Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:

\(\dfrac{a}{2}=\dfrac{b}{5}=\dfrac{c}{6}=\dfrac{a+b-c}{2+5-6}=60\)

Do đó: a=120; b=300; c=360

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Bạn đăng tối đa 10 câu th =) 

\(\sqrt{a^2+3}=\sqrt{a^2+ab+bc+ca}=\sqrt{\left(a+b\right)\left(a+c\right)}\le\dfrac{1}{2}\left(a+b+a+c\right)=\dfrac{1}{2}\left(2a+b+c\right)\)

Tương tự: \(\sqrt{b^2+3}\le\dfrac{1}{2}\left(a+2b+c\right)\) ; \(\sqrt{c^2+3}\le\dfrac{1}{2}\left(a+b+2c\right)\)

Cộng vế với vế:

\(VT\le\dfrac{1}{2}\left(4a+4b+4c\right)=2\left(a+b+c\right)\)

a: \(A=\left(x+2+2x-5\right)^2=\left(3x-3\right)^2\)

\(=\left(\dfrac{3}{4}-3\right)^2=\left(-\dfrac{9}{4}\right)^2=\dfrac{81}{16}\)

tham khảo

like playing soccer, don't you
goes to school late, doesn't he
can swim very well, can't you
is going to the party, isn't she
was published in Germany in 1550, wasn't it
are sold all over the world, aren't they
have been built this year, haven't they
was given a book, wasn't he 
were bought by Mrs Brown yesterday, weren't they
is used everyday, isn't it

bn j oi, co mình hỏi đơn vị thể tích chất khí là jz, để mình còn làm bài

1: Xét ΔABC vuông tại A có 

\(\widehat{B}+\widehat{C}=90^0\)

hay \(\widehat{C}=30^0\)

Xét ΔABC vuông tại A có 

\(BC=\dfrac{AC}{\sin60^0}\)

\(=\dfrac{32\sqrt{3}}{3}\left(cm\right)\)

hay \(AB=\dfrac{16\sqrt{3}}{3}\left(cm\right)\)