\(150=5^2\cdot2\cdot3;1000=2^3\cdot5^3\)

=>\(ƯCLN\left(150;1000\right)=5^2\cdot2=50\)

=>\(ƯC\left(150;1000\right)=Ư\left(50\right)=\left\{1;-1;2;-2;5;-5;10;-10;25;-25;50;-50\right\}\)

Ta có:

=>ƯCLN(150;1000)=2.5=10

=>ƯC(150;1000)={1;2;5;10}

Ta có:

150=2.3.5²

1000=2³.5².7

=>ƯCLN(150;1000)=2.5=10

=>ƯC(150;1000)={-1;-2;-5;-10;1;2;5;10}

ta có: 128 = 2⁷

          240= 2⁴.3.5

=>ƯCLN(128,240)=2⁴=16

=>ƯC(128,240)=Ư(16)={1;2;4;8;16}

 vậy ƯC(128,240)={1;2;4;8;16}

tic cho mình nha

\(ƯC\left(128,240\right)\)

\(128=2^7\)

\(240=2^4.3.5\)

\(ƯCLN(128,240) =2^4 = 16\)

\(ƯC\left(128;240\right)=ƯC\left(16\right)=\left\{1;2;4;8;16\right\}\)

bấm máy tính là ra

1.Ta có:

           Ư(10)={1;2;5;10}.

           Ư(20)={1;2;4;5;10;20}.

=>       Ư(10;20)={1;2;5;10}

Cái dấu ^ là gì rồi tôi giải tiếp cho

dấu ^ là dấu mũ trong lũy thừa

ƯCLN={1}

ƯC={1}

\(36=2^2\cdot3^2\\ 120=2^3\cdot3\cdot5\\ ƯCLN\left(36,120\right)=2^2\cdot3=12\\ ƯC\left(36,120\right)=Ư\left(12\right)=\left\{...\right\}\)

Ta có: 36= 2^2. 3^2

         120= 2^3. 3.5

=> ƯCLN( 36; 120)- 2^2. 3= 12

=> ƯC(36;120) = Ư(12) = { 1; 2; 3; 4; 6; 12}

Ta có: 36 = 2² . 3²

           120 = 2³ . 3 . 5

=> ƯCLN (36, 120) = 2² . 3 = 12

ƯC (36, 120) = ƯCLN (36, 120) = Ư₍₁₂₎ = {1 ; 2 ; 3 ; 4 ; 6 ; 12)

=> ƯC (36, 120) = {1 ; 2 ; 3 ; 4 ; 6 ; 12}

Ư(80)={1;80;2;40;4;20;10;8;5;16}

Ư(126)={1;126;2;63;3;19;14}

dễ mà

phân tích đi

80= 2⁴ .5

120= 2³ .3.5

ƯCLN (80,120)= 2³.5= 40

ƯC(80,120)= Ư(40)= 1,2,4,5,8,10,20,40