\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)

\(=\frac{2^{10}}{2^{10}}-\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}\)

\(=1-5=-4\)

\(\frac{2^{6+4}}{2^{10}}.\frac{2^5.3^3.5^2.5}{2^3.3^3.5^2.2^5}=1-5=-4\)

Biểu thức = \(\frac{2^{4+6}}{2^{5.2}}\)-\(\frac{2^5.\left(3.5\right)^3}{\left(2.3\right)^3.\left(2.5\right)^2}\) = \(\frac{2^{10}}{2^{10}}\)- \(\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}\)

=1-\(\frac{2^5.3^3.5^3}{2^5.3^3.5^2}\)

=1-5

=-4

1. Tính

\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)

\(=\frac{2^{4+6}}{2^{10}}-\frac{2^5.\left(3.5\right)^3}{\left(2.3\right)^3.\left(2.5\right)^2}\)

\(=\frac{2^{10}}{2^{10}}-\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}\)

\(=1-5\)

\(=-4.\)

Chúc bạn học tốt!

từ 2^4.2^6/(2^5)^2-2^5.15^3/6^3.10^2=2^10/2^10-2^5.3^3.5^3/2^3.3^3.2^2.5^2=1-5=-4

bạn viết ra cho dễ nhìn

=2^4.2^6/2^10-2^5.(3.5)^3/(2.3)^3.(2.5)^2
=2^10/2^10-2^5.3^3.5^3/2^3.3^3.2^2.5^2

=1-5

=-4

A) \(=\frac{\left(-1\right).2^{17}.5^6.3^{12}}{2^{16}.5^53^{13}}=\frac{10}{3}\)

B) Tương tự câu A bạn tự làm nha

Sửa câu A thành \(\frac{-10}{3}\)nha nãy viết vội quá

A) = \(\frac{\left(-1\right)\cdot2^{17}\cdot\left(5^2\right)^3\cdot\left(3^3\right)^4}{\left(2\cdot3\right)^{11}\cdot\left(2\cdot5\right)^5\cdot3^2}\)= \(\frac{\left(-1\right)\cdot2^{17}\cdot5^6\cdot3^{12}}{\left(2^{11}\cdot2^5\right)\cdot\left(3^{11}\cdot3^2\right)\cdot5^5}\)= \(\frac{\left(-1\right)\cdot2^{16}\cdot2\cdot5^5\cdot5\cdot3^{12}}{2^{16}\cdot3^{12}\cdot3\cdot5^5}\)

= \(\frac{\left(-1\right)\cdot2\cdot5}{3}=\frac{-10}{3}\)

B) = \(\frac{\left(3^2\right)^4\cdot\left(7^2\right)^3\cdot2^5}{\left(7\cdot3\right)^5\cdot3^4\cdot\left(2\cdot3\right)^3}\)= \(\frac{3^8\cdot7^6\cdot2^5}{7^5\cdot3^5\cdot3^4\cdot2^3\cdot3^3}\)= \(\frac{3^8\cdot7^5\cdot7\cdot2^3\cdot2^2}{7^5\cdot3^8\cdot3^4\cdot2^3}\)= \(\frac{7\cdot4}{3^4}\)= \(\frac{28}{81}\)

H=\(\frac{1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+5\cdot10\cdot15}{1\cdot3\cdot6+2\cdot6\cdot12+3\cdot9\cdot18+5\cdot15\cdot30}=\frac{1.2.3+2^3.\left(1.2.3\right)+3^3.\left(1.2.3\right)+5^3.\left(1.2.3\right)}{1.3.6+2^3.\left(1.3.6\right)+3^3.\left(1.3.6\right)+5^3.\left(1.3.6\right)}=\frac{1.2.3.\left(1+2^3+3^3+5^3\right)}{1.3.6.\left(1+2^3+3^3+5^3\right)}=\frac{2}{6}=\frac{1}{3}\)

\(\frac{4}{3}\)

Bằng \(-0,4041667168\)

\(\frac{2619}{48520}\)

=\(\frac{30\left(1+8+27+64+125\right)}{5\left(3+24+81+64+375\right)}\)

= \(\frac{30.225}{5.574}\)

=\(\frac{6750}{2870}\)

=\(\frac{675}{287}\)

K mình với!!!!