( 2014 x 2015 - 2016 ) : ( 2012 + 2013 x 2014 )

= ( 4058210 - 2016 ) : ( 2012 + 4054182 )

= 4056194 : 4056194

= 1

﴾ 2014 x 2015 ‐ 2016 ﴿ : ﴾ 2012 + 2013 x 2014 ﴿

= ﴾ 4058210 ‐ 2016 ﴿ : ﴾ 2012 + 4054182 ﴿

= 4056194 : 4056194

= 1

 ( 2014 x 2015 - 2016 ) : (2012 + 2013 x 2014 )

= ( 2014 x ( 2013 + 2 ) - 2016 ) : ( 2012 + 2013 x 2014 )

= ( 2014 x 2013 + 2014 x 2 - 2016 ) : ( 2012 + 2013 x 2014 )

= ( 2014 x 2 - 2016 ) : 2012

=  ( 4028 - 2016 ) : 2012 

=      2012       : 2012

= 1 

2016 x 72 + 2016 x 29 – 2016

=(2016-2016) x (72 + 29) 

=  0  x  101=0

\(2016\times72+2016\times29-2016=2016\times72+2016\times29-2016\times1=2016\times\left(72+29-1\right)=2016\times10=201600\)

2016 x 72 + 2016 x 29 - 2016

= 2016 x (72 + 29 - 1)

= 2016 x 100

= 201600

a, \(13\) \(\times\) 15 - 150 + 97 \(\times\) 15

= 15 \(\times\) ( 13 - 10 + 97)

= 15 \(\times\) ( 3 + 97)

= 15 \(\times\) 100

= 1500  

b, \(\dfrac{2016}{2015}\) \(\times\) \(\dfrac{4}{7}\) - \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2015}\) + \(\dfrac{3}{7}\)

= \(\dfrac{4}{7}\) \(\times\) ( \(\dfrac{2016}{2015}\) - \(\dfrac{1}{2015}\)) + \(\dfrac{3}{7}\)

= \(\dfrac{4}{7}\) \(\times\) \(\dfrac{2015}{2015}\) + \(\dfrac{3}{7}\)

= \(\dfrac{4}{7}\) + \(\dfrac{3}{7}\)

= \(\dfrac{7}{7}\)

= 1

a, 13 \(\times\) 15 - 150 + 97 \(\times\)15

13 \(\times\) 15 - 15 \(\times\) 10 + 97 \(\times\) 15

= 15 \(\times\) ( 13 - 10 + 97)

= 15 \(\times\) ( 3 + 97)

= 15 \(\times\) 100

=1500   

b, \(\dfrac{2016}{2015}\) \(\times\) \(\dfrac{4}{7}\) - \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2015}\) + \(\dfrac{3}{7}\)

= \(\dfrac{4}{7}\) \(\times\) ( \(\dfrac{2016}{2015}\) - \(\dfrac{1}{2015}\)) + \(\dfrac{3}{7}\) 

= \(\dfrac{4}{7}\) \(\times\) \(\dfrac{2015}{2015}\) + \(\dfrac{3}{7}\)

= \(\dfrac{4}{7}\) + \(\dfrac{3}{7}\)

= \(\dfrac{7}{7}\)

= 1

( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x ( 1 + 1/3 - 4/3)

=( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x ( 4/3 - 4/3)

=( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x 0

=0

Ta có: \(\left(2013\cdot2014+2014\cdot2015+2015\cdot2016\right)\left(1+\dfrac{1}{3}-\dfrac{4}{3}\right)\)

\(=\left(2013\cdot2014+2014\cdot2015+2015\cdot2016\right)\left(\dfrac{3}{3}+\dfrac{1}{3}-\dfrac{4}{3}\right)\)

=0

2016(34+63+2+1)=2016*100=201600

= 2016 x (34 + 63 +2 +1) =2016 x 100 =201600

d) 0

 2014 x 2016 + 2017

=4060224+2017

=4062241

2016 x 2016 - 2016 x 2016

= 2016 x (2016 - 2016)

= 2016 x 0

= 0

Bài 2 . Cô giáo phát cho số em là :

  21 : 3 = 7 ( em )

Đáp số : 7 em

bằng 0

dễ ẹt mà cũng hỏi

nhớ k cho minh nha !

cho 7 em