Thuc hien phep tinh:
B=\(\frac{2+\sqrt{3}}{\sqrt{2}+\sqrt{2+\sqrt{3}}}+\frac{2-\sqrt{3}}{\sqrt{2}-\sqrt{2-\sqrt{3}}}\)
thuc hien phep tnh:
\(\frac{8+2\sqrt{2}}{3-\sqrt{2}}-\frac{2+3\sqrt{2}}{\sqrt{2}}+\frac{\sqrt{2}}{1-\sqrt{2}}\)
Thuc hien phep tinh \(\frac{5}{4-\sqrt{11}}+\frac{1}{3+\sqrt{7}}-\frac{6}{\sqrt{7}-2}-\frac{\sqrt{7}-5}{2}\)
Thuc hien phep tinh: B=\(\dfrac{2+\sqrt{3}}{\sqrt{2}+\sqrt{2+\sqrt{2}}}+\dfrac{2-\sqrt{3}}{\sqrt{2}-\sqrt{2-\sqrt{3}}}\)
\(B=\dfrac{2+\sqrt{3}}{\sqrt{2}+\sqrt{2+\sqrt{3}}}+\dfrac{2-\sqrt{3}}{\sqrt{2}-\sqrt{2-\sqrt{3}}}\)
\(=\sqrt{2}\left(\dfrac{2+\sqrt{3}}{2+\sqrt{3}+1}+\dfrac{2-\sqrt{3}}{2-\sqrt{3}+1}\right)\)
\(=\sqrt{2}\left(\dfrac{2+\sqrt{3}}{3+\sqrt{3}}+\dfrac{2-\sqrt{3}}{3-\sqrt{3}}\right)\)
\(=\sqrt{2}\cdot\dfrac{6-2\sqrt{3}+3\sqrt{3}-3+6+2\sqrt{3}-3\sqrt{3}-3}{6}\)
\(=\dfrac{1}{3\sqrt{2}}\cdot\dfrac{6}{1}=\sqrt{2}\)
thuc hien phep tinh
\(\left[6-3.\left(-\frac{1}{3}^2\right)+\sqrt{0,25}\right]:\sqrt{0,\left(9\right)}\)
\(\left(\frac{1}{2}\right)^2.\sqrt{16}-3^2.\sqrt{0,01}+\left(2^2\right)^2-\left(0,0\left(6\right)\right)+\frac{13}{30}\)
Rut gon bieu thuc:
a) (2-\(\sqrt{3}\))\(\sqrt{26+15\sqrt{3}}-\left(2+\sqrt{3}\right)\sqrt{26-15\sqrt{3}}\)
b) \(\frac{1}{\sqrt{3}}+\frac{1}{3\sqrt{2}}+\frac{1}{\sqrt{3}}\sqrt{\frac{5}{12}-\frac{1}{\sqrt{6}}}\)
c) \(\frac{\sqrt{7+\sqrt{5}}+\sqrt{7-\sqrt{5}}}{\sqrt{7+2\sqrt{11}}}-\sqrt{3-2\sqrt{2}}\)
thuc hien phep tinh:
\(\sqrt{3}.\sqrt{\frac{1}{27}}.\sqrt{5}.\sqrt{20}\)
\(\sqrt{3}.\sqrt{\frac{1}{27}}.\sqrt{5}.\sqrt{20}=\sqrt{3.\frac{1}{27}}.\sqrt{5.20}=\sqrt{\frac{1}{9}}.\sqrt{100}=\frac{1}{3}.10=\frac{10}{3}\)
truc can thuc va tinh
a) \(\frac{5}{4-\sqrt{11}}+\frac{1}{3+\sqrt{7}}-\frac{6}{\sqrt{7}-2}-\frac{\sqrt{7}-5}{2}\)
b) \(\frac{4}{\sqrt{5}-\sqrt{2}}+\frac{3}{\sqrt{5}-2}-\frac{2}{\sqrt{3}-2}+\frac{\sqrt{3}-1}{6}\)
Bạn xem hộ mk đề cậu b nhé căn 5- căn 2 hay là căn 5 - 2
trục can thuc A= \(\frac{4}{3+\sqrt{5}+\sqrt{2+2\sqrt{5}}}\)
B=\(\frac{2}{\sqrt[3]{4}+\sqrt[3]{2}+2}\)
C=\(\frac{2}{2\sqrt[3]{2}+2+\sqrt[3]{4}}\)
1/ Rut gon bieu thuc sau:
a) \(\sqrt{12-2\sqrt{35}}+\sqrt{7-2\sqrt{10}}-\sqrt{\sqrt{49}}\)
b) \(\frac{\sqrt{7}-5}{2}-\frac{6}{\sqrt{7}-2}+\frac{1}{3+\sqrt{7}}+\frac{3}{5+2\sqrt{7}}\)