1: x=3/4-1/2=3/4-2/4=1/4

2: x-1/5=2/11

=>x=2/11+1/5=21/55

3: x-5/6=16/42-8/56

=>x-5/6=8/21-4/28=5/21

=>x=5/21+5/6=15/14

4: x/5=5/6-19/30

=>x/5=25/30-19/30=6/30=1/5

=>x=1

5: =>|x|=1/3+1/4=7/12

=>x=7/12 hoặc x=-7/12

6: x=-1/2+3/4

=>x=3/4-1/2=1/4

11: x-(-6/12)=9/48

=>x+1/2=3/16

=>x=3/16-1/2=-5/16

1)x= 1/4

2)x= 2/11+ 1/5

   x= 21/55

3)x - 5/6 = 5/21

   x         = 5/21+5/6

   x         = 15/14

4)x/5 = 5/6 + -19/30

   x:5 = 1/5

   x    = 1/5.5

   x    = 1

5) |x| - 1/4 = 6/18

    |x|           = 6/18 - 1/4

    |x|            =7/12

⇒x= 7/12 hoặc -7/12

6)x = -1/2 +3/4

   x= 1/4

7) x/15 = 3/5 + -2/3

   x:15  = -1/15

  x        = -1/15. 15

  x        = -1

8)11/8 + 13/6 = 85/x  

       85/24      = 85/x

  ⇒      x           = 24

9) x - 7/8 = 13/12

   x          = 13/12 + 7/8

   x          = 47/24

10)x - -6/15 = 4/27  

     x            = 4/27 + (-6/15)

    x             = -34/135

11) -(-6/12)+x = 9/48

                    x= 9/48 - 6/12

                    x = -5/16

12) x - 4/6 = 5/25 + -7/15

      x -4/6  =  -4/15

     x           = -4/15 + 4/6

    x             = 2/5

a)\(\frac{x}{5}=\frac{2}{5}\)

\(\Leftrightarrow x=\frac{2\times5}{5}=2\)

Vậy .............

b) \(\frac{3}{8}=\frac{6}{x}\)

\(\Leftrightarrow x=\frac{8\times6}{3}=16\)

Vậy ................

c) \(\frac{1}{9}=\frac{x}{27}\)

\(\Leftrightarrow x=\frac{1\times27}{9}=3\)

Vậy ................

d) \(\frac{4}{x}=\frac{8}{6}\)

\(\Leftrightarrow x=\frac{4\times6}{8}=3\)

Vậy ............

e) \(\frac{3}{x-5}=\frac{-4}{x+2}\)

\(\Leftrightarrow3\left(x+2\right)=-4\left(x-5\right)\)

\(\Leftrightarrow3x+6=-4x+20\)

\(\Leftrightarrow3x+4x=20-6\)

\(\Leftrightarrow7x=14\)

\(\Leftrightarrow x=2\)

Vậy .............

f) \(\frac{x}{-2}=\frac{-8}{x}\)

\(\Leftrightarrow x^2=16\)

\(\Leftrightarrow x=\pm4\)

Vậy ...............

\(\frac{x}{5}=\frac{2}{5}\Rightarrow x=\frac{2\times5}{5}=2\)

\(\frac{1}{9}=\frac{x}{27}\Rightarrow x=\frac{1\times27}{9}=3\)

\(\frac{4}{x}=\frac{8}{6}\Rightarrow x=\frac{8\times6}{8}=6\)

\(\frac{3}{x-5}=\frac{-4}{x+2}\)

\(\Rightarrow3.\left(x+2\right)=-4.\left(x-5\right)\)

\(\Rightarrow3x+6=-4x+20\)

\(\Rightarrow3x+4x=20-6\)

\(\Rightarrow7x=14\)

\(\Rightarrow x=2\)

câu đầu bn suy ra x = 2 luôn nha, viết lại đề suy ra luôn

Trả lời :

\(\left(\frac{4}{9}\right)^{x+1}=\left(\frac{8}{27}\right)^6\)

\(\Rightarrow\left[\left(\frac{2}{3}\right)^2\right]^{x+1}=\left[\left(\frac{2}{3}\right)^3\right]^6\)

\(\Rightarrow\left(\frac{2}{3}\right)^{2x+2}=\left(\frac{2}{3}\right)^{18}\)

\(\Rightarrow2x+2=18\)

\(\Rightarrow2x=16\)

\(\Rightarrow x=8\)

\(\left(\frac{4}{9}\right)^{x+1}=\left(\frac{8}{27}\right)^6=>\left[\left(\frac{2}{3}\right)^2\right]^{x+1}=\left[\left(\frac{2}{3}\right)^3\right]^6\)

\(\left(\frac{2}{3}\right)^{2.\left(x+1\right)}=\left(\frac{2}{3}\right)^{18}=>2.\left(x+1\right)=18\)

\(\left(x+1\right)=18:2=>\left(x+1\right)=9\)

\(x=9-1=>x=8\)

vậy \(x=8\)

\(\left(\frac{4}{9}\right)^{x+1}=\left(\frac{8}{27}\right)^6\)

\(\left[\left(\frac{2}{3}\right)^2\right]^{x+1}=\left[\left(\frac{2}{3}\right)^3\right]^6\)

\(\left(\frac{2}{3}\right)^{2x+2}=\left(\frac{2}{3}\right)^{18}\)

\(\Rightarrow2x+2=18\)

\(\Rightarrow2x=16\)

\(\Rightarrow x=16:2\)

\(\Rightarrow x=8\)

Học tốt

a) \(\left(\frac{1}{9}\right)^x=\left(\frac{1}{27}\right)^{22}\)

\(\left[\left(\frac{1}{3}\right)^2\right]^x=\left[\left(\frac{1}{3}\right)^3\right]^{22}\)

\(\left(\frac{1}{3}\right)^{2\cdot x}=\left(\frac{1}{3}\right)^{66}\)

\(\Rightarrow2\cdot x=66\)

\(x=66\div2\)

\(x=33\)
Vậy x = 33
b) \(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)

\(\left[\left(\frac{2}{3}\right)^2\right]^x=\left[\left(\frac{2}{3}^3\right)\right]^6\)

\(\left(\frac{2}{3}\right)^{2\cdot x}=\left(\frac{2}{3}\right)^{18}\)

\(\Rightarrow2\cdot x=18\)

\(x=18\div2\)

\(x=9\)

Vậy x = 9

a,2/5 = 2/5 ; 3/8=6/16 ; 1/9=3/27

b, 4/3=8/6 ; -1=-1 ; -4/-2=-8/4

tick cho mik nhé 

a) x= 2, x= 8.(6 : 3) = 16, x= 1. (27 : 9)= 3

b) x= 6 : (8 : 4) = 3, x= -1, x= -2 . -8 = x.x => 16 = x² => 4² = x² => x=4

        Tick cho mình đi 

a) \(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)

\(\Leftrightarrow\left(\frac{2}{3}\right)^{2x}=\left(\frac{2}{3}\right)^{18}\)

\(\Leftrightarrow2x=18\)

\(\Leftrightarrow x=9\)

b) \(\left(\frac{1}{9}\right)^x=\left(\frac{1}{27}\right)^{22}\)

\(\Leftrightarrow\left(\frac{1}{9}\right)^x=\left(\frac{1}{3}\right)^{66}\)

\(\Leftrightarrow x=66\)

b) \(\left(\frac{1}{9}\right)^x=\left(\frac{1}{27}\right)^{22}\)

\(\left(\frac{1}{3}\right)^{2.x}=\left(\frac{1}{3}\right)^{3.22}\)

\(2x=3.22\)

\(x=33\)

  Bài 1:

2^\(x\) = 4

2\(^x\) = 2²

 \(x=2\)

Vậy \(x=2\)

Bài 2:

2\(^x\) = 8

2\(^x\) = 2³

\(x=3\)

Vậy \(x=3\)

Bài 3

2\(^x\) = 16

2\(^x\) = 2⁴

  \(x=4\)

Vậy \(x=4\)

a)27^5.3^x=9^8

3^15.3^x=3^16

3^x=3^16 : 3^15

3^x = 3^1

=> x=1

b)8^x.64=4^6

8^x.8^2=8^3

8^x=8^3 : 8^2

8^x= 8^1

=> x=1

c)3^3-x=9^x.3^3

3^3-x=3^2.3^x.3^3

3^3-x=3^5.3^x

3 ^3-x= 3^5+x

=> 3-x=5+x

=> x=-1