a. \(\frac{1}{5}+\frac{3}{4}+\frac{1}{10}\)

= \(\frac{4}{20}+\frac{15}{20}+\frac{2}{20}\)

= \(\frac{21}{20}\)

b. \(\frac{5}{6}-\frac{1}{3}+\frac{1}{6}\)

= \(\frac{5}{6}-\frac{2}{6}+\frac{1}{6}\)

= \(\frac{4}{6}=\frac{2}{3}\)

c. \(\frac{3}{8}-\frac{10}{2}:\frac{4}{5}\)

= \(\frac{3}{8}-\frac{50}{8}\)

= \(\frac{-47}{8}\)

a) \(\frac{1}{5}+\frac{3}{4}+\frac{1}{10}\)

 = \(\frac{4+15+2}{20}\)

 = \(\frac{21}{20}\)

b) \(\frac{5}{6}-\frac{1}{3}+\frac{1}{6}\)

 = \(\frac{5-2+1}{6}\)

 = \(\frac{4}{6}\)

c) \(\frac{3}{8}-\frac{10}{2}:\frac{4}{5}\)

 = \(\frac{3}{8}-\frac{25}{4}\)

 = \(-\frac{47}{8}\)

b,1/5+3/4+1/10

=4/20+15/20+2/20

=21/20

a,5/6-1/3+5/6

5/6-2/6+5/6

=8/6

=4/3

c,3/8-10/2:4/5

=3/8-25/3

-191/24

nhớ k nha

\(=\frac{16}{3}x\frac{30}{7}=\frac{480}{21}=\frac{160}{7}\)

\(\frac{33}{5}:\frac{21}{4}=\frac{33}{5}x\frac{4}{21}=\frac{132}{105}=\frac{44}{35}\)

a) \(5\frac{1}{3}.4\frac{2}{7}=\frac{16}{3}.\frac{30}{7}=\frac{160}{7}\)

b) \(6\frac{3}{5}:5\frac{1}{4}=\frac{33}{5}:\frac{21}{4}=\frac{33}{5}.\frac{4}{21}=\frac{44}{35}\)

5\(\frac{1}{3}\)x 4\(\frac{2}{7}\)=22\(\frac{6}{7}\)

6\(\frac{3}{5}\): 5\(\frac{1}{4}\)= 1\(\frac{9}{35}\)

lộn dấu / là phần nha các bạn

VD 5 phần 8 í

#)Giải :

\(\left(\frac{1}{2}\right)^{15}\div\left(\frac{1}{4}\right)^{20}=\left(\frac{1}{2}\right)^{15}\div\left(\frac{1}{2}\right)^{40}=\left(\frac{1}{2}\right)^{-25}\)

Cảm ơn bạn nha

    \(\frac{1}{2}+\frac{1}{2}.\frac{1}{3}+\frac{1}{3}.\frac{1}{4}+\frac{1}{4}.\frac{1}{5}+...+\frac{1}{9}.\frac{1}{10}\)

\(=\frac{1}{2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\)

\(=\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\)

\(=\frac{1}{2}+\frac{1}{2}-\frac{1}{10}\)

\(=\frac{9}{10}\)

Giải giùm tớ (-209)-401+12