dd ba(no3)2 pli ra ba2+ và 2 no3- => [ba2+]=0,1,,[no3-]=0,2

dd hno3 pli ra h+ và no3- => [h+]=0,02.....[no3-]=0,02

al2(so4)3 pli ra 2 al3+ và 3 so42- => [al3+]=0,2  [so42-]=0,3

a) Ta có: \(n_{HNO_3}=0,1\cdot0,25=0,025\left(mol\right)=n_{H^+}=n_{NO_3^-}\)

b) Ta có: \(n_{Ba\left(OH\right)_2}=0,2\cdot0,15=0,03\left(mol\right)\) \(\Rightarrow\left\{{}\begin{matrix}n_{Ba^{2+}}=0,03\left(mol\right)\\n_{OH^-}=0,06\left(mol\right)\end{matrix}\right.\)

c) Ta có: \(n_{Al_2\left(SO_4\right)_3}=0,2\cdot0,2=0,04\left(mol\right)\) \(\Rightarrow\left\{{}\begin{matrix}n_{Al^{3+}}=0,08\left(mol\right)\\n_{SO_4^{2-}}=0,12\left(mol\right)\end{matrix}\right.\)

a) \(m_{ddAl_2\left(SO_4\right)_3}=200\cdot1,2=240\left(g\right)\)

    \(\Rightarrow m_{Al_2\left(SO_4\right)_3}=\dfrac{240\cdot28,5}{100}=68,4\left(g\right)\)

    \(\Rightarrow n_{Al_2\left(SO_4\right)_3}=0,2mol\)

    \(\Rightarrow\left\{{}\begin{matrix}n_{Al^{3+}}=2n_{Al_2\left(SO_4\right)_3}=0,4mol\\n_{SO^{2-}_4}=0,6mol\end{matrix}\right.\)

b) \(n_{HCl}=0,1\cdot3=0,3mol\) \(\Rightarrow n_{Cl^-}=0,3mol\)

    \(n_{HNO_3}=0,1\cdot1=0,1mol\) \(\Rightarrow n_{NO^-_3}=0,1mol\)

    \(\Sigma n_{H^+}=n_{HCl}+n_{HNO_3}=0,3+0,1=0,4mol\)

a, \(\left[Al^{3+}\right]=0,2.2=0,4\left(M\right)\)

\(\left[SO_4^{2-}\right]=0,2.3=0,6\left(M\right)\)

b, \(\left[Mg^{2+}\right]=0,15.1=0,15\left(M\right)\)

\(\left[Cl^-\right]0,15.2=0,3\left(M\right)\)

a)m Al2(SO4)3=6,84.\(\dfrac{200}{100}\)=13,68g

=>n Al2(SO4)3=0,04 mol

b)n HCl=3.0,2=0,6 mol

a. \(m_{Al_2\left(SO_4\right)_3}=200.6,84\%=13,68\left(g\right)\)

\(n_{Al_2\left(SO_4\right)_3}=\dfrac{13.68}{342}=0,04\left(mol\right)\)

b. \(n_{HNO_3}=0,2.3=0,6\left(mol\right)\)

a)

$Ba(OH)_2 \to Ba^{2+} + 2OH^-$
$[Ba^{2+}] = C_{M_{Ba(OH)_2}} = 0,1M$
$[OH^-] = 0,1.2 = 0,2M$

b)

$Al_2(SO_4)_3 \to 2Al^{3+} + 3SO_4^{2-}$
$[Al^{3+}] = 0,1.2 = 0,2M$
$[SO_4^{2-}] = 0,1.3 = 0,3M$