\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
Xét : 210 . 13 + 210. 65 = 210 . ( 13 + 65 ) = 210 . 78
28 . 104 = 28 . ( 22 . 26 ) = 28. 22. 26 = 210.26
có : \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)= \(\frac{2^{10}.78}{2^{10}.26}\)= \(\frac{78}{26}\)= 3
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}\)
\(=\frac{2^2.39}{52}=\frac{2^2.39}{2^2.13}\)
\(=\frac{39}{13}\)
\(=3\)