Question

1. Tính

\(\frac{2^4\cdot2^6}{\left(2^5\right)^2}-\frac{2^5\cdot15^3}{6^3\cdot10^2}\)

Answer 1

\(\frac{2^{6+4}}{2^{10}}.\frac{2^5.3^3.5^2.5}{2^3.3^3.5^2.2^5}=1-5=-4\)

Answer 2

Biểu thức = \(\frac{2^{4+6}}{2^{5.2}}\)-\(\frac{2^5.\left(3.5\right)^3}{\left(2.3\right)^3.\left(2.5\right)^2}\) = \(\frac{2^{10}}{2^{10}}\)- \(\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}\)

=1-\(\frac{2^5.3^3.5^3}{2^5.3^3.5^2}\)

=1-5

=-4

Answer 3

1. Tính

\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)

\(=\frac{2^{4+6}}{2^{10}}-\frac{2^5.\left(3.5\right)^3}{\left(2.3\right)^3.\left(2.5\right)^2}\)

\(=\frac{2^{10}}{2^{10}}-\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}\)

\(=1-5\)

\(=-4.\)

Chúc bạn học tốt!

Answer 4

\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)

\(=\frac{2^{10}}{2^{10}}-\frac{2^5.\left(3.5\right)^3}{\left(2.3\right)^3.\left(2.5\right)^2}\)

\(=1-\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}\)

\(=1-\frac{2^5.5^3}{2^5.5^2}\)

\(=1-1\)

\(=0\)

Chúc bn học tốt !