1) thuc hien phep tinh:
\(\frac{4}{x+2}+\frac{2}{x-2}+\frac{5x-6}{4-x}\)
Những câu hỏi liên quan
Thuc hien phep tinh :
a) \(\frac{4-x}{x^3+2x}-\frac{x+5}{x^3-x^2+2x-2}\)
b) \(\frac{3x-23}{\left(3x-3\right)\left(x+4\right)}-\frac{x-3}{x^2+5x+4}\)
THUC HIEN PHEP TINH:\(\frac{^{x^2}}{5x+25}-\frac{10-2x}{x}+\frac{5x+50}{5x+x^2}\)
LAM ON GIUP MINH VS LAM HOAI MA NO CU SAI T.T
\(\frac{x^2}{5x+25}-\frac{10-2x}{x}+\frac{5x+50}{5x+x^2}=\frac{x^2}{5\left(x+5\right)}-\frac{10-2x}{x}+\frac{5x+50}{x\left(x+5\right)}\)
\(=\frac{x^3}{5x\left(x+5\right)}-\frac{5\left(x+5\right)\left(10-2x\right)}{5x\left(x+5\right)}+\frac{5\left(5x+50\right)}{5x\left(x+5\right)}\)
\(=\frac{x^3+10x^2+25x}{5x\left(x+5\right)}=\frac{x\left(x+5\right)^2}{5x\left(x+5\right)}=\frac{x+5}{5}\)
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Thuc hien cac phep tinh
a) \(\frac{4x^2}{5y^2}:\frac{6x}{5y}:\frac{2x}{3y}\)
b) \(\frac{x^2-4}{3x+12}.\frac{x+4}{2x-4}\)
c) \(\frac{x^2-36}{2x+10}.\frac{3}{6-x}\)
a) \(\frac{4x^2}{5y^2}.\frac{5y}{6x}.\frac{3y}{2x}=\frac{4x^2.5y.3y}{5y^2.6x.2x}=1\)
b)\(\frac{\left(x-2\right)\left(x+2\right)}{3\left(x+4\right)}.\frac{x+4}{2\left(x-2\right)}=\frac{x+2}{6}\)
c) \(\frac{\left(x-6\right)\left(x+6\right)}{2\left(x+5\right)}.\frac{-3}{x-6}=\frac{-3\left(x+6\right)}{2\left(x+5\right)}\)
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Thuc hien phep tinh
1) \(\frac{1}{x+2}+\frac{3}{x^2-4}+\frac{x-14}{\left(x^2+4x+4\right).\left(x-2\right)}\)
2) \(\frac{x+1}{x-3}-\frac{1-x}{x+3}-\frac{2x.\left(1-x\right)}{9-x^2}\)
thuc hien phep tinh :
\(\frac{1}{x-1}-\frac{x^3-x}{x^2+1}\left(\frac{1}{x^2-2x+1}+\frac{1}{1-x^2}\right)\)
thuc hien phep tinh:
a) \(\dfrac{4}{x+2}+\dfrac{2}{x-2}+\dfrac{5x-6}{4-x}\)
Sửa đề: \(\dfrac{4}{x+2}+\dfrac{2}{x-2}+\dfrac{5x-6}{4-x^2}\)
\(=\dfrac{4x-8+2x+4-5x+6}{\left(x-2\right)\left(x+2\right)}=\dfrac{x+2}{\left(x-2\right)\left(x+2\right)}=\dfrac{1}{x-2}\)
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thuc hien phep tinh:
a) \(\dfrac{4}{x+2}+\dfrac{2}{x-2}+\dfrac{5x-6}{4-x^2}\)
\(=\dfrac{4x-8+2x+4-5x+6}{\left(x-2\right)\left(x+2\right)}=\dfrac{x+2}{\left(x-2\right)\left(x+2\right)}=\dfrac{1}{x-2}\)
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Thuc hien cac phep tinh mot cach hop li nhat:
1 + \(\frac{1}{2}\)x (1 + 2) +\(\frac{1}{3}\)x (1 + 2 + 3) + \(\frac{1}{4}\)x (1 + 2 + 3 + 4) +......+\(\frac{1}{20}\) x (1 + 2 +...+ 20)
Giải chi tiết hộ mình nha!!!!!!!!
thuc hien phep tinh \(\frac{4x-8}{x+5}\)* \(\frac{25-x^2}{2x-x^2}\)
\(\frac{4x-8}{x+5}\)* \(\frac{25-x^x}{2x-x^2}\)
\(=\)\(\frac{4\left(x-2\right)\left(5-x\right)\left(5+x\right)}{\left(x+5\right)x\left(2-x\right)}\)
\(=\)\(\frac{-4\left(5-x\right)}{x}\)\(=\)\(\frac{x-20}{x}\)
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