1. tong binh phuong tac ca cac nghiem cua phuong trinh :x4(x-1)+(x-1)x3=0
2.gia tri lon nhat cua bieu thuc7x-2x2
3.nghiem nho nhat cua da thuc 11x-2x2-15
1. nghiem nho nhat cua da thuc 11x-2x2-15
2.gia tri x nho nhat thoa man : 4x2+7x+3=0
3.gia tri lon nhat cua bieu thuc7x-2x2
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1 . tong binh phuong tat ca cac nghiem cua phuong trinh : x4(x-1)+(x-1)x3=0
2.neu da thuc 2m3-m+n co 2 nhan tu la : x+2 va x-1 thi gia tri cua 2m+3n la
3.tong x; y thoa man (x-2015)2+(y-2014)4>hoac bang 0 la ?
1) Tim tac ca cac gia tri thuc cua tham so m de phuong trinh:
(m-2)x2 - 2mx+m+3 = 0 co 2 nghiem duong phan biet
TH1: \(m=2\)
\(pt\Leftrightarrow-4x+5=0\Leftrightarrow x=\dfrac{5}{4}\)
\(\Rightarrow m=2\) không thỏa mãn yêu cầu bài toán
TH2: \(m\ne2\)
Yêu cầu bài toán thỏa mãn khi:
\(\left\{{}\begin{matrix}\Delta'=m^2-\left(m-2\right)\left(m+3\right)>0\\\dfrac{2m}{m-2}>0\\\dfrac{m+3}{m-2}>0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}6-m>0\\\dfrac{2m}{m-2}>0\\\dfrac{m+3}{m-2}>0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}m< -3\\2< m< 6\end{matrix}\right.\)
Vậy \(m\in\left(-\infty;-3\right)\cup\left(2;6\right)\)
1. gia tri cua x thoa man (2x+3)(x+1)2-(2x+3)(2x-3)
2. so nghiem cua da thuc x3+6x2+11x+6 la ?
3. bieu thuc C = 8-5x-2x2 dat gia tri lon nhat tai x = ?
giup to 2 bai nay
1 .So nghiem cua da thuc x3+6x2+11x+6 la....
2gia tri lon nhat cua bieu thuc B= 1+3x-x2 la
1.nghiem nho nhat cua da thuc : 11x-2x2-15
2.gia tri x nho nhat thoa man 4x2+7x+3=0
3.gia tri cua x3+y3biet x+y=2 va x2+y2=20
giup to 3 bai nay
1. gia tri cua x thoa man (2x+3)(x+1)2-(2x+3)(2x-3)
2. so nghiem cua da thuc x3+6x2+11x+6 la ?
3. bieu thuc C = 8-5x-2x2 dat gia tri lon nhat tai x = ?
giup to 3 bai nay
1. gia tri cua x thoa man (2x+3)(x+1)2-(2x+3)(2x-3)
2. so nghiem cua da thuc x3+6x2+11x+6 la ?
3. bieu thuc C = 8-5x-2x2 dat gia tri lon nhat tai x = ?
hay viet cac da thuc tren thanh tong binh phuong cua da thuc bac nhat,tu do tim ra gia tri x,y de cac da thuc tren bang 0
A=x2+y2+2x-4y+5
nho neu ca cach giai nhe moi nguoi
A=x2+y2+2x-4y+5
=x2+2x+1+y2-4y+4
=(x+1)2+(y-2)2
A=0
=>(x+1)2+(y-2)2=0
<=>x+1=0 và y-2=0
<=>x=-1 và y=2