Bài 12: 

\(\dfrac{a}{b}=\dfrac{7}{8}\)

nên \(b=a:\dfrac{7}{8}=\dfrac{8}{7}a\)

Ta có: \(\dfrac{b}{c}=\dfrac{4}{3}\)

\(\Leftrightarrow b=\dfrac{4}{3}c\)

\(\Leftrightarrow a\cdot\dfrac{8}{7}=\dfrac{4}{3}c\)

\(\Leftrightarrow a=\dfrac{4}{3}:\dfrac{8}{7}\cdot c=\dfrac{4}{3}\cdot\dfrac{7}{8}\cdot c=\dfrac{7}{6}c\)

Vậy: c tỉ lệ với a theo hệ số tỉ lệ k=6/7

a)MTC:\(12x^5y^4\)

\(\dfrac{5}{x^5y^3}=\dfrac{5\cdot12y}{x^5y^3\cdot12y}=\dfrac{60y}{12x^5y^4}\)

\(\dfrac{7}{12x^3y^4}=\dfrac{7\cdot x^2}{12x^3y^4\cdot x^2}=\dfrac{7x^2}{12x^5y^4}\)

b)MTC:\(60x^4y^5\)

\(\dfrac{4}{15x^3y^5}=\dfrac{4\cdot4x}{15x^3y^5\cdot4x}=\dfrac{16x}{60x^4y^5}\)

\(\dfrac{11}{12x^4y^2}=\dfrac{11\cdot5y^3}{12x^4y^2\cdot5y^3}=\dfrac{55y^3}{60x^4y^5}\)

\(\frac{12x-15y}{7}=\frac{20z-12x}{9}=\frac{15y-20z}{11}=\frac{12x-15y+20z-12x+15y-20z}{7+9+11}=0\)

\(12x-15y=0\Rightarrow4x=5y\Rightarrow\frac{x}{5}=\frac{y}{4}\)

\(20z-12x=0\Rightarrow5z=3x\Rightarrow\frac{z}{3}=\frac{x}{5}\)

\(15y-20z=0\Rightarrow3y=4z\Rightarrow\frac{y}{4}=\frac{z}{3}\)

\(\Rightarrow\frac{x}{5}=\frac{y}{4}=\frac{z}{3}=\frac{x+y+z}{5+4+3}=\frac{48}{12}=4\)

ta có;x=4x5=20

y=4x4=16

z=4x3=12

sde dQTYTWAYEGFSAYEFGEYSARR WAFWIUFB   A RR qiiRY ii yÌU ẨU YIUWYR URH Y Y2QUR2QGyrg Y4

Bn lam dk chua Anh

Ta có:

\(\frac{12x-15y}{7}=\frac{20z-12x}{9}=\frac{15y-20z}{11}=\frac{12x-15y+20z-12x+15y-20z}{7+9+11}=0\)

Đề bài gì lạ vậy

Áp dụng tính chất của dãy tỉ số bằng nhau ta có : 

\(\frac{12x-15y}{7}=\frac{20z-12x}{9}=\frac{15y-20z}{11}=\frac{12x-15y+20z-12x+15y-20z}{7+9+11}=\frac{0}{27}=0\)

\(\Rightarrow\hept{\begin{cases}12x-15y=0\\15y-20z=0\end{cases}\Rightarrow\hept{\begin{cases}12x=15y\\15y=20z\end{cases}\Rightarrow}\hept{\begin{cases}\frac{x}{15}=\frac{y}{12}\\\frac{y}{20}=\frac{z}{15}\end{cases}\Rightarrow}\hept{\begin{cases}\frac{x}{75}=\frac{y}{60}\\\frac{y}{60}=\frac{z}{45}\end{cases}\Rightarrow}\frac{x}{75}=\frac{y}{60}=\frac{z}{45}}\)

Áp dụng tính chất của dãy tỉ số bằng nhau ta có : 

\(\frac{x}{75}=\frac{y}{60}=\frac{z}{45}=\frac{x+y+z}{75+60+45}=\frac{48}{180}=\frac{4}{15}\)

=> x = 75.4 : 15 = 20 ; 

     y = 60.4 : 15 = 16

     z = 45.4 : 15 = 12

Vậy x = 20 ; y = 16 ; z = 12