(75.5^4+175.5^4):(20.25.125-625.75)
[(3^2.5^2.4^3):(2^3.3^2)] .2005^0
(3.4.2^16)^2:(11.2^13.4^11-16^9)
194.12+6.437.2+3.369.4
(1^2+2^2+3^2+...+1000^2) (91-273:3)
(75.5^4+175.5^4):(20.25.125-625.75)
[(3^2.5^2.4^3):(2^3.3^2)] .2005^0
(3.4.2^16)^2:(11.2^13.4^11-16^9)
194.12+6.437.2+3.369.4
(1^2+2^2+3^2+...+1000^2) (91-273:3)
a: \(=\dfrac{5^4\left(75+175\right)}{5^6\cdot4-5^4\cdot5^2\cdot3}=\dfrac{5^4\cdot250}{5^6}=10\)
b: \(=\dfrac{3^2\cdot5^2\cdot2^6}{2^3\cdot3^2}=\dfrac{5^2\cdot2^3}{1}=25\cdot8=200\)
c: \(=\dfrac{\left(3\cdot2^{18}\right)^2}{11\cdot2^{13}\cdot2^{22}-2^{36}}\)
\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{35}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\left(11-2\right)}=2\)
d: \(=12\left(194+437+369\right)=12000\)
e: \(=A\cdot\left(91-91\right)=0\)
Tính hợp lí bài 2 :
I, 194.12+6.437.2+3.369.4
J, (12+22+32+....+10002).(91-273:3)
K, (75.54+175.54):(20.25.125-625.75)
Ai giúp mik vs mik cần gấp pleasee mình sẽ tick
Bài 1 : tính hợp lí ( nếu có thể )
J, (12+22+32+...+10002).(91-273:3)
K, (75.54+175.54):(20.25.125-625.75)
Ai giúp mình với pleaseeee
Tính nhanh:
a, \(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
b, ( 75.54 + 175.54 )
(3.4.2^16)^2/11.2^13.4^11-16^9.Tính bằng cách hợp lý
Câu 2:
a,(19x+2.5^2):14=(13-8)^2-4^2
b,x+(x+1)+(x+2)+...+(x+30)=1204
c,11-(-53+x)=97
d,-(x+84)+213=-16
thực hiện phép tính sau
a) (20.2^4+12.2^4-48.2^4):2
b) (75.5^4+175.5^4):(20.25.125-625.75)
c) 100-(75-3^2)
a) \(\left(20.2,4+12.2,4-48.2,4\right):2\)
\(=\left[2^4.\left(20+12-48\right)\right]:2=2^4.\left(-16\right):2=\left(2^4:2\right).\left(-16\right)=8.\left(-16\right)=-128\)
b)\(\left(75.5^4+175.5^4\right):\left(20.25.125-625.75\right)\)
\(=\left[5^4.\left(75+175\right)\right]:\left[5.\left(4.5.25-125.15\right)\right]\)
...............
c)\(100-\left(75-3^2\right)=100-75+9=34\)
chúc cậu học tốt:)
nếu được thì làm quen ạ<3
Thực hiện các phép tính;
a, A=1+2+2^2+2^3+...+2^2018
b,B=1.2.3...9-1.2.3...8-1.2.3...7.8^2
c,C=(3.4.2^16)^2/11.2^13.4^11-16^9
thôi minh giai duoc roi .thanks ban nhieu
(3.4.2^16)^2/11.2^13.4^11-16^9
\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\dfrac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\dfrac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\dfrac{3^2.2^{36}}{11.2^{35}-2.2^{35}}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.9}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.3^2}\)
\(=2\)
a)(10^2+11^2+12^2):(13^2+14^2) b)1.2.3...9-1.2.3...8-1.2.3...7.8^2 c)(3.4.2)^16/11.2^13.4^11-16^9 d)1152-(374+1152)+(-56+374) e)13-12+11+10-9+8-7-6+5-4+3+2-1 |