C=2/4×7-3/5×9+2/7×10-3/9×13+...+2/301×304-3/401×405
Những câu hỏi liên quan
Tính
A=1/2×9+1/9×7+1/7×19+...+1/252×509
B=1/10×9+1/18×13+1/26×17+...+1/802×405
C=2/4×7-3/5×9+2/7×10-3/9×13+...+2/301×304-3/401×405
B = \(\frac{1}{10.9}+\frac{1}{18.13}+\frac{1}{26.17}+...+\frac{1}{802.405}\)
B = \(\frac{2}{10.18}+\frac{2}{18.26}+\frac{2}{26.34}+...+\frac{2}{802.810}\)
B = \(\frac{1}{4}.\left(\frac{1}{10}-\frac{1}{18}+\frac{1}{18}-\frac{1}{26}+\frac{1}{26}-\frac{1}{34}+...+\frac{1}{802}-\frac{1}{810}\right)\)
B = \(\frac{1}{4}.\left(\frac{1}{10}-\frac{1}{810}\right)=\frac{1}{4}.\frac{8}{81}\)
B = \(\frac{2}{81}\)
Đúng 0
Bình luận (0)
Bài 1;tính
A=1/2*9+1/9*7+1/7*19+....+1/252*509
B=1/10*9+1/18*13+/26*17+....+1/802*405
C=2/4*7-3/5*9+2/7*10-3/9*13+...+2/301*304-3/401*405
Bài 2
Cho S=1/5^2+1/9^2+...+1/409^2
Chứng minh S<1/12
4S = 4/(5x5) + 4/(9x9) + … + 1/(409x409)
Ta thấy:
4/(5x5) < 4/(3x7) = 1/3 – 1/7
4/(9x9) < 4/(7x11) = 1/7 – 1/11
…………
4/(409x409) < 4/(407x411) = 1/407 – 1/411
Mà :
4/(3x7) + 4/(7x11) + …. + 4/(407x411) = 1/3 – 1/411 = 136/411
4S < 136/411
S < 34/411 < 34/408 = 1/12
Hay S < 1/12
Đúng 0
Bình luận (0)
1+2-3-4+5+6-7-8+9+10...+401+402-403-404+405+406
1 +2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + ....... + 402 - 403 - 404 + 405 + 406
= 406 + ( 405 - 404 - 403 + 402 ) + ( 401 - 400 - 399 + 398 ) + ......... + ( 5 - 4 - 3 + 2 ) + 1
= 406 + 0 + 0 + ....... + 0 + 1
=407
Đúng 0
Bình luận (0)
1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + ....... + 402 - 403 - 404 + 405 + 406
= 406 + ( 405 - 404 - 403 + 402 ) + ( 401 - 400 - 399 + 398 ) + ......... + ( 5 - 4 - 3 + 2 ) + 1
= 406 + 0 + 0 + ....... + 0 + 1
= 407
ko biết đúng hay sai
nếu đúng thì nha
Đúng 0
Bình luận (0)
A=1+2-3-4+5+6-7-8+9+10...+401+402-403-404+405+406
1) Thuc hien phep tinh:
a) 4^6 × 9^2 / 6^3 × 8^2
b) 5^6 × 15^4 /5^4 × 3^3
c) 3^9 - 2^3 × 3^7 + 2^10 × 3^2 - 2^13 / 3^10 - 2^2 × 3^7 + 2^10 × 3^3 - 2^12
d) (1/9)^10 : (1/3)^20
e) (1/64)^5 × (1/4)^7
2) Chung minh rang:
a)2014^100+2014^99 chia het cho 2015
b) 4^13+32^5-8^8 chia het cho 5
c) 81^27-27^9-9^13 chia het cho 405
Help me!! Pleass!!
R = 1/10*9 + 1/ 18*13 +....+ 1/ 802 * 405
S = 2/4*7 - 3/5*9 + 2/7*10 - 3/9*13
Ráng giúp mk nha mk dg cần gấp !!!
\(S=\dfrac{2}{4\cdot7}+\dfrac{2}{7\cdot10}-\dfrac{3}{5\cdot9}-\dfrac{3}{9\cdot13}\)
\(=\dfrac{2}{3}\left(\dfrac{3}{4\cdot7}+\dfrac{3}{7\cdot10}\right)-\dfrac{3}{4}\left(\dfrac{4}{5\cdot9}+\dfrac{4}{9\cdot13}\right)\)
\(=\dfrac{2}{3}\left(\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}\right)-\dfrac{3}{4}\cdot\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{13}\right)\)
\(=\dfrac{2}{5}\cdot\dfrac{3}{20}-\dfrac{3}{4}\cdot\dfrac{8}{65}=\dfrac{-21}{650}\)
Đúng 0
Bình luận (0)
\(\frac{2}{4\cdot7}-\frac{2}{5\cdot9}+\frac{2}{7\cdot10}-\frac{2}{9\cdot13}+\frac{2}{10\cdot13}-\frac{2}{13\cdot17}+...+\frac{2}{301\cdot304}-\frac{2}{401\cdot405}CM:tich,tren,< \frac{1}{15}\)
1+2-3-4+5+6-7-8+9+10-11-12+13+14-...-299-300+301+302 =?
Đặt biểu thức trên là A
A=(1-3)+(2-4)+(5-7)+(6-8)+.....+(297-299)+(298-300)+301+302
A=301+302-(3-1)-(4-2)-(7-5)-(8-6)-......-(299-297)-(300-298)
------------------------------------------------------------------
có 150 số hạng
A=301+302-(2+2+2+2+..........+2)
------------------------------
50 số hạng
A=301+302-2x150=303
Đúng 0
Bình luận (0)
1+2-3-4+5+6-7-8+9+10-11-12+13+14-15-16+...+301+302
1+2-3-4+5+6-...+301+302
đặt A=(1+2)+(5+6)+...+(301+302)=3+11+19+...+603
A=[(603-3):8+1]x(603+3)=75x606=45450
đặt B=-3-4-7-8-11-13-...-299-300
B=(-3-4)+(-7-8)+(-11-12)+..+(-299-300)
B=-(7+15+23+...+599)
B=-[(599-7):8+1]x(599+7)=45450
ta có:
1+2-3-4+5+6-7-8+...+301+302=A-B=45450-45450=0
Đúng 0
Bình luận (0)