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to cao luon

ko biết lam

a/ đúng

b/ sai

c/sai

d/ đúng

Đ

S

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Đ

Đ

S

S

Đ

3 + 1 + 2 = 4 + 2 = 6                                   

5 – 2 – 2 = 3 – 2 = 1

4 + 3 + 1 = 7 + 1 = 8                                   

8 – 1 – 3 = 7 – 3 = 4

\(\dfrac{24}{x}:\dfrac{8}{3}=\dfrac{3}{5}\)

\(\dfrac{24}{x}=\dfrac{3}{5}.\dfrac{8}{3}\)

\(\dfrac{24}{x}=\dfrac{8}{5}\)

\(\dfrac{24}{x}=\dfrac{24}{15}\)

=>x=5

Vậy x=5

\(x+3\dfrac{1}{2}+x=24\dfrac{1}{4}\)

\(\left(x+x\right)+3\dfrac{1}{2}=24\dfrac{1}{4}\)

\(x.2+\dfrac{7}{2}=\dfrac{97}{4}\)

\(x.2=\dfrac{97}{4}-\dfrac{7}{2}\)

\(x.2=\dfrac{97}{4}-\dfrac{14}{4}\)

\(x.2=\dfrac{83}{4}\)

\(x=\dfrac{83}{4}:2\)

\(x=\dfrac{83}{4}.\dfrac{1}{2}\)

\(x=\dfrac{83}{8}\)

\(x=10\dfrac{3}{8}\)

\(\dfrac{1}{3}+\dfrac{3}{4}+\dfrac{1}{2}=\dfrac{4}{12}+\dfrac{9}{12}+\dfrac{6}{12}=\dfrac{19}{12}\)
\(\dfrac{6}{8}+\dfrac{2}{4}+\dfrac{6}{24}=\dfrac{3}{4}+\dfrac{2}{4}+\dfrac{1}{4}=\dfrac{6}{4}=\dfrac{3}{2}\)
\(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{5}{6}=\dfrac{3}{6}+\dfrac{2}{6}+\dfrac{5}{6}=\dfrac{10}{6}=\dfrac{5}{3}\)
\(\dfrac{3}{5}+\dfrac{3}{2}+2=\dfrac{6}{10}+\dfrac{15}{10}+\dfrac{20}{10}=\dfrac{41}{10}\)

\(\dfrac{1}{3}+\dfrac{3}{4}+\dfrac{1}{2}=\dfrac{13}{12}+\dfrac{1}{2}=\dfrac{19}{12}\\ \dfrac{6}{8}+\dfrac{2}{4}+\dfrac{6}{24}=\dfrac{5}{4}+\dfrac{6}{24}=\dfrac{3}{2}\\ \dfrac{1}{2}+\dfrac{1}{3}+\dfrac{5}{6}=\dfrac{5}{6}+\dfrac{5}{6}=\dfrac{10}{6}\\ \dfrac{3}{5}+\dfrac{3}{2}+2=\dfrac{21}{10}+\dfrac{20}{10}=\dfrac{41}{10}\)

`1/3 + 3/4 +1/2`

`= 4/12 + 9/12 + 6/12`

`= (4+9+6)/12`

`= 19/12`

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`6/8 + 2/4 + 6/24`

`= 3/4 + 2/4 + 1/4`

`=(3+2+1)/4`

`= 6/4= 3/2`

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`1/2 + 1/3 + 5/6`

`= 3/6 + 2/6 + 5/6`

`=(3+2+5)/6`

`=10/6`

`=5/3`

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`3/5 + 3/2+2`

`= 6/10 + 15/10 + 20/10`

`=(6+15+20)/10`

`= 41/10`