tính : \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
Tính giá trị biểu thức :
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(=\frac{2^{10}.\left(13+65\right)}{2^8.104}\)
\(=\frac{2^{10}.78}{2^8.104}\)
\(=\frac{2^8.2^2.78}{2^8.104}\)
\(=\frac{2^8.4.78}{2^8.104}\)
\(=\frac{2^8.312}{2^8.104}\)
\(=\frac{2^8.3.104}{2^8.104}=3\)
tính giá trị biêu thức:
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(=\frac{2^{10}.\left(13+65\right)}{2^8.104}\)
\(=\frac{2^{10}.78}{2^8.104}\)
\(=\frac{2^{10}.2.39}{2^8.2^3.13}\)
\(=\frac{2^{11}.39}{2^{11}.13}=3\)
Tính giạ trị biểu thức: \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(\frac{2^{10}\cdot13+2^{10}\cdot65}{2^8\cdot104}=\frac{2^{10}\cdot\left(13+65\right)}{2^8\cdot104}=\frac{2^{10}\cdot78}{2^8\cdot104}=\frac{2^{10}\cdot2\cdot3\cdot13}{2^8\cdot2^2\cdot13}=\frac{2^{11}\cdot3\cdot13}{2^{10}\cdot13}=2\cdot3=6\)
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)= ?
\(\frac{2^{10^2}13+2^{10}.65}{2^8.104}\)=?
\(\frac{2^{10}.13+2^{10}.65}{2^{8^{ }}.104}=\frac{2^{10}\left(13+65\right)}{2^8.104}=\frac{2^8.2^2.78}{2^8.104}=3\)
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}\left(13+65\right)}{2^8.104}=\frac{2^8.2^2.78}{2^8.104}=3\)
Tính giá trị của các biểu thức:
a. \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
b. ( 1 + 2 + 3 + ... + 100 ) . ( 12 + 22 + 32 + ... + 102 ) . ( 65 . 111 - 13 . 15 . 37 )
35) Tính giá trị của các biểu thức
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(B=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
Bài 35 :
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(A=\frac{2^{10}.\left(13+65\right)}{2^8.104}\)
\(A=\frac{2^8.2^2.98}{2^8.104}\)
\(A=\frac{2^8.4.98}{2^8.4.26}\)
\(A=\frac{49}{13}\)
Vậy \(A=\frac{49}{13}\)
\(B=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(B=\frac{11.3^{29}-9^{15}}{2^2.\left(3^{14}\right)^2}\)
\(B=\frac{11.3^{29}-9^{15}}{2^2.3^{28}}\)
\(B=\frac{11.3^{29}-\left(3^2\right)^{15}}{4.3^{28}}\)
\(B=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(B=\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)
\(B=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}\)
\(B=\frac{3^{29}.8}{4.3^{28}}\)
\(B=\frac{3^{28}.3.4.2}{4.3^{28}}\)
\(B=3.2\)
\(B=6\)
Vậy B = 6
A = 2^10 . 13 + 2^10 . 65 / 2^8 . 104
= 2^10 ( 13 + 65 ) / 2^8 . 104 = 2^10 . 78 / 2^8 . 104 = 2^8 . 2^2 . 78 / 2^8 . 104 = 2^8 . 4 . 78 / 2^8 . 104 = 2^8 . 312 / 2^8 . 104
= 312/104
= 3
B = 11 . 3^22 . 3^7 - 9^15 / ( 2.3^14)^2
= 11 . 3^29 - (3^2)^15 / ( 3.2^14)^2
= 11 . 3^29 - 3^30 / ( 3. 2 )^28
= ( 8 + 3 ) . 3^29 - 3^30 / ( 3. 2)^28
= 8 . 3^29 + 3.3^29 - 3^30 / ( 3.2)^28
= 8 . 3^29 + 3^30 - 3^30 / ( 3 . 2)^28
= 8 . 3^29 / 3^28 . 2^28
= 2^3 . 3 / 2^28
= 3/ 2^25
So Sánh: B = \(\frac{^{3^{10}.11+3^{10}.5}}{3^9.2^4}\) và C= \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
Ta có:
B=\(\frac{3^{10}.\left(11+5\right)}{3^9.2^4}\) = \(\frac{3^{10}.16}{3^9.2^4}\)= \(\frac{3^9.3.16}{3^9.16}\)= 3
C=\(\frac{2^{10}.\left(13+65\right)}{2^8.104}\) =\(\frac{2^{10}.78}{2^8.104}\) = \(\frac{2^8.2^2.78}{2^8.104}\)= \(\frac{4.78}{104}\) = \(\frac{4.78}{4.26}\)=\(\frac{78}{26}\)=3
=>B=C
tính :
\(\frac{2^{10}.13.2^{10}.65}{2^8.104}\)
\(\frac{2^{10}.13.2^{10}.65}{2^8.104}=\frac{1024.13.1024.65}{256.104}\)
\(=\frac{1024.13.65}{256.104}=\frac{865280}{26642}\)
\(=32,5\)
\(\frac{2^{10}.13.2^{10}.65}{2^8.104}=\frac{2^{20}.13.65}{2^8.2^3.13}\)
\(=\frac{2^{20}.13.65}{2^{11}.13}\)
\(=2^9.65\)
\(=512.65\)
\(=33280\)
\(\frac{2^{10}.13.2^{10}.65}{2^8.104}=\frac{2^{20}.13^2.5}{2^{11}.13}=2^9.13.5=33280\)
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