\(\frac{1}{\left(x+29\right)^2}+\frac{1}{\left(x+30\right)^2}=\frac{\left(x+30\right)^2}{\left(x+29\right)^2\left(x+30\right)^2}+\frac{\left(x+29\right)^2}{\left(x+29\right)^2\left(x+30\right)^2}\)
\(=\frac{x^2+60x+900+x^2+58x+841}{\left(x+29\right)^2\left(x+30\right)^2}\)
\(=\frac{2x^2+118x+1741}{\left(x+29\right)^2\left(x+30\right)^2}\)
giải pt: a)\(\left(x^2-3x\right)\left(x^2+7x+10\right)=216\) b)\(\left(2x^2-7x+3\right)\left(2x^2+x-3\right)+9=0\) c)\(\frac{1}{\left(x+29\right)^2}+\frac{1}{\left(x+30\right)^2}=\frac{13}{36}\)
\(\frac{\left(1^2+\frac{1}{4}\right)\left(3^2+\frac{1}{4}\right)\left(5^2+\frac{1}{4}\right)..........\left(29^2+\frac{1}{4}\right)}{\left(2^2+\frac{1}{4}\right)\left(4^2+\frac{1}{4}\right)\left(6^2+\frac{1}{4}\right)...........\left(30^2+\frac{1}{4}\right)}\)
tính giá trị biểu thức trên
TÍnh giá trị biểu thức
A=\(\frac{\left(1+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)...\left(29^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)...\left(30^4+\frac{1}{4}\right)}\)
Tính giá trị biểu thức
A=\(\frac{\left(1+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)..........\left(29^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right).........\left(30^4+\frac{1}{4}\right)}\)
tính giá trị của biểu thức \(\frac{\left(\frac{1}{4}+1\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)...\left(29^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)...\left(30^4+\frac{1}{4}\right)}\)
\(\frac{\left(1^4+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)...\left(29^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)...\left(30^4+\frac{1}{4}\right)}=?\)
Ai biết giúp tớ với
Tính giá trị biểu thức
\(A=\frac{\left(1+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)..........\left(29^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)..........\left(30^4+\frac{1}{4}\right)}\)
Rút gọn và tính số trị của tổng: \(M=\frac{\left(1+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)...\left(29^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)...\left(30^4+\frac{1}{4}\right)}\)
ta có D =\(\left(\frac{1}{x-1}-\frac{x}{1-x^3}.\frac{x^2+x+1}{x+1}\right):\left(\frac{2x+1}{x^2+x+1}\right)\)
( đkxđ: x khác 1 và -1, x khác -1/2)
=\(\left(\frac{1}{x-1}+\frac{x}{ \left(x-1\right)\left(x^2+x+1\right)}.\frac{x^2+x+1}{x+1}\right):\left(\frac{2x+1}{x^2+x+1}\right)\)
=\(\left(\frac{1}{x-1}+\frac{x\left(x^2+x+1\right)}{\left(x-1\right)\left(x+1\right)\left(x^2+x+1\right)}\right):\left(\frac{2x+1}{x^2+x+1}\right)\)
=\(\left(\frac{1}{x-1}+\frac{x}{\left(x-1\right)\left(x+1\right)}\right):\left(\frac{2x+1}{x^2+x+1}\right)\)
