Đề như vậy đúng ko bn ?

\(2x^2-7.x.10\)

\(=2x^2-70x\)

\(=2x\left(x-35\right)\)

Phân tích thành nhân tử :.:

\(2x^2-7x10\)

\(=2x^2-70x\)

\(=2x\left(x^2-35\right)\)

Chúc bạn nhớ tốt  cách phân tích :)

Đúng rồi Uyên Trần

= 10² * x² - 1

= 100 * x² -1 

\(10x^2-1=\left(\sqrt{10}x-1\right)\left(\sqrt{10}x+1\right)\)

\(\left(10x\right)^2-1=\left(10x-1\right)\left(10x+1\right)\)

(4a⁴-12a²+1)=(4a⁴-8a²+1)-4a²=(2a²-1)²-4a²=(2a²-2a-1)(2a²+2a-1)

\(9a^2-6ab+b^2-1=\left(3a-b\right)^2-1^2=\left(3a-b-1\right)\left(3a-b+1\right)\)

9a^2 - 6ab + b^2 - 1= (3a)^2 - 2.3a.b + b^2 -1

                            = (3a - b)^2 - 1^2

                            = (3a - b - 1).(3a - b + 1)

  9a² - 6ab + b² - 1 = (3a - b)² - 1

                                   =  (3a - b + 1)(3a-b-1)

\((4x-y)(a+b)(4x-y)(c-1)\)

\(=\left(4x-y\right)\left(4x-y\right)=\left(4x-y\right)^{1+1}=\left(4y-2\right)^2\)

\(=\left(a+b\right)\left(4x-y\right)^2\left(c-1\right)\)

(4x-y)(a+b)(4x-y)(c-1)

= ( 4x - y ) ( 4x - y ) = ( 4x - y ) ^{1 + 1} = ( 4y - 2 ) ²

= (a + b ) ( 4x - y )²  ( c - 1 )

Bài giải : 

(4x-y)(a+b)(4x-y)(c-1)

= ( 4x - y ) ( 4x - y ) = ( 4x - y ) ^{1 + 1} 

= ( 4y - 2 ) ²

= (a + b ) ( 4x - y )²  ( c - 1 )

 4x^4 - 32x^2 +1 = 4x^4 + 4x^2 +1 - 36x^2 = (2x^2 + 1)^2 - 36x^2 = (2x^2 - 6x + 1)(2x^2 + 6x + 1) 

4 x⁴ - 32 x² + 1 

= ( 2 x² )² - 2 . 2x². 8 + 64 - 63 

= ( 2 x² - 8 )² - 63 

= ( 2x² - 8 + √63 ) ( 2x² - 8 - √63 )

Xong

\(3x-7\sqrt{x}+4=3x-4\sqrt{x}-3\sqrt{x}+4=\sqrt{x}\left(3\sqrt{x}-4\right)-\left(3\sqrt{x}-4\right)=\left(3\sqrt{x}-4\right)\left(\sqrt{x}-1\right)\)

\(3x-7\sqrt{x}+4=3x-3\sqrt{x}-4\sqrt{x}+4\)

\(=3\sqrt{x}\left(\sqrt{x}-1\right)-4\left(\sqrt{x}-1\right)\)

\(=\left(3\sqrt{x}-4\right)\cdot\left(\sqrt{x}-1\right)\)

\(3x-7\sqrt{x}+4=3x-3\sqrt{x}-4\sqrt{x}+4=3.\left(\sqrt{x}\right)^2-3\sqrt{x}-4\sqrt{x}+4=3\sqrt{x}\left(\sqrt{x}-1\right)-4\left(\sqrt{x}-1\right)=\left(3\sqrt{x}-4\right)\left(\sqrt{x}-1\right)\)

\(x+\sqrt{x}-12=\left(\sqrt{x}+4\right)\left(\sqrt{x}-3\right)\)