tim x,y,z thuoc Z biet:
\(|x-2017|+|y+2018|+|2019-3z|nhohonhoacbang0\)
Tim x, y, z biet
\(\dfrac{12x-15y}{2017}=\dfrac{20z-12x}{2018}=\dfrac{15y-20z}{2019}\) va x+y+z=48
Ta có:
\(\dfrac{12x-15y}{2017}=\dfrac{20z-12x}{2018}=\dfrac{15y-20z}{2019}\)
\(=\dfrac{12x-15y+20z-12x+15y-20z}{2017+2018+2019}\)
\(=\dfrac{0}{2017+2018+2019}=0\)
\(\Rightarrow\left\{{}\begin{matrix}12x-15y=0\\20z-12x=0\\15y-20z=0\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}12x=15y\\20z=12x\\15y=20z\end{matrix}\right.\)\(\Rightarrow12x=15y=20z\)
\(\Rightarrow\dfrac{x}{5}=\dfrac{y}{4}=\dfrac{z}{3}\)
Áp dụng tích chất dãy tỉ số bằng nhau, ta có:
\(\dfrac{x}{5}=\dfrac{y}{4}=\dfrac{z}{3}=\dfrac{x+y+z}{5+4+3}=\dfrac{48}{12}=4\)
\(\Rightarrow\left\{{}\begin{matrix}x=4.5=20\\y=4.4=16\\z=4.3=12\end{matrix}\right.\)
Vậy ...
tim x,y thuoc Z biet 25-y^2=9(x-2018)^2
tính
\(B=xy^2z^3+x^2y^3z^4+x^3y^4z^5+...+x^{2017}y^{2018}z^{2019}vớix=y=z=-1\)
Lời giải:
Với \(x=y=z=-1\) thì:
\(B=(-1)(-1)^2(-1)^3+(-1)^2(-1)^3(-1)^4+(-1)^3(-1)^4(-1)^5+...+(-1)^{2017}(-1)^{2018}(-1)^{2019}\)
\(=(-1)^{1+2+3}+(-1)^{2+3+4}+(-1)^{3+4+5}+...+(-1)^{2017+2018+2019}\)
\(=(-1)^6+(-1)^{9}+(-1)^{12}+...+(-1)^{6054}\)
\(=[(-1)^6+(-1)^{12}+(-1)^{18}+...+(-1)^{6054}]+[(-1)^9+(-1)^{15}+...+(-1)^{6051}]\)
\(=\underbrace{1+1+..+1}_{1009}+\underbrace{[(-1)+(-1)+..+(-1)]}_{1008}\)
\(=1009-1008=1\)
a)tim a,b,c thuoc Z biet:
Ia-bI+Ib-cI+Ic-aI=2017^2018
b)Tim x:y thuoc N* biet :
3x-1 chia het cho y va 3y-1 chia het cho x
NHANH LEN NHE CAC BAN !!!!!!!!!!!!!!!!!!!!!
Cho x, y, z thỏa mãn:
\(\frac{x}{2017}+\frac{y}{2018}+\frac{z}{2019}=1\)
\(\frac{2017}{x}+\frac{2018}{y}+\frac{2019}{z}=0\)
CMR:\(\frac{x^2}{2017^2}+\frac{y^2}{2018^2}+\frac{z^2}{2019^2}=1\)
tim x, y, z thuoc Z sao cho /x-y/+/y-z/+/x-z/=2019
cho x^2016 + y^2016 + z^2016 = x^2019 + y^2019 + z^2019 = 1
tính P = (x-1)^2017 + (y-1)^2018 + (z-1)^2019
tim x, y, z thuoc Z sao cho /x-y/+/y-z/+/z-x/=2019
Cho các số thực x,y,z thỏa mãn: x+2y+3z=0 và 2xy+6yz+3zx=0. Tính giá trị của biểu thức:
S=\(\frac{\left(x-1\right)^{2019}-\left(1-y\right)^{2017}+\left(3z-1\right)^{2015}}{\left(x+1\right)^{2018}+2\left(y-z\right)^{2016}+y^{2014}+2}\)
Giúp mik vs gấp quá !