-2\right)=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x>=-2\\\left(3x+5\right)\left(x+1\right)=0\end{matrix}\right.\)

hay x=-1

d: \(\left(x-5\right)^{x+11}=\left(x-5\right)^{x+1}\)

\(\Leftrightarrow\left(x-5\right)\left(x-4\right)\left(x-6\right)=0\)

hay \(x\in\left\{5;4;6\right\}\)

e: =>|x-2010|=2010

=>x-2010=2010 hoặc x-2010=-2010

=>x=4020 hoặc x=0

b: \(\Leftrightarrow4x+13=5\)

hay x=-2

a) 2x(3x+1) – (2x+3)(3x-2) = 12

\(\Leftrightarrow6x^2+2x-\left(6x^2-4x+9x-6\right)=12\)

\(\Leftrightarrow6x^2+2x-6x^2+4x-9x+6=12\)

\(\Leftrightarrow-3x+6=12\) 

\(\Leftrightarrow-3x=6\)  

\(\Leftrightarrow x=-2\)  

vậy x = -2

 b)  (x+2)² – (x-3)(x+3) = 5

\(\Leftrightarrow\left(x+2\right)^2-\left(x^2-9\right)=5\)

\(\Leftrightarrow x^2+4x+4-x^2+9-5=0\)  

\(\Leftrightarrow4x+8=0\)

\(\Leftrightarrow4x=-8\) 

\(\Leftrightarrow x=-2\)

Vậy  x = -2

a) \(12\left(x-5\right)=7x-5\)

    \(12x-60=7x-5\)

    \(12x-7x=60-5\)   

     \(5x=55\)

     \(x=11\)

a, 12(x-5)=7x-5

suy ra 12x-60-7x+5=0

suy ra 5x-55=0

suy ra x=55/5=11

vay x=11

b, ta có 5+2!3x-1/2!=6

suy ra 2!3x-1/2!=6-5=1

suy ra !3x-1/2!=1/2

xet th1: 3x-1/2=1/2

suy ra x=1/3

xet th2 3x-1/2=-1/2

suy ra x=0

vạy x=0 hoac x=1/3

c, (2x-3)^2010=(2x-3)^2012

xet th1 2x-3=1  suy ra x=2

xet th2 2x-*3=0  suy ra x=3/2

vạy x=2 hoac x=3/2