17. coming 18. iron___ doing 19. wakes 20. buying

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ỉon        doing 

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17. to come    18.iron , doing.  19.wake.  

\(=\left(4+\sqrt{15}\right)\left(\sqrt{5}-\sqrt{3}\right)\sqrt{2}\sqrt{4-\sqrt{15}}\\ =\left(4+\sqrt{15}\right)\left(\sqrt{5}-\sqrt{3}\right)\sqrt{8-2\sqrt{15}}\\ =\left(4+\sqrt{15}\right)\left(\sqrt{5}-\sqrt{3}\right)\sqrt{\left(\sqrt{5}-\sqrt{3}\right)^2}\\ =\left(4+\sqrt{15}\right)\left(\sqrt{5}-\sqrt{3}\right)\left(\sqrt{5}-\sqrt{3}\right)\\ =\left(4+\sqrt{15}\right)\left(8-2\sqrt{15}\right)\\ =32-8\sqrt{15}+8\sqrt{15}-30=2\)

a) n_CuCl2 = 0,15.2 = 0,3 (mol)

PTHH: 2Al + 3CuCl₂ --> 2AlCl₃ + 3Cu

____0,2<------0,3--------->0,2---->0,3

=> m = 0,3.64 - 0,2.27 = 13,8 (g)

b) \(C_{M\left(AlCl_3\right)}=\dfrac{0,2}{0,15}=1,3333M\)

        = 12/11

Thanks bạn!

\(a,ĐKXĐ:\left\{{}\begin{matrix}8-4x\ge0\\5x-10\ne0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\le2\\x\ne2\end{matrix}\right.\Leftrightarrow x< 2\\ b,ĐKXĐ:\left\{{}\begin{matrix}\dfrac{-3}{x+2}\ge0\\x^2+2\ge0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x+2< 0\left(-3< 0;x+2\ne0\right)\\x\in R\left(x^2+2\ge2>0\right)\end{matrix}\right.\Leftrightarrow x< -2\)