Tính nhanh:
1 x \(\frac{1}{15}\)x 1\(\frac{1}{16}\)x \(1\frac{1}{17}\)x........x \(1\frac{1}{2016}\)x \(1\frac{1}{2017}\)
Tính nhanh giúp mình nha!
phân tích, tính
A=(1-\(\frac{1}{2016}\))x(1-\(\frac{2}{2016}\))x....x(1-\(\frac{2017}{2016}\))
Các bạn giúp mình nha! Nhanh giùm mình nghen....mình tik cho:))
Bạn chú ý trong tích A có chứa thừa số \(1-\frac{2016}{2016}=1-1=0\)
Vì tích có 1 thừa số bằng 0 nên cả tích sẽ bằng 0
Vậy A=0
Bạn ghi rõ ra đc ko?
(ví dụ: 2x3+5=6+5=11)
a)\(\frac{x+1}{5}+\frac{x+1}{6}+\frac{x+1}{7}=\frac{x+1}{8}+\frac{x+1}{9}\)
b)\(\frac{x+6}{2015}+\frac{x+5}{2016}+\frac{x+4}{2017}=\frac{x+3}{2018}+\frac{x+2}{2019}+\frac{x+1}{2010}\)
c)\(\frac{x+6}{2016}+\frac{x+7}{2017}+\frac{x+8}{2018}=\frac{x+9}{2019}+\frac{x+10}{2020}+1\)
d)\(\frac{x-90}{10}+\frac{x-76}{12}+\frac{x-58}{14}+\frac{x-36}{16}+\frac{x-15}{17}=15\)
ai xong nhanh nhất và đúng em xin gửi 2 SP ạ
a) \(\frac{x+1}{5}+\frac{x+1}{6}+\frac{x+1}{7}=\frac{x+1}{8}+\frac{x+1}{9}\)
\(\Leftrightarrow\frac{x+1}{5}+\frac{x+1}{6}+\frac{x+1}{7}-\frac{x+1}{8}-\frac{x+1}{9}=0\)
\(\Leftrightarrow\left(x+1\right).\left(\frac{1}{5}+\frac{1}{6}+\frac{1}{7}-\frac{1}{8}-\frac{1}{9}\right)=0\)
\(\Leftrightarrow x+1=0\)
\(\Leftrightarrow x=0-1\)
\(\Rightarrow x=-1\)
Vậy \(x=-1.\)
Mình chỉ làm câu a) thôi nhé.
Chúc bạn học tốt!
Lê Thị Thục HiềnTrần Thanh PhươngVũ Minh Tuấn?Amanda?Nguyễn Việt LâmHISINOMA KINIMADONguyễn Huy TúAkai Haruma
tính nhanh \(\left(1+\frac{1}{2}\right)x\left(1+\frac{2}{3}\right)x\left(1+\frac{3}{4}\right)x.....x\left(1+\frac{1}{2017}\right)\)
giúp mik giải nha, nhớ là tín nhanh đó
Hình như đề bạn ghi sai rồi, nó ko theo thứ tự để tính nhanh
thế thì hợp lý nha bn
1 x \(\frac{1}{15}\) x 1\(\frac{1}{16}\) x 1\(\frac{1}{17}\) x............x 1\(\frac{1}{2016}\) x 1\(\frac{1}{2017}\)
Ta có: \(1\times\frac{1}{15}\times1\frac{1}{16}\times1\frac{1}{17}\times......\times1\frac{1}{2016}\times1\frac{1}{2017}\)
\(=\frac{1}{15}\times\frac{17}{16}\times\frac{18}{17}\times......\times\frac{2017}{2016}\times\frac{2018}{2017}\)
\(=\frac{1}{15}\times\frac{2018}{16}\)
\(=\frac{1009}{8\times15}\)
\(=\frac{1009}{120}\)
Mình nghĩ đề bài của bạn bị nhầm ở chỗ \(1\frac{1}{15}\)thành \(1\times\frac{1}{15}\)
Nhưng không sao bạn ạ
Vẫn giải được
\(1\frac{1}{15}\times1\frac{1}{16}\times.....\times1\frac{1}{2017}\)(lỗi đề sao bạn)
\(=\frac{16}{15}\times\frac{17}{16}\times.....\times\frac{2018}{2017}\)
\(=\frac{16\times17\times.....\times2018}{15\times16\times.....\times2017}\)
\(=\frac{2018}{15}\)
\(1\frac{1}{15}\)x \(1\frac{1}{16}\)x \(1\frac{1}{17}\)x .......... x \(1\frac{1}{2016}\)x \(1\frac{1}{2017}\)
\(1\frac{1}{15}\cdot1\frac{1}{16}\cdot1\frac{1}{17}\cdot...\cdot1\frac{1}{2016}\cdot1\frac{1}{2017}\)
\(=\frac{16^{\left(1\right)}}{15}\cdot\frac{17^{\left(1\right)}}{16^{\left(1\right)}}\cdot\frac{18^{\left(1\right)}}{17^{\left(1\right)}}\cdot...\cdot\frac{2017^{\left(1\right)}}{2016^{\left(1\right)}}\cdot\frac{2018}{2017^{\left(1\right)}}\)
\(=\frac{1}{15}\cdot2018\)
\(=\frac{2018}{15}=134\frac{8}{15}\)
BÀI 1 : Tính nhanh : \(1\frac{1}{3}\)x \(1\frac{1}{8}\)x \(1\frac{1}{15}\)x ..... ( có 98 thừa số )
BÀI 2 : Tính : \(\frac{1}{24}\)+\(\frac{1}{48}\)+ .... + \(\frac{1}{39600}\)
BÀI 3 : Tính : Cho hai phân số : A = \(\frac{201620162016}{201720172017}\)và B = \(\frac{2016}{2017}\). Hãy so sánh A và B.
GIÚP MÌNH VỚI MÌNH SẼ TICK VÀ KẾT BẠN !! ^-^
Bai3
201620162016/201720172017=2016.100010001/2017.100010002=2016/2017
Vay 201620162016/201720172017=2016/2017
bài 1 kobik
bài 2\(\frac{1}{39600}\):\(\frac{1}{4}\)=\(\frac{2}{33}\)
bài 3\(\frac{201620162016}{201720172017}=\frac{2016}{2017}\)
nên mó bằng nhau
1/Tính nhanh
P=(1-\(\frac{1}{2^2}\)) x (1-\(\frac{1}{3^2}\)) x (1-\(\frac{1}{4^2}\)) x ... x (1-\(\frac{1}{50^2}\))
2/Cho Q=(1-\(\frac{1}{2^2}\)) x (1-\(\frac{1}{3^2}\)) x (1-\(\frac{1}{4^2}\)) x ... x (1-\(\frac{1}{40^2}\)) . So sánh Q với \(\frac{1}{2}\)
3/So sánh: A = \(\frac{2016^{2016}+1}{2016^{2017}+1}\)và B = \(\frac{2016^{2017}-3}{2016^{2018}-3}\)
P \(=\left(1-\frac{1}{2^2}\right).\left(1-\frac{1}{3^2}\right).\left(1-\frac{1}{4^2}\right)...\left(1-\frac{1}{50^2}\right)\)
P\(=\frac{2^2-1}{2^2}.\frac{3^2-1}{3^2}.\frac{4^2-1}{4^2}...\frac{50^2-1}{50^2}\)
P \(=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}...\frac{49.51}{50.50}\)
P\(=\frac{\left(1.2.3...49\right).\left(3.4.5...51\right)}{\left(2.3.4...50\right).\left(2.3.4...50\right)}\)
P\(=\frac{1.51}{50.2}=\frac{51}{100}\)
1. Tính nhanh:
A= (\(1-\frac{1}{9}\))x(\(1-\frac{1}{16}\))x(\(1-\frac{1}{25}\)) ..... (\(1-\frac{1}{361}\))x(\(1-\frac{1}{400}\))
B= (\(1+\frac{1}{8}\))x(\(1+\frac{1}{15}\))x(\(1+\frac{1}{24}\)) ... (\(1+\frac{1}{440}\))x(\(1+\frac{1}{483}\))
C= \(\frac{17}{23}x\frac{7}{61}+\frac{17}{23}x\frac{28}{61}+\frac{17}{23}x\frac{26}{61}\)
\(A=\frac{8}{9}\cdot\frac{15}{16}\cdot\frac{24}{25}\cdot...\cdot\frac{360}{361}\cdot\frac{399}{400}\)
\(A=\frac{2\cdot4\cdot3\cdot5\cdot4\cdot6\cdot...\cdot18\cdot20\cdot19\cdot21}{3\cdot3\cdot4\cdot4\cdot5\cdot5\cdot...\cdot19\cdot19\cdot20\cdot20}\)
\(A=\frac{2\cdot21}{3\cdot20}\)
\(A=\frac{7}{10}\)
\(B=\frac{9}{8}\cdot\frac{16}{15}\cdot\frac{25}{24}\cdot...\cdot\frac{441}{440}\cdot\frac{484}{483}\)
\(B=\frac{3\cdot3\cdot4\cdot4\cdot5\cdot5\cdot...\cdot21\cdot21\cdot22\cdot22}{2\cdot4\cdot3\cdot5\cdot4\cdot6\cdot...\cdot20\cdot22\cdot21\cdot23}\)
\(B=\frac{3\cdot22}{2\cdot23}=\frac{33}{23}\)
\(C=\frac{17}{23}.\left(\frac{7}{61}+\frac{28}{61}+\frac{26}{61}\right)\)
\(C=\frac{17}{23}\cdot1=\frac{17}{23}\)
Tính nhanh :
\(\frac{1}{1}x\frac{1}{2}+\frac{1}{2}x\frac{1}{3}+\frac{1}{3}x\frac{1}{4}+\frac{1}{4}x\frac{1}{5}+\frac{1}{5}x\frac{1}{6}\)
Giúp mình với nha <3 Chiều mai mình đi học rồi
\(\frac{1}{1}.\frac{1}{2}+\frac{1}{2}.\frac{1}{3}+\frac{1}{3}.\frac{1}{4}+\frac{1}{4}.\frac{1}{5}+\frac{1}{5}.\frac{1}{6}=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=1-\frac{1}{6}=\frac{5}{6}\)
\(\frac{1}{1}.\frac{1}{2}+\frac{1}{2}.\frac{1}{3}+\frac{1}{3}.\frac{3}{4}+\frac{1}{4}.\frac{1}{5}+\frac{1}{5}.\frac{1}{6}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=\frac{1}{1}-\frac{1}{6}\)
\(=\frac{5}{6}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+........+\frac{1}{5.6}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...........+\frac{1}{5}-\frac{1}{6}\)
\(=1-\frac{1}{6}\)
\(=\frac{5}{6}\)