x : 0,625 + x : 0,375 = 123456789
Tìm x
x - \(\frac{0,375-0,3+\frac{3}{17}-\frac{3}{19}}{-0,625+0,5-\frac{5}{17}-\frac{5}{19}}\)= \(\frac{1}{4}\)
RUT GON A=0,375-0,3+3/11+3/12/-0,625+0,5-5/11-5/12
RUT GON A=0,375-0,3+3/11+3/12/-0,625+0,5-5/11-5/12
\(A=\dfrac{\dfrac{3}{8}-\dfrac{3}{10}+\dfrac{3}{11}+\dfrac{3}{12}}{\dfrac{-5}{8}+\dfrac{5}{10}-\dfrac{5}{11}-\dfrac{5}{12}}=\dfrac{-3}{5}\)
B=85.(−5)8(−2)5.109216.57+2087B=85.(−5)8(−2)5.109216.57+2087
C=0,375−0,3+311+312−0,625+0,5−511−512+1,5+1−0,752,5+53−1,25C=0,375−0,3+311+312−0,625+0,5−511−512+1,5+1−0,752,5+53−1,25
Rút gọn các biểu thức trên .
(làm được bao nhiêu thì làm nhé :( )
Tính:
M = 0,375 -0,3+3/11 +3/12 / -0,625 + 0,5 -5/11-5/12
\(M=0,375-0,3+\dfrac{3}{11}+\dfrac{3}{12}-0,625+0,5-\dfrac{5}{11}-\dfrac{5}{12}\)
\(M=\left(0,375-0,625\right)+\left(0,5-0,3\right)+\left(\dfrac{3}{11}-\dfrac{5}{11}\right)+\left(\dfrac{3}{12}-\dfrac{5}{12}\right)\)
\(M=-0,25+0,2-\dfrac{2}{11}-\dfrac{1}{6}\)
\(M=-\dfrac{263}{660}\)
\(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625+0,5-\frac{5}{11}-\frac{5}{12}}\)
A = 0,375-0,3 +3/11 +3/12
0,625 +0,5 -5/11 -5/11
A=\(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625+0,5-\frac{5}{11}-\frac{5}{12}}\)
A=\(\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{5}{8}+\frac{5}{10}-\frac{5}{11}-\frac{5}{12}}\)
A=\(\frac{3\cdot\left(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)}{-5\cdot\left(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)}\)
A=\(\frac{-3}{5}\)
Bạn ghi sai đề nhá
Tui sửa dùm rồi nghen
Học tốt !!!
Tính \(A=\frac{0,375-0,3+\frac{3}{11}+\frac{1}{4}}{0,625+0,5-\frac{5}{11}-\frac{5}{12}}\)
\(A=\frac{0,375-0,3+\frac{3}{11}+\frac{1}{4}}{0,625+0,5-\frac{5}{11}-\frac{5}{12}}\)
\(=\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{5}{8}+\frac{5}{10}-\frac{5}{11}-\frac{5}{12}}\)
\(=\frac{3\left(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)}{5\left(\frac{1}{8}+\frac{1}{10}-\frac{1}{12}-\frac{1}{12}\right)}\)
\(=\frac{3.263.\frac{1}{1320}}{5.67.\frac{1}{1320}}=\frac{789.\frac{1}{1320}}{335,\frac{1}{1320}}=\frac{789}{335}\)
Tính
\(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0.5+\frac{5}{11}+\frac{5}{12}}\)
\(\frac{3.\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{6.\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{6}=\frac{1}{2}\)