15x+3-4x=17x-12x=43
a)(6x^2+17x+12):(2x+3) b)(5x^2+13x-6):(5x-2) c)(-8x^2+22x-15):(2x-5) d)(14x^2-33x-5):(2x-5) e)(2x^3+7x^2+15x+6):(2x+1) f)(x^3+4x^2-11x-2):(x-2) g)(12x^3+2x^2+4x+3):(2x+1)
a: \(=\dfrac{6x^2+9x+8x+12}{2x+3}=\dfrac{3x\left(2x+3\right)+4\left(2x+3\right)}{2x+3}\)
=3x+4
b: \(=\dfrac{5x^2-2x+15x-6}{5x-2}\)
\(=\dfrac{x\left(5x-2\right)+3\left(5x-2\right)}{5x-2}=x+3\)
c: \(=\dfrac{-8x^2+20x+2x-5-10}{2x-5}=-4x+1+\dfrac{-10}{2x-5}\)
d: \(=\dfrac{14x^2-35x+2x-5}{2x-5}=\dfrac{7x\left(2x-5\right)+\left(2x-5\right)}{2x-5}\)
=7x+1
e: \(=\dfrac{2x^3+x^2+6x^2+3x+12x+6}{2x+1}\)
\(=\dfrac{x^2\left(2x+1\right)+3x\left(2x+1\right)+6\left(2x+1\right)}{2x+1}=x^2+3x+6\)
f: \(=\dfrac{x^3-2x^2+6x^2-12x+x-2}{x-2}=x^2+6x+1\)
g: \(=\dfrac{12x^3+6x^2-4x^2-2x+6x+3}{2x+1}=6x^2-2x+3\)
Cho 3 đa thức:
P(x)=6x2-17x+15
Q(x)=12x2 +4x-3
H(x)= -15x2+13x-12
Chứng tỏ rằng trong 3 đa thức trên có 1 giá trị không âm.
Giúp mk vs.
a) -2x-(x-17)=34-(-x 25)
b) 17x-(-16x-27)=2x 43
c) -2x-3(x-17)=34-2(-x 25)
d) 17x +3(-16x-37)=2x 43-4x
a) -2x - (x-17) = 34-(-x + 25)
-2x- x+17= 34+x-25
-2x-x-x= -17 +34-25
-4x = -8
x = 2
b)17x-(-16x-27) = 2x+43
17x + 16x + 27 = 2x + 43
17x + 16x -2x= -27 +43
31x= 26
x= 21/31
c)- 2x- 3(x-17) = 34- 2(-x + 25)
-2x - 3x + 51 = 34 + 2x -50
-2x - 3x -2x = -51 + 34 -50
-7x = -67
x = 67/7
d) 17x +3(-16x-37) = 2x+ 43 -4x
17x -48x -111 = 2x + 43 -4x
17x - 48x -2x + 4x = 111 -43
-29x = 68
x = -68/29
D) 17x+ 3. ( -16x -37) = 2x +43 -4x
ko chép lại đề abif
<=> 17x-48x-111=43-2x
<=> -31x+2x=43+111
<=>-29x=154
<=> x=\(\frac{-154}{29}\)
x=\(\frac{-154}{29}\)
B) 17X - ( -16X - 37 ) + 2x + 43
C) -2x -3.( x-17) = 34 -2 (-2x +25)
D) 17x+ 3. ( -16x -37) = 2x +43 -4x
E) {- 3x +2. [45 - x-3 (3x + 7) - 2x] + 4x} =55
F) -103 - 57 : [ -2 ( 2x -1 )2 - ( -9 )0 ] - 106
G) -2x + 3. { 12-2 [ 3x - ( 20 + 2x ) - 4x ] + 1} = 45
Tìm số nguyên x:
a) -2x -(x-17)=34 -(-x+25)
b) 17x -(16x-37)=2x+43
c) -2x - 3.(x-17)=34-2(-x+25)
d) 17x + 3.(-16-37)=2x + 43 -4x
e) {-3x + 2.[45 - x - 3(3x + 7)-2x] + 4x}=55
Giúp mik vs:33
a,-2x -(x-17)=34-(-x+25)
-2x-x+17=34+x-25
-3x+17=9+x
-3x-x=9-17
-4x=-8
-->4x=8
x=8:4
x=2
Vậy x=2
b,17-(16x-37)=2x+43
17-16x+37=2x+43
20-16x=2x+43
-16x-2x=43-20
-18x=23
x=23:(-18)
x=23/-18
Mà x là số nguyên nên --> x thuộc tập rỗng
c,-2x-3.(x-17)=34-2(-x+25)
-2x-3x+51=34-2.(-x)-25
-5x+51=9-(-2).x
-5x+(-2).x=9-51
-7x=-42
7x=42
x=42:7
x=6
Vậy x=6
-2x – (x – 17) = 34 – (-x + 25)
17x – ( -16x – 37) = 2x + 43
-2x –3. (x – 17) = 34 – 2(-x + 25)
17x + 3. ( -16x – 37) = 2x + 43 - 4x
{ -3x + 2.[ 45- x -3( 3x+ 7 -2x ] +4x } = 55
103 -57: [-2. (2x – 1 ) ^ 2 – (-9) ^ 0 ] = -106
1)-2x – (x – 17) = 34 – (-x + 25)
-2x-x-_17
17x + 3. ( -16 x -37 ) = 2x + 43 + 4x
giải hộ mk vs
17x+3.(-16x-37) =2x+43+4x
17x+3.(-16).x-3.37=6x+43
17x+(-48)x-119 =6x+43
[17x-6x+(-48)x] =43+119
-37x =162
37x =-162
x =-162:37
x = -162/37
Cho mình hỏi bài này với:
a/ 17x - ( -16x - 37 ) = 2x + 43
b/ -2x - 3. (x - 17 ) = 34 -2 ( -x+25)
c/ 17x + 3. ( -16 x -37 ) = 2x + 43 + 4x
Giải kỹ giùm nha. Thanks!
a/17.x+16.x+37-2.x=43
=>17.x+16.x-2.x=43-37=6
=>x.(17+16-2)=6
=>x.31=6
=>x=\(\frac{6}{31}\)
b và c tương tự
-2-(x-17)=34-(x+25)
-2-x+17=34+x-25
-x-x=34-25+2-17
-2x=-6
x=-6:(-2)
x=3
nho cho minh nha