2/3;5/6;11/12;7/6;3/2;7/4;11/3

0,15;4/10;1,2;2,5;3

Theo thứ tự tăng dần:

0,15 ; 4/10 ; 1,2 ; 2,5 ; 3

4/10 ; 0,15 ; 1,2 ; 2,5; 3,4

+L_I_K_E+_+

-9,-|-5|,-|-3|,0,-(-4),7

-9 ; -|-5| ; -|3| ; |0 ; -(-4) ; 7

sắp sếp theo thứ tự tăng dần là:

-9 < -/-5/ < -/3/ < 0 < -(-4) < 7

tick nha

\(\frac{9}{10}>\frac{8}{9}>\frac{7}{8}>\frac{6}{7}>\frac{5}{6}>\frac{4}{5}>\frac{3}{4}>\frac{2}{3}>\frac{1}{2}.\)

9/10;8/9;7/8;6/7;5/6;4/5;3/4;2/3;1/2

\(\dfrac{-5}{7}=\dfrac{-5\cdot19}{7\cdot19}=\dfrac{-95}{133}\)

\(\dfrac{-16}{19}=\dfrac{-16\cdot7}{19\cdot7}=\dfrac{-112}{133}\)

mà -95>-112

nên \(-\dfrac{16}{19}< -\dfrac{5}{7}\)(1)

\(-\dfrac{5}{7}< 0\)

\(0< \dfrac{214}{315}\)

Do đó: \(-\dfrac{5}{7}< \dfrac{214}{315}\left(3\right)\)

\(\dfrac{214}{315}< \dfrac{220.5}{315}=\dfrac{7}{10}\)(2)

\(\dfrac{7}{10}=1-\dfrac{3}{10}\)

\(\dfrac{20}{23}=1-\dfrac{3}{23}\)

ta có: \(\dfrac{3}{10}>\dfrac{3}{23}\)

=>\(-\dfrac{3}{10}< -\dfrac{3}{23}\)

=>\(-\dfrac{3}{10}+1< -\dfrac{3}{23}+1\)

=>\(\dfrac{7}{10}< \dfrac{20}{23}\)(4)

\(\dfrac{20}{23}< 1\)

\(1< \dfrac{205}{107}\)

DO đó: \(\dfrac{20}{23}< \dfrac{205}{107}\)(5)

Từ (1),(2),(3),(4),(5) suy ra \(\dfrac{-16}{19}< -\dfrac{5}{7}< \dfrac{214}{315}< \dfrac{7}{10}< \dfrac{20}{23}< \dfrac{205}{107}\)