\(\frac{1}{\left(x+29\right)^2}\)+\(\frac{1}{\left(x+30\right)^2}\)
Những câu hỏi liên quan
Tìm x biết :
\(\frac{1}{\left(x+29\right)^2}+\frac{1}{\left(x+30\right)^2}=\frac{5}{4}\)
Đặt x + 29 = a (a \(\ne-29;-30\))
Đề trở thành: \(\frac{1}{a^2}+\frac{1}{\left(a+1\right)^2}=\frac{5}{4}\)
\(\Leftrightarrow\frac{\left(a+1\right)^2+a^2}{a^2\left(a+1\right)^2}=\frac{5}{4}\)
\(\Leftrightarrow\frac{a^2+2a+1+a^2}{a^2\left(a^2+2a+1\right)}=\frac{5}{4}\)
\(\Leftrightarrow\frac{2a^2+2a+1}{a^4+2a^3+a^2}=\frac{5}{4}\)
\(\Leftrightarrow8a^2+8a+4=5a^4+10a^3+5a^2\)
\(\Leftrightarrow5a^4+10a^3-3a^2-8a-4=0\)
\(\Leftrightarrow5a^4+10a^3-3a^2-6a-2a-4=0\)
\(\Leftrightarrow5a^3\left(a+2\right)-3a\left(a+2\right)-2\left(a+2\right)=0\)
\(\Leftrightarrow\left(a+2\right)\left(5a^3-3a-2\right)=0\)
\(\Leftrightarrow\left(a+2\right)\left(5a^3-5a+2a-2\right)=0\)
\(\Leftrightarrow\left(a+2\right)\left(a-1\right)\left(5a^2+5a+2\right)=0\)
tới đây dễ r`
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=\(\frac{1}{x^2}\)+ \(\frac{1}{^{29^2}}\)+\(\frac{1}{x^2}\)+\(\frac{1}{30^2}\)=5/4
=\(\frac{1}{x^2}\)x2 + \(\frac{1}{29^2}\)+\(\frac{1}{30^2}\)=5/4
=\(\frac{2}{x^2}\)+\(\frac{1}{841}\)+\(\frac{1}{900}\)=5/4
\(\frac{2}{x^2}\)=\(\frac{5}{4}\)-\(\frac{1}{841}\)-\(\frac{1}{900}\)bạn tự tính tiếp đi
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a) Tìm x,y biết: x4+x2-y2+y+10=0
b) Tính giá trị biểu thức: \(\frac{\left(1+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)...\left(29^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)...\left(30^4+\frac{1}{4}\right)}\)
giải pt: a)\(\left(x^2-3x\right)\left(x^2+7x+10\right)=216\) b)\(\left(2x^2-7x+3\right)\left(2x^2+x-3\right)+9=0\) c)\(\frac{1}{\left(x+29\right)^2}+\frac{1}{\left(x+30\right)^2}=\frac{13}{36}\)
\(\frac{\left(1^2+\frac{1}{4}\right)\left(3^2+\frac{1}{4}\right)\left(5^2+\frac{1}{4}\right)..........\left(29^2+\frac{1}{4}\right)}{\left(2^2+\frac{1}{4}\right)\left(4^2+\frac{1}{4}\right)\left(6^2+\frac{1}{4}\right)...........\left(30^2+\frac{1}{4}\right)}\)
tính giá trị biểu thức trên
tính B=\(\frac{\left(1^4+\frac{1}{4}\right).\left(3^4+\frac{1}{4}\right).....\left(29^4+\frac{1}{4}\right)}{\left(2^{\text{4}}+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)......\left(30^4+\frac{1}{4}\right)}\)
Tính \(A=\frac{\left(1+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)...\left(29^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)...\left(30^4+\frac{1}{4}\right)}\)
tính :\(\frac{\left(1+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)...\left(29^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)...\left(30^4+\frac{1}{4}\right)}\)
1.Giải phương trình: \(\frac{1}{x^2+9x+20}+\frac{1}{x^2+11x+30}+\frac{1}{x^2+13x+42}=\frac{1}{18}\)
2.Giải phương trình: \(8\left(x+\frac{1}{x}\right)^2+4\left(x^2+\frac{1}{x^2}\right)^2-4\left(x^2+\frac{1}{x^2}\right)\left(x+\frac{1}{x}\right)^2=\left(x+4\right)^2\)
Giải phương trình:
1. frac{2x+3}{4}-frac{5x+3}{6}frac{3-4x}{12}
2. frac{3.left(2x+1right)}{4}-1frac{15x-1}{10}
3. frac{2x-1}{5}-frac{x-2}{3}frac{x+7}{15}
4. frac{x+3}{2}-frac{x-1}{3}frac{x+5}{6}+1
5. frac{x-4}{5}-frac{3x-2}{10}-xfrac{2x-5}{3}-frac{7x+2}{6}
6. frac{left(x+2right)left(x+10right)}{3}-frac{left(x+4right)left(x+10right)}{12}frac{left(x-2right)left(x+4right)}{4}
7. frac{left(x+2right)^2}{8}-2left(2x-1right)25+frac{left(x-2right)^2}{8}
8.frac{7x^2-14x-5}{5}frac{left(2x+1right)^...
Đọc tiếp
Giải phương trình:
1. \(\frac{2x+3}{4}-\frac{5x+3}{6}=\frac{3-4x}{12}\)
2. \(\frac{3.\left(2x+1\right)}{4}-1=\frac{15x-1}{10}\)
3. \(\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{15}\)
4. \(\frac{x+3}{2}-\frac{x-1}{3}=\frac{x+5}{6}+1\)
5. \(\frac{x-4}{5}-\frac{3x-2}{10}-x=\frac{2x-5}{3}-\frac{7x+2}{6}\)
6. \(\frac{\left(x+2\right)\left(x+10\right)}{3}-\frac{\left(x+4\right)\left(x+10\right)}{12}=\frac{\left(x-2\right)\left(x+4\right)}{4}\)
7. \(\frac{\left(x+2\right)^2}{8}-2\left(2x-1\right)=25+\frac{\left(x-2\right)^2}{8}\)
8.\(\frac{7x^2-14x-5}{5}=\frac{\left(2x+1\right)^2}{5}-\frac{\left(x-1\right)^2}{3}\)
9. \(\frac{\left(2x-3\right)\left(2x+3\right)}{8}=\frac{\left(x-4\right)^2}{6}+\frac{\left(x-2\right)^2}{3}\)
10. \(\frac{x+1}{35}+\frac{x+3}{33}=\frac{x+5}{31}+\frac{x+7}{29}\)
1.
\(\frac{2x+3}{4}-\frac{5x+3}{6}=\frac{3-4x}{12}\)
\(MC:12\)
Quy đồng :
\(\Rightarrow\frac{3.\left(2x+3\right)}{12}-\left(\frac{2.\left(5x+3\right)}{12}\right)=\frac{3x-4}{12}\)
\(\frac{6x+9}{12}-\left(\frac{10x+6}{12}\right)=\frac{3x-4}{12}\)
\(\Leftrightarrow6x+9-\left(10x+6\right)=3x-4\)
\(\Leftrightarrow6x+9-3x=-4-9+16\)
\(\Leftrightarrow-7x=3\)
\(\Leftrightarrow x=\frac{-3}{7}\)
2.\(\frac{3.\left(2x+1\right)}{4}-1=\frac{15x-1}{10}\)
\(MC:20\)
Quy đồng :
\(\frac{15.\left(2x+1\right)}{20}-\frac{20}{20}=\frac{2.\left(15x-1\right)}{20}\)
\(\Leftrightarrow15\left(2x+1\right)-20=2\left(15x-1\right)\)
\(\Leftrightarrow30x+15-20=15x-2\)
\(\Leftrightarrow15x=3\)
\(\Leftrightarrow x=\frac{3}{15}=\frac{1}{5}\)