1) 70 - 5( x - 3 ) = 45

5( x - 3 ) = 70 - 45

5( x - 3 ) = 25

x - 3 = 25 : 5

x - 3 = 5

x = 5 + 3

x = 8

2) 12 + ( 5 + x ) = 20

5 + x = 20 - 12

5 + x = 8

x = 8 - 5

x = 3

3) 130 - ( 100 + x ) = 25

100 + x = 130 - 25

100 + x = 105

x = 105 - 100

x = 5

4) 175 + ( 30 - x ) = 200

30 - x = 200 - 175

30 - x = 25

x = 30 - 25

x = 5

5) 5( x + 12 ) + 22 = 92

5( x + 12 ) = 92 - 22

5( x + 12 ) = 70

x + 12 = 70 : 5

x + 12 = 14

x = 14 - 12

x = 2

6) 95 - 5( x + 2 ) = 45

5( x + 2 ) = 95 - 45

5( x + 2 ) = 50

x + 2 = 50 : 5

x + 2 = 10

x = 10 - 2

x = 8

7) 14x + 54 = 82

14x = 82 - 54

14x = 28

x = 28 : 14

x = 2

8) 15x - 133 = 17

15x = 17 + 133

15x = 150

x = 150 : 15

x = 10

9) 155 - 10( x + 1 ) = 55

10( x + 1 ) = 155 - 55

10( x + 1 ) = 100

x + 1 = 100 : 10

x + 1 = 10

x = 10 - 1

x = 9

Mn giúp e với ak

a) \(\sqrt{x^2-6x+9}\)

\(=\sqrt{\left(x^2-2.x.3+3^2\right)}\)

\(=\sqrt{\left(x-3\right)^2}\) ≥0,∀x

⇒x∈\(R\)

b) \(\sqrt{x^2-2x+1}\)

\(=\sqrt{\left(x^2-2.x.1+1^2\right)}\)

\(=\sqrt{\left(x-1\right)^2}\) ≥0,∀x

⇒x∈\(R\)

a) \(x^3-7x+6=x^3+3x^2-x^2-3x-2x^2-6x+2x+6\)

=\(x^2\left(x+3\right)-x\left(x+3\right)-2x\left(x+3\right)+2\left(x+3\right)\)

=\(\left(x+3\right)\left(x^2-x-2x+2\right)\)

=\(\left(x+3\right)\left(x-2\right)\left(x-1\right)\)

=\(\left\{\begin{matrix}x+3=0=>x=-3\\x-2=0=x=2\\x-1=0=>x=1\end{matrix}\right.\)

\(b...x^3-19x+30=0\)

\(=>x^3+5x^2-2x^2-10x-3x^2-15x+6x+30=0\)

=>\(x^2\left(x+5\right)-2x\left(x+5\right)-3x\left(x+5\right)+6\left(x+5\right)=0\)

=>\(\left(x+5\right)\left(x^2-2x-3x+6\right)=0\)

=>\(\left(x+5\right)\left(x-3\right)\left(x-2\right)=0\)

=>\(\left\{\begin{matrix}x-3=0=>x=3\\x-2=0=>x=2\\x+5=0=>x=-5\end{matrix}\right.\)

Vậy x=-5;2;3

a, (x + 30) – 75 = 125

=> x + 30 = 125 + 75 = 200

=> x = 200 – 30

=> x = 170

Vậy x = 170

b, x – 72 : 36 = 18

=> x – 2 = 18

=> x = 18 + 2 = 20

Vậy x = 20

c, x – 17 = 54

=> x = 54 +17

=> x = 71.

Vậy x = 71

d, 36 – (x – 2) = 12

=> x – 2 = 36 – 12

=> x = 24 + 2 = 26

Vậy x = 26

e, 9x – 7 = 837

=>9x = 837 + 7 = 844

=> x =  844 9

Vậy x =  844 9

f, (x – 15) – 107 = 0

=> x – 15 = 107

=> x = 107 +15

=> x = 122.

Vậy x = 122

g, 134 + (116 – x) = 145

=> 116 – x = 145 – 134

=> x = 116 – 11

=> x = 5.

Vậy x = 5

A, 7[x + 5] - 20 = 190

7x + 35 - 20 = 190

7x + 15 = 190

7x = 175

x = 25

B, 155 - 10[x + 1] = 55

155 - 10x - 10 = 55

-10x + 90 = 55

-10x = -35

x = 3.5

C, 6[x + 2^3] + 40 = 100

6[x + 8] + 40 = 100

6x + 48 + 40 = 100

6x + 88 = 100

6x = 1

2 x = 2

D, 15x - 133 = 17

15x = 150

x = 10

E, 90[x + 2] = 45

90x + 180 = 45

90x = -135

x = -1.5

F, 4x + 54 = 82

4x = 28

x = 7

G, 17x - 20 = 14

17x = 34

x = 2

\(a,3\sqrt{2x}+\sqrt{8x}-\sqrt{18x}=16\left(dk:x\ge0\right)\\ \Leftrightarrow3\sqrt{2x}+2\sqrt{2x}-3\sqrt{2x}=16\\ \Leftrightarrow\sqrt{2x}\left(3+2-3\right)=16\\ \Leftrightarrow2\sqrt{2x}=16\\ \Leftrightarrow\sqrt{2x}=8\\ \Leftrightarrow\left|2x\right|=64\\ \Leftrightarrow2x=64\\ \Leftrightarrow x=32\left(tm\right)\)

Vậy \(S=\left\{32\right\}\)

\(b,\sqrt{4x+20}-3\sqrt{x+5}+\dfrac{4}{3}\sqrt{9x+45}=6\left(dk:x\ge-5\right)\)

\(\Leftrightarrow\sqrt{4\left(x+5\right)}-3\sqrt{x+5}+\dfrac{4}{3}\sqrt{9\left(x+5\right)}=6\\ \Leftrightarrow2\sqrt{x+5}-3\sqrt{x+5}+4\sqrt{x+5}=6\\ \Leftrightarrow\sqrt{x+5}\left(2-3+4\right)=6\\ \Leftrightarrow3\sqrt{x+5}=6\\ \Leftrightarrow\sqrt{x+5}=2\\ \Leftrightarrow\left|x+5\right|=4\\ \Leftrightarrow x+5=4\\ \Leftrightarrow x=-1\left(tm\right)\)

Vậy \(S=\left\{-1\right\}\)

14x + 54 = 82

14x = 28

x = 2

175 + (30 - x) = 2001

30 - x = 1826

x = 30 - 1826

x = - 1796

1551 - 10 ( x + 1 ) = 55

10(x + 1) = 1496

x + 1 = 149,6

x = 148,6

5 . (x + 12) + 22 = 92

5 . (x + 12) = 70

x + 12 = 14

x = 2

6 . (x + 23) + 40 = 100

6 . (x + 23) = 60

x + 23 = 10

x = - 13

\(14x+54=82\)

\(\Leftrightarrow14x=82-54\)

\(\Leftrightarrow14x=28\)

\(\Leftrightarrow x=2\)

Vậy \(x=2\)

\(175+\left(30-x\right)=2001\)

\(\Leftrightarrow30-x=2001-175\)

\(\Leftrightarrow30-x=1826\)

\(\Leftrightarrow x=-1796\)

Vậy \(x=-1796\)

\(1551-10\left(x+1\right)=55\)

\(\Leftrightarrow10.\left(x+1\right)=1551-55\)

\(\Leftrightarrow10.\left(x+1\right)=1496\)

\(\Leftrightarrow x+1=\frac{1496}{10}\)

\(\Leftrightarrow x=\frac{1486}{10}\)

Vậy \(x=\frac{1486}{10}\)

\(5.\left(x+12\right)+22=92\)

\(\Leftrightarrow5.\left(x+12\right)=70\)

\(\Leftrightarrow x+12=14\).

\(\Leftrightarrow x=2\)

Vậy \(x=2\)

\(6.\left(x+23\right)+40=100\)

\(\Leftrightarrow6.\left(x+23\right)=60\)

\(\Leftrightarrow x+23=10\)

\(\Leftrightarrow x=-13\)

Vậy \(x=-13\)