b, \(\left(x-5\right)\left(x-4\right)-\left(x+1\right)\left(x-2\right)=7\)

\(\Rightarrow x^2-9x+20-x^2+x+2=7\)

\(\Rightarrow-8x+22=7\)

\(\Rightarrow-8x=-15\)

\(\Rightarrow x=\frac{15}{8}\)

c, \(\left(3x-4\right)\left(x-2\right)=3x\left(x-9\right)-3\)

\(\Rightarrow3x^2-10x+8=3x^2-27x-3\)

\(\Rightarrow3x^2-10x-3x^2+27x=\left(-3\right)+\left(-8\right)\)

\(\Rightarrow17x=-11\)

\(\Rightarrow x=-\frac{11}{17}\)

d, \(\left(x-3\right)\left(x^2+3x+9\right)+x\left(5-x^2\right)=6x\)

\(\Rightarrow x^3+3x^2+9x-3x^2-9x-27+5x-x^3=6x\)

\(\Rightarrow6x=-27\)

\(\Rightarrow x=-\frac{27}{6}\)

\(\Rightarrow x=-\frac{9}{2}\)

e, \(\left(3x-5\right)\left(x+1\right)-\left(3x-1\right)\left(x+1\right)=x-4\)

\(\Rightarrow3x^2-2x-5-3x^2-2x+1=x-4\)

\(\Rightarrow-4=x-4\)

\(\Rightarrow x=0\)

b)    (x - 5)(x - 4) - (x + 1)(x - 2) = 7
<=> x² - 9x + 20 - x² + x + 2 - 7 = 0
<=> 8x - 15 = 0 <=> x = 15/8

c)    (3x - 4)(x - 2) = 3x(x - 9) - 3
<=> 3x² - 10x + 8 = 3x² - 27x - 3
<=> 17x = -11 <=> x = -11/17

d)    (x - 3)(x² + 3x + 9) + x(5 - x²) = 6x
<=> x³ - 27 - x³ + 5x - 6x = 0
<=> x = -27

e)    (3x - 5)(x + 1) - (3x - 1)(x + 1) = x - 4
<=> (x + 1)(3x - 5 - 3x + 1) - x + 4 = 0
<=> -4x - 4 - x + 4 = 0 <=> x = 0

a) Rút gọn VT = 45x + 8. Từ đó tìm được x = 2 15 .  

b) Rút gọn VT = -25x – 8. Từ đó tìm được x = − 11 25 .

(x+2)(x+3)-(x-2)(x+5)=0

=> x²+5x+6-x²-3x+10=0

=>2x+16=0 

 =>2x=-16

=>x=-8

a) \(\Rightarrow5x^2-15x=5x^2-x-10x+2-5\)

\(\Rightarrow5x^2-15x-5x^2+x+10x=2-5\)

\(\Rightarrow-4x=-3\)

\(\Rightarrow x=\frac{3}{4}\)

Vậy \(x=\frac{3}{4}\)

b) \(\Rightarrow x^2-4x-5x+20-x^2+2x-x+2=7\)

\(\Rightarrow x^2-4x-5x-x^2+2x-x=7-20-2\)

\(\Rightarrow-8x=-15\)

\(\Rightarrow x=\frac{15}{8}\)

Vậy \(x=\frac{15}{8}\)

c) \(\Rightarrow3x^2-6x-4x+8=3x^2-27x-3\)

\(\Rightarrow3x^2-6x-4x-3x^2+27x=-3-8\)

\(\Rightarrow17x=-11\)

\(\Rightarrow x=\frac{-11}{17}\)

Vậy \(x=\frac{-11}{17}\)

Chúc bạn học tốt.

a)4×(x-5)-(x-1)×(4x-3)=5

=>4x-20-4x²+7x-3-5=0

=>-4x²+11x-28=0

=>-4(x²-\(\frac{11x}{4}\)+7)=0

=>\(-4\left(x-\frac{11}{8}\right)^2-\frac{327}{16}< 0\)

=>vô nghiệm

b) (3x-4)(x-2)=3x(x-9)-3

=>3x²-10x+8=3x²-27x-3

=>17x=-11

=>x=-11/17

c)(x-5)×(x-4)-(x+1)×(x-2)=7

=>x²-9x+20-x²+x+2=7

=>22-8x=7

=>-8x=-15

=>x=8/15

d)(2x-1)×(x-2)-(x+3)×(2x-7)=3

=>2x²-5x+2-2x²+x+21=3

=>23-4x=3

=>-4x=-20

=>x=5

dễ mà ko biết làm

k mk đi

ai k mk 

mk k lại

thanks

không ai trả lời 

a,\(2\left(3x-1\right)-5\left(x-3\right)-9\left(2x-4\right)=24\)

\(< =>6x-2-5x+15-18x+36=24\)

\(< =>-29x+49=24< =>29x=25< =>x=\frac{25}{29}\)

b,\(2x^2+4\left(x^2-1\right)=2x\left(3x+1\right)\)

\(< =>2x^2+4x^2-4=6x^2+2x\)

\(< =>2x=-4< =>x=-\frac{4}{2}=-2\)

c, \(2x\left(5-3x\right)+2x\left(3x-5\right)-3\left(x-7\right)=4\)

\(< =>10x-6x^2+6x^2-10x-3x+21=4\)

\(< =>-3x=4-21=-17< =>x=\frac{17}{3}\)

d, \(5x\left(x+1\right)-4x\left(x+2\right)=1-x\)

\(< =>5x^2+5x-4x^2-8x=1-x\)

\(< =>x^2-3x+x-1=0\)

\(< =>x^2-2x-1=0\)

\(< =>\left(x-1\right)^2=2\)

\(< =>\orbr{\begin{cases}x-1=\sqrt{2}\\x-1=-\sqrt{2}\end{cases}}\)

\(< =>\orbr{\begin{cases}x=1+\sqrt{2}\\x=1-\sqrt{2}\end{cases}}\)

Sai rồi bn:)

a, \(2\left(3x-1\right)-5\left(x-3\right)-9\left(2x-4\right)=24\)

\(\Leftrightarrow6x-2-5x+15-18x+36=24\)

\(\Leftrightarrow-17x+25=0\Leftrightarrow x=\frac{25}{17}\)

b, \(2x^2+4\left(x^2-1\right)=2x\left(3x+1\right)\)

\(\Leftrightarrow2x^2+4x^2-4=6x^2+2x\)

\(\Leftrightarrow-4-2x=0\Leftrightarrow x=-2\)

c, \(2x\left(5-3x\right)+2x\left(3x-5\right)-3\left(x-7\right)=4\)

\(\Leftrightarrow10x-6x^2+6x^2-10x-3x+21=4\)

\(\Leftrightarrow-3x+17=0\Leftrightarrow x=\frac{17}{3}\)

d, \(5x\left(x+1\right)-4x\left(x+2\right)=1-x\)

\(\Leftrightarrow5x^2+5x-4x^2-8x=1-x\)

\(\Leftrightarrow x^2-3x-1+x=0\Leftrightarrow x^2-2x-1=0\)

\(\Leftrightarrow x^2-2x+1-2=0\Leftrightarrow\left(x-1\right)^2=2\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=\sqrt{2}\\x-1=-\sqrt{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\sqrt{2}+1\\x=-\sqrt{2}+1\end{cases}}}\)