2x+2xy=39

=> 2x(y+1)=39

:v đề thế m giải đi

Thu gọn đơn thức $P = x^3y - 5xy^3 + 2x^3y + 5xy^3$

___________________

Giải:

$P = x^3y - 5xy^3 + 2x^3y + 5xy^3$

$P = x^3y + 2x^3y - 5xy^3 + 5xy^3$

$P = 3x^3y$

A+B

=3x^2y^3-5x^3y^2-5xy+1+5x^3y^2-2x^2y^3-5xy+2

=x^2y^3-10xy+3

A+B = \(\left(3x^2y^3-5x^3y^2-5xy+1\right)+\left(5x^3y^2-2x^2y^3-5xy+2\right)\)

        = \(\left(3x^2y^3-2x^2y^3\right)+\left(-5x^3y^2+5x^3y^2\right)+\left(-5xy-5xy\right)+\left(1+2\right)\)

        = \(x^2y^3-10xy+3\)

Không bíc có đúng không nữa

a: \(=\left(4xy^2+2xy^2\right)+\left(3x^2y-3x^2y\right)=6xy^2\)

b: \(=xy\left(\dfrac{1}{5}+\dfrac{1}{3}\right)+xy^2\left(\dfrac{4}{3}-\dfrac{2}{5}\right)=\dfrac{8}{15}xy+\dfrac{14}{15}xy^2\)

d: \(=\dfrac{-4}{9}\cdot\dfrac{3}{2}\cdot xy^2\cdot xy^3=-\dfrac{2}{3}x^2y^5\)

A-B

=3x^2y^3-5x^3y^2-5xy+1-5x^3y^2+2x^2y^3+5xy-2

=5x^2y^3-10x^3y^2-1

A = (2x^2+2xy)-(3xy+3y^2) / (2x-2xy)-(3xy-3y^2)

   = (x+y).(2x-3y)/(x-y).(2x-3y) = x+y/x-y

k mk nha

đkxđ \(x\ne y\)

 \(A=\frac{x\left(2x-3y\right)+y\left(2x-3y\right)}{x\left(2x-3y\right)-y\left(2x-3y\right)}=\frac{\left(x+y\right)\left(2x-3y\right)}{\left(x-y\right)\left(2x-3y\right)}=\frac{x+y}{x-y}\)